lesson 10 homework grade 5 module 2

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Grade 10 dll quarter 1 week 5 (august 26-30, 2024), free download.

The Daily Lesson Log (DLL) is a crucial tool for teachers in planning and delivering quality education to their students. This standard template covers a week's worth of lessons, making it an efficient and effective way for teachers to plan their lessons. The Department of Education (DepEd) recognizes the importance of well-planned lessons in delivering quality teaching and learning in schools.

The Department of Education has released the DO 42, S. 2016 – POLICY GUIDELINES ON DAILY LESSON PREPARATION FOR THE K TO 12 BASIC EDUCATION PROGRAM. This policy aims to provide teachers a guide on how to prepare effective daily lessons that will help students learn better. The DLL format includes the following parts: Objectives, Content, Learning Resources, Procedures, Remarks and Reflection. (Download the memo to read more ( DO_s2016_042 )

• Helps teachers stay organized: With the DLL, teachers can plan their lessons for the week and ensure that they are covering all the necessary topics. This makes it easier for them to stay organized and keep track of what they have taught and what they still need to cover.
• Promotes consistency: By following the DLL, teachers can ensure that they are delivering the same quality of education to all their students. This helps to promote consistency in the classroom, which is essential for effective learning.
• Encourages collaboration: The DLL is a standard template that is used by all teachers, which means that they can easily share their lessons with one another. This encourages collaboration among teachers and helps them to learn from each other's experiences.
• Provides a framework for assessment: The DLL includes objectives, learning activities, and assessment methods, which provides a framework for assessing student learning. This makes it easier for teachers to determine whether their students have mastered the material or if they need additional support.

The Department of Education (DepEd) recognizes the importance of the DLL in delivering quality teaching and learning in schools. By providing teachers with a standardized template and promoting its use, DepEd is helping to ensure that students receive the education they need to succeed.

• DAILY LESSON LOG IN ARALING PANLIPUNAN  10 – QUARTER 1: WEEK 5
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With the help of a Daily Lesson Log, you can better manage your time and resources, stay on track with your teaching objectives, and ensure that your students are receiving a quality education. So, take advantage of this helpful tool and download your Daily Lesson Log for Week 1-10 of the first     quarter today! Note that some of the documents are still updating. Please do visit the site more often for more exclusive updates on the DLL based on the Most Essential Learning Competencies (MELC)

DepEd Tambayan has compiled all DLLs from the first quarter to the fourth quarter for Grade 1-12 for the school year 2024-2025. This is a great resource for teachers who want to ensure that their lessons are well-planned and executed. The use of a DLL allows teachers to maintain quality education standards and helps them plan their lessons in a flexible manner.

The Daily Lesson Log (DLL) is an essential tool for teachers in planning and delivering quality education to their students. It is a flexible and efficient way to plan lessons and maintain quality education standards. With the compilation of DLLs for Grade 1-12 for the school year 2024-2025 by DepEd Tambayan, teachers now have a valuable resource to help them in their lesson planning.

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Eureka Math Grade 5 Module 3 Lesson 10 Answer Key

Engage ny eureka math 5th grade module 3 lesson 10 answer key, eureka math grade 5 module 3 lesson 10 sprint answer key.

Question 1. 3 + 1 = Answer: 3 + 1 = 4 Explanation : Adding 1 to 3 we get 4 a s sum .

Question 2. 3 + \(\frac{1}{2}\) = Answer: 3 + \(\frac{1}{2}\) = 3\(\frac{1}{2}\) Explanation : 3 + \(\frac{1}{2}\) = \(\frac{6}{2}\) + \(\frac{1}{2}\) = \(\frac{7}{2}\) = 3\(\frac{1}{2}\)

Question 3. 3\(\frac{1}{2}\) + 1 = Answer: 3\(\frac{1}{2}\) + 1 = 4\(\frac{1}{2}\) Explanation : 3\(\frac{1}{2}\) + 1 = \(\frac{7}{2}\) + \(\frac{2}{2}\) = \(\frac{9}{2}\) =4\(\frac{1}{2}\)

Question 4. 3 – 1 = Answer: 3 – 1 = 2 Explanation : subtracting 1 from 3 we get 2 .

Question 5. 3\(\frac{1}{2}\) – 1 = Answer: 3\(\frac{1}{2}\) – 1 = 2\(\frac{1}{2}\) Explanation : 3\(\frac{1}{2}\) – 1 = \(\frac{7}{2}\) – \(\frac{2}{2}\) = \(\frac{5}{2}\) =2\(\frac{1}{2}\)

Question 6. 4 – 2 = Answer: 4 – 2 = 2 Explanation : Subtracting 2 from 4 we get difference as 2.

Question 7. 4\(\frac{1}{2}\) – 2 = Answer: 4\(\frac{1}{2}\) – 2 = 2\(\frac{1}{2}\) Explanation : 4\(\frac{1}{2}\) – 2 = \(\frac{9}{2}\) – \(\frac{4}{2}\) = \(\frac{5}{2}\) =2\(\frac{1}{2}\)

Question 8. 5 – 2 = Answer: 5 – 2 = 3 Explanation : Subtracting 2 from 5 we get difference as 3.

