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Curriculum  /  Math  /  6th Grade  /  Unit 6: Equations and Inequalities  /  Lesson 6

Equations and Inequalities

Lesson 6 of 14

Criteria for Success

Tips for teachers, anchor problems, problem set, target task, additional practice.

Lesson Notes

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Solve percent problems using equations.

Common Core Standards

Core standards.

The core standards covered in this lesson

Expressions and Equations

6.EE.B.7 — Solve real-world and mathematical problems by writing and solving equations of the form x + p = q and px = q for cases in which p, q and x are all nonnegative rational numbers.

Ratios and Proportional Relationships

6.RP.A.3.C — Find a percent of a quantity as a rate per 100 (e.g., 30% of a quantity means 30/100 times the quantity); solve problems involving finding the whole, given a part and the percent.

Foundational Standards

The foundational standards covered in this lesson

6.RP.A.1 — Understand the concept of a ratio and use ratio language to describe a ratio relationship between two quantities. For example, "The ratio of wings to beaks in the bird house at the zoo was 2:1, because for every 2 wings there was 1 beak." "For every vote candidate A received, candidate C received nearly three votes."

6.RP.A.2 — Understand the concept of a unit rate a/b associated with a ratio a:b with b ≠ 0, and use rate language in the context of a ratio relationship. Expectations for unit rates in this grade are limited to non-complex fractions. For example, "This recipe has a ratio of 3 cups of flour to 4 cups of sugar, so there is 3/4 cup of flour for each cup of sugar." "We paid $75 for 15 hamburgers, which is a rate of $5 per hamburger."

The essential concepts students need to demonstrate or understand to achieve the lesson objective

  • Determine, through repeated reasoning, an equation to represent the relationship between percent, whole, and part:   $$percent\times{whole}=part$$   (MP.8).
  • Write an equation to represent a percent situation when given a part and a percent.
  • Write and solve equations to find the whole, given the part and percent.

Suggestions for teachers to help them teach this lesson

In Unit 2, students solved percent problems by reasoning about diagrams, double number lines, and tables. Now having learned about equations in the form  $${px=q}$$ , students revisit percent problems to see how they can be modeled and solved efficiently using an equation (MP.4).

Unlock features to optimize your prep time, plan engaging lessons, and monitor student progress.

Problems designed to teach key points of the lesson and guiding questions to help draw out student understanding

25-30 minutes

  • 30% of 120?

In general, if you’re given a percent and a whole, how can you find the part? Write this as an equation.

Guiding Questions

Student response.

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30% of what number is 12?

Solve this problem first by drawing a diagram. Then write and solve an equation to verify your solution. 

For each situation below, write and solve an equation to answer the question.

a.   There are 6 liters of water in a bucket, which is 20% of the maximum number of liters the bucket can hold. What is the maximum number of liters the bucket can hold?

b.   A softball team won 18 games, which was 60% of the games they played this season. How many games did the softball team play this season?

A set of suggested resources or problem types that teachers can turn into a problem set

15-20 minutes

Give your students more opportunities to practice the skills in this lesson with a downloadable problem set aligned to the daily objective.

A task that represents the peak thinking of the lesson - mastery will indicate whether or not objective was achieved

5-10 minutes

Paula is saving money to buy a tablet. So far, she has saved $54, which is 45% of what she needs to buy the tablet. 

Write and solve an equation to find the price of the tablet. 

The following resources include problems and activities aligned to the objective of the lesson that can be used for additional practice or to create your own problem set.

  • Challenge: In a choir, there are 28 female singers which is 40% of the choir. How many female singers would have to be added to the group so exactly 50% of the choir were females?
  • EngageNY Mathematics Grade 6 Mathematics > Module 1 — Lessons 27–29 (Revisit these lessons from Unit 2 and have students write equations to solve.)
  • Open Up Resources Grade 6 Unit 6 Practice Problems — Lesson 7 #1–3

Topic A: Reasoning About and Solving Equations

Represent equations in the form  $${ x+p=q }$$ and  $${px=q}$$ using tape diagrams and balances.