Question 9. 5\(\frac{1}{3}\) – 2 = Answer: 5\(\frac{1}{3}\) – 2 = 3\(\frac{1}{3}\) Explanation : 5\(\frac{1}{3}\) – 2 = \(\frac{16}{3}\) – \(\frac{6}{3}\) = \(\frac{10}{3}\) =3\(\frac{1}{3}\)

Question 10. 5\(\frac{2}{3}\) – 2 = Answer: 5\(\frac{2}{3}\) – 2 = 3\(\frac{2}{3}\) Explanation : 5\(\frac{2}{3}\) – 2 = \(\frac{17}{3}\) – \(\frac{6}{3}\) = \(\frac{11}{3}\) =3\(\frac{2}{3}\)

Question 11. 5\(\frac{2}{3}\) + 2 = Answer: 5\(\frac{2}{3}\) + 2 = 7\(\frac{2}{3}\) Explanation : 5\(\frac{2}{3}\) + 2 = \(\frac{17}{3}\) + \(\frac{6}{3}\) = \(\frac{23}{3}\) = 7\(\frac{2}{3}\)

Question 12. 6 + 2 = Answer: 6 + 2 = 8 Explanation : Adding 2 to 6 we get sum as 8 .

Question 13. 6 + \(\frac{3}{4}\) = Answer: 6 + \(\frac{3}{4}\) = 6\(\frac{3}{4}\) Explanation : 6 + \(\frac{3}{4}\) = \(\frac{24}{4}\) + \(\frac{3}{4}\) = \(\frac{27}{4}\) = 6\(\frac{3}{4}\)

Question 14. 6\(\frac{3}{4}\) + 2 = Answer: 6\(\frac{3}{4}\) + 2 = 8\(\frac{3}{4}\) Explanation : 6\(\frac{3}{4}\) + 2 = \(\frac{27}{4}\) + \(\frac{8}{4}\) = \(\frac{35}{4}\) = 8\(\frac{3}{4}\)

Question 15. 6\(\frac{3}{4}\) – 2 = Answer: 6\(\frac{3}{4}\) – 2 = 4\(\frac{3}{4}\) Explanation : 6\(\frac{3}{4}\) – 2 = \(\frac{27}{4}\) – \(\frac{8}{4}\) = \(\frac{19}{4}\) = 4\(\frac{3}{4}\)

Question 16. 6\(\frac{3}{4}\) – 3 = Answer: 6\(\frac{3}{4}\) – 3 = 3\(\frac{3}{4}\) Explanation : 6\(\frac{3}{4}\) – 3 = \(\frac{27}{4}\) – \(\frac{12}{4}\) = \(\frac{15}{4}\) = 3\(\frac{3}{4}\)

Question 17. 6\(\frac{3}{4}\) – 4 = Answer: 6\(\frac{3}{4}\) – 4 = 2\(\frac{3}{4}\) Explanation : 6\(\frac{3}{4}\) – 4 = \(\frac{27}{4}\) – \(\frac{16}{4}\) = \(\frac{11}{4}\) = 2\(\frac{3}{4}\)

Question 18. 6\(\frac{3}{4}\) – 6 = Answer: 6\(\frac{3}{4}\) – 6 = \(\frac{3}{4}\) Explanation : 6\(\frac{3}{4}\) – 6 = \(\frac{27}{4}\) – \(\frac{24}{4}\) = \(\frac{3}{4}\)

Question 19. 6\(\frac{3}{4}\) – \(\frac{3}{4}\) = Answer: 6\(\frac{3}{4}\) – \(\frac{3}{4}\) = 6 Explanation : 6\(\frac{3}{4}\) – \(\frac{3}{4}\) = \(\frac{27}{4}\) – \(\frac{3{4}\) = \(\frac{24}{4}\) = 6

Question 20. 2\(\frac{5}{6}\) + 3 = Answer: 2\(\frac{5}{6}\) + 3 = 5\(\frac{5}{6}\) Explanation : 2\(\frac{5}{6}\) + 3 = \(\frac{17}{6}\) + \(\frac{18}{6}\) = \(\frac{35}{6}\) = 5\(\frac{5}{6}\)

Question 21. 2\(\frac{1}{6}\) + 3 = Answer: 2\(\frac{1}{6}\) + 3 = 5\(\frac{1}{6}\) Explanation : 2\(\frac{1}{6}\) + 3 = \(\frac{13}{6}\) + \(\frac{18}{6}\) = \(\frac{31}{6}\) = 5\(\frac{1}{6}\)

Question 22. 2\(\frac{5}{6}\) + 7 = Answer: 2\(\frac{5}{6}\) + 7 = 9\(\frac{5}{6}\) Explanation : 2\(\frac{5}{6}\) + 7 = \(\frac{17}{6}\) + \(\frac{42}{6}\) = \(\frac{59}{6}\) = 9\(\frac{5}{6}\)

Question 23. 3\(\frac{5}{6}\) + 7 = Answer: 3\(\frac{5}{6}\) + 7 = 10\(\frac{5}{6}\) Explanation : 3\(\frac{5}{6}\) + 7 = \(\frac{23}{6}\) + \(\frac{42}{6}\) = \(\frac{65}{6}\) = 10\(\frac{5}{6}\)

Question 24. 7\(\frac{5}{6}\) + 3 = Answer: 7\(\frac{5}{6}\) + 3 = 10\(\frac{5}{6}\) Explanation : 7\(\frac{5}{6}\) + 3 = \(\frac{47}{6}\) + \(\frac{18}{6}\) = \(\frac{65}{6}\) = 10\(\frac{5}{6}\)