6.EE.B.6 6.EE.B.7

Define and identify solutions to equations.

Write equations for real-world situations.

Solve one-step equations with addition and subtraction.

Solve one-step equations with multiplication and division.

6.EE.B.7 6.RP.A.3.C

Solve multi-part equations leading to the form  $${x+p=q }$$  and $${px=q}$$ .

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Topic B: Reasoning About and Solving Inequalities

Define and identify solutions to inequalities.

6.EE.B.5 6.EE.B.8

Write and graph inequalities for real-world conditions. (Part 1)

Write and graph inequalities for real-world conditions. (Part 2)

Solve one-step inequalities.

6.EE.B.6 6.EE.B.8

Topic C: Representing and Analyzing Quantitative Relationships

Write equations for and graph ratio situations. Define independent and dependent variables.

6.EE.C.9 6.RP.A.3.A

Represent the relationship between two quantities in graphs, equations, and tables. (Part 1)

Represent the relationship between two quantities in graphs, equations, and tables. (Part 2)

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Problem Solving - Make a Table

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Go Math! 6 Common Core Edition, Grade: 6 Publisher: Houghton Mifflin Harcourt

Go math 6 common core edition, title : go math 6 common core edition, publisher : houghton mifflin harcourt, isbn : 547587783, isbn-13 : 9780547587783, use the table below to find videos, mobile apps, worksheets and lessons that supplement go math 6 common core edition..

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Chapter 6, Lesson 7: Problem-Solving Strategy: Make a Table

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CCSS Math Answers

Eureka Math Grade 6 Module 1 Lesson 27 Answer Key

Engage ny eureka math 6th grade module 1 lesson 27 answer key, eureka math grade 6 module 1 lesson 27 example answer key.

Example 1. Solve the following three problems. Write the words PERCENT, WHOLE, or PART under each problem to show which piece you were solving for. 60% of 300 = ____________            60% of ____________ = 300           60 out of 300 = ____________ %

Eureka Math Grade 6 Module 1 Lesson 27 Example Answer Key 1

How did your solving method differ with each problem? Answer: Solutions will vary. A possible answer may include: When solving for the part, I need to find the missing number in the numerator. When solving for the whole, I solve for the denominator. When I solve for the percent, I need to find the numerator when the denominator is 100.

Eureka Math Grade 6 Module 1 Lesson 27 Exercise Answer Key

Eureka Math Grade 6 Module 1 Lesson 27 Exercise Answer Key 2

What is the total cost of Priya’s outfit? Answer: Shirt 25% = \(\frac{25}{100}=\frac{1}{4}=\frac{11}{44}\) The discount is $11. The cost of the shirt is $33 because $44 – $11 = $33.

Pants 30% = \(\frac{30}{100}=\frac{15}{50}\) The original price is $50. The price of the pants is $35 because $50 – $15 = $35.

Shoes 15% = \(\frac{15}{100}=\frac{3}{20}=\frac{9}{60}\) The original price is $60. The cost of the shoes is $51 because $60 – $9 = $51.

Necklace 10% = \(\frac{1}{10}=\frac{2}{20}\) The discount is $2. The cost of the necklace is $18 because $20 – $2 = $18.

Sweater 20% = \(\frac{20}{100}=\frac{1}{5}=\frac{7}{35}\) The original price is $35. The cost of the sweater is $28 because $35 – $7 = $28. The total outfit would cost the following: $33 + $35 + $51 + $18 + $28 = $165.

Eureka Math Grade 6 Module 1 Lesson 27 Problem Set Answer Key

Question 1. Mr. Yoshi has 75 papers. He graded 60 papers, and he had a student teacher grade the rest. What percent of the papers did each person grade? Answer: Mr. Yoshi graded 80% of the papers, and the student teacher graded 20%.