Question 25. 10\(\frac{5}{6}\) – 3 = Answer: 10\(\frac{5}{6}\) – 3 = 7\(\frac{5}{6}\) Explanation : 10\(\frac{5}{6}\) – 3 = \(\frac{65}{6}\) – \(\frac{18}{6}\) = \(\frac{47}{6}\) = 7\(\frac{5}{6}\)

Question 26. 10\(\frac{5}{6}\) – 7 = Answer: 10\(\frac{5}{6}\) – 7 = 3\(\frac{5}{6}\) Explanation : 10\(\frac{5}{6}\) – 7 = \(\frac{65}{6}\) – \(\frac{42}{6}\) = \(\frac{23}{6}\) = 3\(\frac{5}{6}\)

Question 27. 3 + \(\frac{4}{5}\) + 2 = Answer: 3 + \(\frac{4}{5}\) + 2 = 5\(\frac{4}{5}\) Explanation : 3 + \(\frac{4}{5}\) + 2 = 5 + \(\frac{4}{5}\) = \(\frac{25}{5}\) + \(\frac{4}{5}\) = \(\frac{29}{5}\) = 5\(\frac{4}{5}\)

Question 28. 5 + \(\frac{7}{8}\) + 4 = Answer: 5 + \(\frac{7}{8}\) + 4 = 9 \(\frac{7}{8}\) Explanation : 5 + \(\frac{7}{8}\) + 4 = 9 + \(\frac{7}{8}\) = \(\frac{72}{8}\) + \(\frac{7}{8}\) = \(\frac{79}{8}\) = 9\(\frac{7}{8}\)

Question 29. 7 + \(\frac{4}{5}\) – 2 = Answer: 7 + \(\frac{4}{5}\) – 2 = 5\(\frac{4}{5}\) Explanation : 7 + \(\frac{4}{5}\) – 2 = 5 + \(\frac{4}{5}\) = \(\frac{29}{5}\) + \(\frac{4}{5}\) = \(\frac{33}{5}\) = 5\(\frac{4}{5}\)

Question 30. 9 + \(\frac{5}{12}\) – 5 = Answer: 9 + \(\frac{5}{12}\) – 5 = 4\(\frac{5}{12}\) Explanation : 9 + \(\frac{5}{12}\) – 5 = 4 + \(\frac{5}{12}\) = \(\frac{48}{12}\) + \(\frac{5}{12}\) + \(\frac{53}{12}\) = 4\(\frac{5}{12}\) .

Question 31. 7 + \(\frac{1}{5}\) + \(\frac{1}{5}\) + 2 Answer: 7 + \(\frac{1}{5}\) + \(\frac{1}{5}\) + 2 = 9\(\frac{2}{5}\) Explanation : 7 + \(\frac{1}{5}\) + \(\frac{1}{5}\) + 2 = 9 + \(\frac{2}{5}\) = \(\frac{45}{5}\) + \(\frac{2}{5}\) = \(\frac{47}{5}\) = 9\(\frac{2}{5}\)

Question 32. 7 + \(\frac{2}{5}\) + 2 = Answer: 7 + \(\frac{2}{5}\) + 2 =  9 \(\frac{2}{5}\)  Explanation : 7 + \(\frac{2}{5}\) + 2 = 9 + \(\frac{2}{5}\) = \(\frac{45}{5}\) + \(\frac{2}{5}\) = \(\frac{47}{5}\) = 9\(\frac{2}{5}\)

Question 33. 7 + \(\frac{2}{5}\) + 2 + \(\frac{2}{5}\) = Answer: 7 + \(\frac{2}{5}\) + 2 + \(\frac{2}{5}\) = 9\(\frac{4}{5}\) Explanation : 7 + \(\frac{2}{5}\) + 2 + \(\frac{2}{5}\) = 9 + \(\frac{4}{5}\) = \(\frac{45}{5}\)  + \(\frac{4}{5}\) = \(\frac{49}{5}\) = 9\(\frac{4}{5}\)

Question 34. 7\(\frac{2}{5}\) + 2\(\frac{2}{5}\) = Answer: 7\(\frac{2}{5}\) + 2\(\frac{2}{5}\) = 9\(\frac{4}{5}\) Explanation : 7\(\frac{2}{5}\) + 2\(\frac{2}{5}\) = \(\frac{37}{5}\)  + \(\frac{12}{5}\) = \(\frac{49}{5}\) = 9\(\frac{4}{5}\)

Question 35. 6 + \(\frac{1}{3}\) + 1 + \(\frac{1}{3}\) = Answer: 6 + \(\frac{1}{3}\) + 1 + \(\frac{1}{3}\) = 7 \(\frac{2}{3}\) Explanation : 6 + \(\frac{1}{3}\) + 1 + \(\frac{1}{3}\) = 7 + \(\frac{2}{3}\) = \(\frac{22}{3}\) + \(\frac{2}{3}\) = \(\frac{24}{3}\)

Question 36. 6\(\frac{1}{3}\) + 1\(\frac{1}{3}\) = Answer: 6\(\frac{1}{3}\) + 1\(\frac{1}{3}\) = 7\(\frac{2}{3}\) Explanation : 6\(\frac{1}{3}\) + 1\(\frac{1}{3}\) = \(\frac{19}{3}\) + \(\frac{4}{3}\) = \(\frac{23}{3}\) = 7\(\frac{2}{3}\)

Question 37. 6 + \(\frac{2}{3}\) – 1 = Answer: 6 + \(\frac{2}{3}\) – 1 = 5\(\frac{2}{3}\) Explanation : 6 + \(\frac{2}{3}\) – 1 = 5 + \(\frac{2}{3}\) = \(\frac{15}{3}\) + \(\frac{2}{3}\) = \(\frac{17}{3}\) = 5\(\frac{2}{3}\)

Question 38. 6\(\frac{2}{3}\) – 1\(\frac{1}{3}\) = Answer: 6\(\frac{2}{3}\) – 1\(\frac{1}{3}\) = 5\(\frac{1}{3}\) Explanation : 6\(\frac{2}{3}\) – 1\(\frac{1}{3}\) = \(\frac{20}{3}\) – \(\frac{4}{3}\) = \(\frac{16}{3}\) = 5\(\frac{1}{3}\)

Question 39. 6\(\frac{2}{3}\) – 1\(\frac{2}{3}\) = Answer: 6\(\frac{2}{3}\) – 1\(\frac{2}{3}\) = 5 Explanation : 6\(\frac{2}{3}\) – 1\(\frac{2}{3}\) = \(\frac{20}{3}\) – \(\frac{5}{3}\) = 5

Question 40. 3 + \(\frac{4}{7}\) + 1 + \(\frac{2}{7}\) = Answer: 3 + \(\frac{4}{7}\) + 1 + \(\frac{2}{7}\) = 4 \(\frac{6}{7}\) Explanation : 3 + \(\frac{4}{7}\) + 1 + \(\frac{2}{7}\) = 4 + \(\frac{6}{7}\) = \(\frac{28}{7}\) + \(\frac{6}{7}\) = \(\frac{34}{7}\) = 4\(\frac{6}{7}\)

Question 41. 3\(\frac{4}{7}\) + 1\(\frac{2}{7}\) = Answer: 3\(\frac{4}{7}\) + 1\(\frac{2}{7}\) = 4\(\frac{6}{7}\) Explanation : 3\(\frac{4}{7}\) + 1\(\frac{2}{7}\) = \(\frac{25}{7}\) + \(\frac{9}{7}\) = \(\frac{34}{7}\) = 4\(\frac{6}{7}\)

Question 42. 7\(\frac{4}{5}\) – 2\(\frac{3}{5}\) = Answer: 7\(\frac{4}{5}\) – 2\(\frac{3}{5}\) = 5\(\frac{1}{5}\) Explanation : 7\(\frac{4}{5}\) – 2\(\frac{3}{5}\) = \(\frac{39}{5}\) – \(\frac{13}{5}\) = \(\frac{26}{5}\) = 5\(\frac{1}{5}\)

Question 43. 7\(\frac{4}{5}\) – 2\(\frac{2}{5}\) = Answer: 7\(\frac{4}{5}\) – 2\(\frac{2}{5}\) = 5\(\frac{2}{5}\) Explanation : 7\(\frac{4}{5}\) – 2\(\frac{2}{5}\) = \(\frac{39}{5}\) – \(\frac{12}{5}\) = \(\frac{27}{5}\) = 5\(\frac{2}{5}\)

Question 44. 13\(\frac{7}{9}\) – 7\(\frac{5}{9}\) = Answer: 13\(\frac{7}{9}\) – 7\(\frac{5}{9}\) = 6\(\frac{2}{9}\) Explanation : 13\(\frac{7}{9}\) – 7\(\frac{5}{9}\) = \(\frac{124}{9}\) – \(\frac{68}{9}\) = \(\frac{56}{9}\)= 6\(\frac{2}{9}\)

Question 1. 2 + 1 = Answer: 2 + 1 = 3 Explanation : adding 1 to 2 we get sum as 3 .

Question 2. 2 + \(\frac{1}{2}\) = Answer: 2 + \(\frac{1}{2}\) = 2\(\frac{1}{2}\) Explanation : 2 + \(\frac{1}{2}\) = \(\frac{4}{2}\) + \(\frac{1}{2}\) = \(\frac{5}{2}\) =2\(\frac{1}{2}\)

Question 3. 2\(\frac{1}{2}\) + 1 = Answer: 2\(\frac{1}{2}\) + 1 = 3\(\frac{1}{2}\) Explanation : 2\(\frac{1}{2}\) + 1 = \(\frac{5}{2}\)  + \(\frac{2}{2}\) = \(\frac{7}{2}\) = 3\(\frac{1}{2}\)

Question 4. 2 – 1 = Answer: 2 – 1 = 1 Explanation : Subtracting 1 from 2 we get 1as difference .

Question 5. 2\(\frac{1}{2}\) – 1 = Answer: 2\(\frac{1}{2}\) – 1 = 1\(\frac{1}{2}\) Explanation : 2\(\frac{1}{2}\) – 1 = \(\frac{5}{2}\)  – \(\frac{2}{2}\) = \(\frac{3}{2}\) = 1\(\frac{1}{2}\)

Question 6. 5 – 2 = Answer: 5 – 2 = 3 Explanation : subtract 2 from 5 we get 3 as difference .

Question 7. 5\(\frac{1}{2}\) – 2 = Answer: 5\(\frac{1}{2}\) – 2 = 3\(\frac{1}{2}\) Explanation : 5\(\frac{1}{2}\) – 2 = \(\frac{11}{2}\)  – \(\frac{4}{2}\)  = \(\frac{7}{2}\) = 3\(\frac{1}{2}\)

Question 8. 6 – 2 = Answer: 6 – 2 = 4 Explanation : subtract 2 from 6 we get 4 as difference .