Question 2. Mrs. Bennett has graded 20% of her 150 student’s papers. How many papers does she still need to finish grading? Answer: Mrs. Bennett has graded 30 papers. 150 – 30 = 120. Mrs. Bennett has 120 papers left to grade.

Eureka Math Grade 6 Module 1 Lesson 27 Exit Ticket Answer Key

Jane paid $40 for an item after she received a 20% discount. Jane’s friend says this means that the original price of the item was $48.

a. How do you think Jane’s friend arrived at this amount? Answer: Jane’s friend found that 20% of 40 is 8. Then she added $8 to the sale price: 40 + 8 = 48. Then she determined that the original amount was $48.

Eureka Math Grade 6 Module 1 Lesson 27 Exit Ticket Answer Key 4

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Go Math Answer Key

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs

Refer to our Texas Go Math Grade 6 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs.

Question 1. Look for a Pattern When the amount of solvent increases by 1 milliliter, the amount of distilled water increases by ____________ milliliters. So 6 milliliters of solvent requires ____________ milliliters of distilled water. Answer: 1 ∙ 50 = 50 6 ∙ 50 = 300 50 milliliters, 300 milliliters.

Go Math Grade 6 Lesson 8.2 Ratio Tables Answer Key Question 2. Communicate Mathematical Ideas How can you use the graph to find the amount of distilled water to use for 4.5 milliliters of solvent? Answer: Locate the point x = 4.5 on the graph and then study its corresponding value of y. This value of y is the amount of distilled water required for 4.5 ml of ammonia and will be equal to 4.5 × 50 = 225 ml.

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 1

time gallon
2 8
3 12
3.5 14
5 20
6.5 26

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 15

The shower uses 4 gallons per minute.

Texas Go Math Grade 6 Lesson 8.2 Guided Practice Answer Key

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 3

Sulfur Oxygen
6 18
9 27
21 63
27 81

Equivalent ratios are: \(\frac{6}{18}=\frac{9}{27}=\frac{21}{63}=\frac{27}{81}\)

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 4

List the ordered pairs from the table: (6, 18), (9, 27), (21, 63), (27, 81) and graph them on a coordinate plane.

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 5

Width (in) Length (in)
2 4
4 8
7 14
8 16
For every 2 inches of width the length is 4 inches. This implies that there is \( \frac{4}{2} \) = 2 inches of length per inch of width.

Equivalent ratio of width to length is 1 : 2

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 6

List the ordered pairs from the table: (2, 4), (4, 8), (7, 14), (8, 16) and graph them on a coordinate plane.

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 7

Essential Question Check-In

Question 6. How do you represent real-world problems involving ratios and rates with tables and graphs? Answer: Real-world problems involving ratios and rates are represented with tables as ordered pairs and then these ordered pairs are graphed to study the relation between the 2 given variables or quantities.

We can study the relation between the two given variables or quantities.

The table shows information about the number of sweatshirts sold and the money collected at a fund raiser for school athletic programs. For Exercises 7 – 12, use the table.

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 9

Question 7. Find the rate of money collected per sweatshirt sold. Show your work. Answer: According to the given data, the sale of 3 sweatshirts collected $60, so this means that 1 sweatshirt collected \(\frac{\$ 60}{3}\) = $20 $20 is collected per sweatshirt sold.

Question 8. Use the unit rate to complete the table. Answer: $20 is collected per sweatshirt sold, so the sale of 5 sweatshirts will generate 5 × $20 = $100. $20 is collected per sweatshirt sold, so the sale of 8 sweatshirts will generate 8 × $20 = $160. $20 is collected per sweatshirt sold, so the sale of 12 sweatshirts will generate 12 × $20 = $240. $20 is collected per sweatshirt sold, so $180 was collected by selling \(\frac{\$ 180}{\$ 20}\) = 9 sweatshirts.