Question 9. 6\(\frac{1}{3}\) – 2 = Answer: 6\(\frac{1}{3}\) – 2 = 4\(\frac{1}{3}\) Explanation : 6\(\frac{1}{3}\) – 2 = \(\frac{19}{3}\) – \(\frac{6}{3}\)= \(\frac{13}{3}\)= 4\(\frac{1}{3}\)

Question 10. 6\(\frac{2}{3}\) – 2 = Answer: 6\(\frac{2}{3}\) – 2 = 4\(\frac{2}{3}\) Explanation : 6\(\frac{2}{3}\) – 2 = \(\frac{20}{3}\) – \(\frac{6}{3}\)= \(\frac{14}{3}\)= 4\(\frac{2}{3}\)

Question 11. 6\(\frac{2}{3}\) + 2 = Answer: 6\(\frac{2}{3}\) + 2 = 8\(\frac{2}{3}\) Explanation : 6\(\frac{2}{3}\) + 2 = \(\frac{20}{3}\) + \(\frac{6}{3}\)= \(\frac{26}{3}\)= 8\(\frac{2}{3}\)

Question 12. 7 + 2 = Answer: 7 + 2 = 9 Explanation: Adding 2 to 7 we get sum as 9

Question 13. 7 + \(\frac{3}{4}\) = Answer: 7 + \(\frac{3}{4}\) = 7\(\frac{3}{4}\) Explanation : 7 + \(\frac{3}{4}\) = \(\frac{28}{4}\) + \(\frac{3}{4}\) = \(\frac{31}{4}\)= 7\(\frac{3}{4}\)

Question 14. 7\(\frac{3}{4}\) + 2 = Answer: 7\(\frac{3}{4}\) + 2= 9\(\frac{3}{4}\) Explanation : 7\(\frac{3}{4}\) + 2 = \(\frac{31}{4}\) + \(\frac{8}{4}\) = \(\frac{39}{4}\)= 9\(\frac{3}{4}\)

Question 15. 7\(\frac{3}{4}\) – 2 = Answer: 7\(\frac{3}{4}\) – 2= 5\(\frac{3}{4}\) Explanation : 7\(\frac{3}{4}\) – 2 = \(\frac{31}{4}\) – \(\frac{8}{4}\) = \(\frac{23}{4}\)= 5\(\frac{3}{4}\)

Question 16. 7\(\frac{3}{4}\) – 3 = Answer: 7\(\frac{3}{4}\) – 3= 4\(\frac{3}{4}\) Explanation : 7\(\frac{3}{4}\) – 3 = \(\frac{31}{4}\) – \(\frac{12}{4}\) = \(\frac{19}{4}\)= 4\(\frac{3}{4}\)

Question 17. 7\(\frac{3}{4}\) – 4 = Answer: 7\(\frac{3}{4}\) – 4= 3\(\frac{3}{4}\) Explanation : 7\(\frac{3}{4}\) – 4 = \(\frac{31}{4}\) – \(\frac{16}{4}\) = \(\frac{15}{4}\)= 3\(\frac{3}{4}\)

Question 18. 7\(\frac{3}{4}\) – 7 = Answer: 7\(\frac{3}{4}\) – 7= \(\frac{3}{4}\) Explanation : 7\(\frac{3}{4}\) – 7 = \(\frac{31}{4}\) – \(\frac{28}{4}\) = \(\frac{3}{4}\)

Question 19. 7\(\frac{3}{4}\) – \(\frac{3}{4}\) = Answer: 7\(\frac{3}{4}\) – \(\frac{3}{4}\) = 7 Explanation : 7\(\frac{3}{4}\) – \(\frac{3}{4}\) = \(\frac{31}{4}\) – \(\frac{3}{4}\) = \(\frac{28}{4}\) = 7

Question 20. 3\(\frac{5}{6}\) + 2 = Answer: 3\(\frac{5}{6}\) + 2 = 5\(\frac{5}{6}\) Explanation : 3\(\frac{5}{6}\) + 2 = \(\frac{23}{6}\) + \(\frac{12}{6}\) = \(\frac{35}{6}\) = 5\(\frac{5}{6}\)

Question 21. 3\(\frac{1}{6}\) + 2 = Answer: 3\(\frac{5}{6}\) + 2 = 5\(\frac{5}{6}\) Explanation : 3\(\frac{5}{6}\) + 2 = \(\frac{23}{6}\) + \(\frac{12}{6}\) = \(\frac{35}{6}\) = 5\(\frac{5}{6}\)

Question 22. 3\(\frac{5}{6}\) + 6 = Answer: 3\(\frac{5}{6}\) + 6 = 9\(\frac{5}{6}\) Explanation : 3\(\frac{5}{6}\) + 6 = \(\frac{23}{6}\) + \(\frac{36}{6}\) = \(\frac{59}{6}\) = 9\(\frac{5}{6}\)

Question 23. 4\(\frac{5}{6}\) + 6 = Answer: 4\(\frac{5}{6}\) + 6 = 10\(\frac{5}{6}\) Explanation : 4\(\frac{5}{6}\) + 6 = \(\frac{29}{6}\) + \(\frac{36}{6}\) = \(\frac{65}{6}\) = 10\(\frac{5}{6}\)

Question 24. 6\(\frac{5}{6}\) + 4 = Answer: 6\(\frac{5}{6}\) + 4 = 10\(\frac{5}{6}\) Explanation : 6\(\frac{5}{6}\) + 4 = \(\frac{41}{6}\) + \(\frac{24}{6}\) = \(\frac{65}{6}\) = 10\(\frac{5}{6}\)

Question 25. 10\(\frac{5}{6}\) – 4 = Answer: 10\(\frac{5}{6}\) – 4 = 6\(\frac{5}{6}\) Explanation : 10\(\frac{5}{6}\) – 4 = \(\frac{65}{6}\) – \(\frac{24}{6}\) = \(\frac{41}{6}\) = 6\(\frac{5}{6}\)

Question 26. 10\(\frac{5}{6}\) – 6 = Answer: 10\(\frac{5}{6}\) – 6 = 4\(\frac{5}{6}\) Explanation : 10\(\frac{5}{6}\) – 6 = \(\frac{65}{6}\) – \(\frac{36}{6}\) = \(\frac{29}{6}\) = 4\(\frac{5}{6}\)

Question 27. 4 + \(\frac{4}{5}\) + 2 = Answer: 4 + \(\frac{4}{5}\) + 2 = 6\(\frac{4}{5}\) Explanation : 4 + \(\frac{4}{5}\) + 2 = 6 + \(\frac{4}{5}\) = \(\frac{30}{5}\) + \(\frac{4}{5}\) = \(\frac{34}{5}\) = 6\(\frac{4}{5}\)

Question 28. 6 + \(\frac{7}{8}\) + 3 = Answer: 6 + \(\frac{7}{8}\) + 3 = 9\(\frac{7}{8}\) Explanation : 6 + \(\frac{7}{8}\) + 3 = 9 + \(\frac{7}{8}\) = \(\frac{72}{8}\) + \(\frac{7}{8}\) = \(\frac{79}{8}\) = 9\(\frac{7}{8}\)

Question 29. 6 + \(\frac{4}{5}\) – 2 = Answer: 6 + \(\frac{4}{5}\) – 2 = 4\(\frac{4}{5}\) Explanation : 6 + \(\frac{4}{5}\) – 2 = 4 + \(\frac{4}{5}\) = \(\frac{20}{5}\)  + \(\frac{4}{5}\)  = \(\frac{24}{5}\) = 4\(\frac{4}{5}\)

Question 30. 9 + \(\frac{5}{12}\) – 4 = Answer: 9 + \(\frac{5}{12}\) – 4 = 5\(\frac{5}{12}\) Explanation : 9 + \(\frac{5}{12}\) – 4 = 5 + \(\frac{5}{12}\) = \(\frac{60}{12}\) + \(\frac{5}{12}\) = \(\frac{65}{12}\) = 5\(\frac{5}{12}\)

Question 31. 6 + \(\frac{1}{5}\) + \(\frac{1}{5}\) + 2 = Answer: 6 + \(\frac{1}{5}\) + \(\frac{1}{5}\) + 2 = 8 \(\frac{2}{5}\) Explanation : 6 + \(\frac{1}{5}\) + \(\frac{1}{5}\) + 2 = 8 + \(\frac{2}{5}\) = \(\frac{40}{5}\) + \(\frac{2}{5}\) = \(\frac{42}{5}\) = 8\(\frac{2}{5}\)

Question 32. 6 + \(\frac{2}{5}\) + 2 = Answer: 6 + \(\frac{2}{5}\) + 2 = 8\(\frac{2}{5}\) Explanation : 6 + \(\frac{2}{5}\) + 2 = 8 + \(\frac{2}{5}\) = \(\frac{40}{5}\) + \(\frac{2}{5}\)  = \(\frac{42}{5}\) = 8\(\frac{2}{5}\)

Question 33. 6 + \(\frac{2}{5}\) + 2 + \(\frac{2}{5}\) = Answer: 6 + \(\frac{2}{5}\) + 2 + \(\frac{2}{5}\) = 8\(\frac{4}{5}\) Explanation : 6 + \(\frac{2}{5}\) + 2 + \(\frac{2}{5}\) = 8 + \(\frac{4}{5}\) = \(\frac{40}{5}\) + \(\frac{4}{5}\) = \(\frac{44}{5}\) = 8\(\frac{4}{5}\)

Question 34. 6\(\frac{2}{5}\) + 2\(\frac{2}{5}\) = Answer: 6\(\frac{2}{5}\) + 2\(\frac{2}{5}\) = 8\(\frac{4}{5}\) Explanation : 6\(\frac{2}{5}\) + 2\(\frac{2}{5}\) = \(\frac{32}{5}\) + \(\frac{12}{5}\) = \(\frac{44}{5}\)= 8\(\frac{4}{5}\)

Question 35. 5 + \(\frac{1}{3}\) + 1 + \(\frac{1}{3}\) = Answer: 5 + \(\frac{1}{3}\) + 1 + \(\frac{1}{3}\) = 6\(\frac{2}{3}\) Explanation : 5 + \(\frac{1}{3}\) + 1 + \(\frac{1}{3}\) = 6 + \(\frac{2}{3}\) = \(\frac{18}{3}\) + \(\frac{2}{3}\) = \(\frac{20}{3}\) = 6\(\frac{2}{3}\)