Go Math 6th Grade Ratios and Rates Answer Key Question 9. Explain how to graph Information from the table. Answer: List the ordered pairs from the table: (3, 60), (5, 100), (8, 160), (9, 180), (12. 240) and graph them on a coordinate plane.

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 21

The sale of 24 sweatshirts will collect $480.

Question 12. Analyze Relationships Does the point (5.5, 110) make sense in this context? Explain. Answer: The point (5.5, 110) does not make sense in this context because the independent variable x, the number of shirts sold is discrete and not continuous. This means that selling 5.5 sweatshirts does not make sense, the number of sweatshirts sold MUST be a whole number.

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 11

She would have covered a distance of 330 miles.

Use the graph for Exercises 14 – 15.

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 12

Question 14. Analyze Relationships Does the relationship show a ratio or a rate? Explain. Answer: The ratio because it represents the relationship between the two numbers.

Go Math Grade 6 Lesson 8.2 Ratios and Rates Question 15. Represent Real-World Problems What is a real-life relationship that might be described by the graph? Answer: We can find out how many days are in, for example, one, two, or three weeks. Ordered pair on the graph (4, 28) tells us there are 28 days in 4 weeks.

H.O.T. Focus On Higher Order Thinking

Texas Go Math Grade 6 Lesson 8.2 Answer Key Ratios, Rates, Tables, and Graphs 13

Time Distance
1 5
2 10
5 25
20 100

\(\frac{\text { distance }}{\text { time }}\) = \(\frac{5}{1}\) \(\frac{\text { time }}{\text { distance }}\) = \(\frac{1}{5}\)

a. Are the \(\frac{\text { time }}{\text { distance }}\) rates equivalent? Explain. Answer: They are equivalent because \(\frac{1}{5} \cdot \frac{2}{2}=\frac{2}{10}\) \(\frac{1}{5} \cdot \frac{5}{5}=\frac{5}{25}\) \(\frac{1}{5} \cdot \frac{20}{20}=\frac{20}{100}\)

b. Suppose you graph the points (time, distance) and your friend graphs (distance, time). How will your graphs be different? Answer: The graph of (time, distance) will grow slower than the graph of (distance, time)

Lesson 8.2 Answer Key 6th Grade Go Math Question 17. Communicate Mathematical Ideas To graph a rate or ratio from a table, how do you determine the scales to use on each axis? Answer: The maximum values of the 2 given quantities are considered and based on that, the scales of the axes of the graphs are decided.

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    2. $7.20, because each baseball card costs 60 cents, and 0.6 times 12 is 7.2. 3. Answers vary. Sample response: A table would be more convenient, because the rows of the table can be listed in any order, and not all values between the ones needed have to be filled in. Problem 7 (from Unit 2, Lesson 9) Jada traveled 135 miles in 3 hours.

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  8. Lesson 6

    6.EE.B.7 — Solve real-world and mathematical problems by writing and solving equations of the form x + p = q and px = q for cases in which p, q and x are all nonnegative rational numbers. 6.RP.A.3.C — Find a percent of a quantity as a rate per 100 (e.g., 30% of a quantity means 30/100 times the quantity); solve problems involving finding ...

  9. Problem Solving

    30 minutes. Report this resource to TPT. Reported resources will be reviewed by our team. Report this resource to let us know if this resource violates TPT's content guidelines. This page teaches students how to use the Make a Table strategy when solving a problem. I created it in my class for studetns to use during a guided practice lesson.

  10. PDF Skills Practice Workbook

    A manatee eats an average of 70 pounds of wet vegetation each day. 9. Make a table to show the relationship between the number of p pounds of wet vegetation a manatee eats in d days. 10. Write an equation to find p, the number of pounds of wet vegetation a manatee eats in d days.

  11. Chapter 11, Lesson 1: Problem-Solving Investigation: Make a Table

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