Question 36. 5\(\frac{1}{3}\) + 1\(\frac{1}{3}\) = Answer: 5\(\frac{1}{3}\) + 1\(\frac{1}{3}\) = 6\(\frac{2}{3}\) Explanation : 5\(\frac{1}{3}\) + 1\(\frac{1}{3}\) = \(\frac{16}{3}\) + \(\frac{4}{3}\) = \(\frac{20}{3}\)= 6\(\frac{2}{3}\)

Question 37. 7 + \(\frac{2}{3}\) – 1 = Answer: 7 + \(\frac{2}{3}\) – 1 = 6\(\frac{2}{3}\) Explanation : 7 + \(\frac{2}{3}\) – 1 = 6 + \(\frac{2}{3}\) = \(\frac{18}{3}\)  + \(\frac{2}{3}\)  = \(\frac{20}{3}\) = 6\(\frac{2}{3}\)

Question 38. 7\(\frac{2}{3}\) – 1\(\frac{1}{3}\) = Answer: 7\(\frac{2}{3}\) – 1\(\frac{1}{3}\) = 6\(\frac{1}{3}\) Explanation : 7\(\frac{2}{3}\) – 1\(\frac{1}{3}\) = \(\frac{23}{3}\) – \(\frac{4}{3}\) = \(\frac{19}{3}\) = 6\(\frac{1}{3}\)

Question 39. 7\(\frac{2}{3}\) – 1\(\frac{2}{3}\) = Answer: 7\(\frac{2}{3}\) – 1\(\frac{2}{3}\) = 6 Explanation : 7\(\frac{2}{3}\) – 1\(\frac{2}{3}\) = \(\frac{23}{3}\) – \(\frac{5}{3}\) = \(\frac{18}{3}\) = 6

Question 40. 5 + \(\frac{4}{7}\) + 1 + \(\frac{2}{7}\) = Answer: 5 + \(\frac{4}{7}\) + 1 + \(\frac{2}{7}\) = 6\(\frac{6}{7}\) Explanation : 5 + \(\frac{4}{7}\) + 1 + \(\frac{2}{7}\) = 6 + \(\frac{6}{7}\) = \(\frac{42}{7}\) + \(\frac{6}{7}\)  = \(\frac{48}{7}\) =6\(\frac{6}{7}\)

Question 41. 5\(\frac{4}{7}\) + 1\(\frac{2}{7}\) = Answer: 5\(\frac{4}{7}\) + 1\(\frac{2}{7}\) = 6\(\frac{6}{7}\) Explanation : 5\(\frac{4}{7}\) + 1\(\frac{2}{7}\) = \(\frac{39}{7}\) + \(\frac{9}{7}\) = \(\frac{48}{7}\) = 6\(\frac{6}{7}\)

Question 42. 6 + \(\frac{4}{5}\) – 2\(\frac{3}{5}\) = Answer: 6 + \(\frac{4}{5}\) – 2\(\frac{3}{5}\) =  4\(\frac{1}{5}\) Explanation : 6 + \(\frac{4}{5}\) – 2\(\frac{3}{5}\) = \(\frac{30}{5}\) + \(\frac{4}{5}\) – \(\frac{13}{5}\) = \(\frac{21}{5}\) = 4\(\frac{1}{5}\)

Question 43. 6\(\frac{4}{5}\) – 2\(\frac{3}{5}\) = Answer: 6\(\frac{4}{5}\) – 2\(\frac{3}{5}\) = 4\(\frac{1}{5}\) Explanation : 6\(\frac{4}{5}\) – 2\(\frac{3}{5}\) = \(\frac{34}{5}\) – \(\frac{13}{5}\) = \(\frac{21}{5}\) = 4\(\frac{1}{5}\)

Question 44. 13\(\frac{7}{9}\) – 6\(\frac{5}{9}\) = Answer: 13\(\frac{7}{9}\) – 6\(\frac{5}{9}\) = 7\(\frac{2}{9}\) Explanation : 13\(\frac{7}{9}\) – 6\(\frac{5}{9}\) = \(\frac{124}{9}\) – \(\frac{59}{9}\) = \(\frac{65}{9}\) = 7\(\frac{2}{9}\)

Eureka Math Grade 5 Module 3 Lesson 9 Problem Set Answer Key

Question 1. Add. a. 2\(\frac{1}{4}\) + 1\(\frac{1}{5}\) = b. 2\(\frac{3}{4}\) + 1\(\frac{2}{5}\) = c. 1\(\frac{1}{5}\) + 2\(\frac{1}{3}\) = d. 4\(\frac{2}{3}\) + 1\(\frac{2}{5}\) = e. 3\(\frac{1}{3}\) + 4\(\frac{5}{7}\) = f. 2\(\frac{6}{7}\) + 5\(\frac{2}{3}\) = g. 15\(\frac{1}{5}\) + 3\(\frac{5}{8}\) = h. 15\(\frac{5}{8}\) + 5\(\frac{2}{5}\) = Answer: a. 2\(\frac{1}{4}\) + 1\(\frac{1}{5}\) =\(\frac{9}{4}\) + \(\frac{6}{5}\) lcm of 4 and 5 is 20 . \(\frac{45}{20}\) + \(\frac{24}{20}\) = \(\frac{69}{20}\) = 3\(\frac{9}{20}\)

b. 2\(\frac{3}{4}\) + 1\(\frac{2}{5}\) = \(\frac{11}{4}\) + \(\frac{7}{5}\) lcm of 4 and 5 is 20 . \(\frac{55}{20}\) + \(\frac{28}{20}\) =\(\frac{88}{20}\) = \(\frac{22}{5}\) = 4\(\frac{2}{5}\)

c. 1\(\frac{1}{5}\) + 2\(\frac{1}{3}\) =\(\frac{6}{5}\) + \(\frac{7}{3}\) lcm of 5 and 3 is 15 . \(\frac{18}{15}\) + \(\frac{35}{15}\) = \(\frac{53}{15}\) =3\(\frac{8}{15}\)

d. 4\(\frac{2}{3}\) + 1\(\frac{2}{5}\) = \(\frac{14}{3}\) + \(\frac{7}{5}\) lcm of 3 and 5 is 15 . \(\frac{70}{15}\) + \(\frac{21}{15}\) = \(\frac{91}{15}\) = 6\(\frac{1}{15}\)

e. 3\(\frac{1}{3}\) + 4\(\frac{5}{7}\) = \(\frac{10}{3}\) + \(\frac{33}{7}\) lcm of 3 and 7 is 21. \(\frac{70}{21}\) + \(\frac{99}{21}\) = \(\frac{169}{21}\) =8\(\frac{1}{21}\)

f. 2\(\frac{6}{7}\) + 5\(\frac{2}{3}\) = \(\frac{20}{7}\) + \(\frac{17}{3}\) lcm of 7 and 3 is 21 . \(\frac{60}{21}\) + \(\frac{139}{21}\) = \(\frac{199}{21}\) = 9\(\frac{10}{21}\)

g. 15\(\frac{1}{5}\) + 3\(\frac{5}{8}\) =\(\frac{76}{5}\) + \(\frac{29}{8}\) lcm of 5 and 8 is 40 . \(\frac{608}{40}\) + \(\frac{145}{40}\) = \(\frac{753}{40}\) = 18 \(\frac{33}{40}\)

h. 15\(\frac{5}{8}\) + 5\(\frac{2}{5}\) = \(\frac{125}{8}\) + \(\frac{12}{5}\) lcm of 8 and 5 is 40 . \(\frac{625}{40}\) + \(\frac{96}{40}\) = \(\frac{721}{40}\) = 18 \(\frac{1}{40}\)

Question 2. Erin jogged 2\(\frac{1}{4}\) miles on Monday. Wednesday, she jogged 3\(\frac{1}{3}\) miles, and on Friday, she jogged 2\(\frac{2}{3}\) miles. How far did Erin jog altogether? Answer: Fraction of miles jogged on Monday = 2\(\frac{1}{4}\) = \(\frac{9}{4}\) Fraction of miles jogged on Wednesday = 3\(\frac{1}{3}\) = \(\frac{10}{3}\) Fraction of miles jogged on Friday = 2\(\frac{2}{3}\) = \(\frac{8}{3}\) Total Fraction of miles jogged altogether = \(\frac{9}{4}\) + \(\frac{10}{3}\) + \(\frac{8}{3}\) = \(\frac{27}{12}\) + \(\frac{40}{12}\) + \(\frac{32}{12}\) = \(\frac{99}{12}\) =\(\frac{33}{4}\) = 8\(\frac{1}{4}\) . Therefore, Total Fraction of miles jogged altogether = 8\(\frac{1}{4}\)

Question 3. Darren bought some paint. He used 2\(\frac{1}{4}\) gallons painting his living room. After that, he had 3\(\frac{5}{6}\) gallons left. How much paint did he buy? Answer: Fraction of Quantity of paint used for living room = 2\(\frac{1}{4}\) gallons Fraction of Quantity of paint left = 3\(\frac{5}{6}\) gallons Total Fraction of Quantity of Paint = 2\(\frac{1}{4}\) + 3\(\frac{5}{6}\) = \(\frac{9}{4}\) + \(\frac{23}{6}\) = \(\frac{27}{12}\) + \(\frac{46}{12}\) = \(\frac{73}{12}\) . Therefore, Total Fraction of Quantity of Paint = \(\frac{73}{12}\) .

Question 4. Clayton says that 2\(\frac{1}{2}\) + 3\(\frac{3}{5}\) will be more than 5 but less than 6 since 2 + 3 is 5. Is Clayton’s reasoning correct? Prove him right or wrong. Answer: 2\(\frac{1}{2}\) + 3\(\frac{3}{5}\) = \(\frac{5}{2}\) + \(\frac{18}{5}\) = \(\frac{25}{10}\) + \(\frac{36}{10}\) = \(\frac{61}{10}\) = 6\(\frac{1}{10}\) . Clyton is not correct \(\frac{1}{2}\) + \(\frac{3}{5}\) is more than 1 .

Eureka Math Grade 5 Module 3 Lesson 9 Exit Ticket Answer Key

Add. Question 1. 3\(\frac{1}{2}\) + 1\(\frac{1}{3}\) = Answer: 3\(\frac{1}{2}\) + 1\(\frac{1}{3}\) = \(\frac{7}{2}\) + \(\frac{4}{3}\) lcm of 2 and 3 is 6 \(\frac{21}{6}\) + \(\frac{8}{6}\) = \(\frac{29}{6}\)

Question 2. 4\(\frac{5}{7}\) + 3\(\frac{3}{4}\) = Answer: 4\(\frac{5}{7}\) + 3\(\frac{3}{4}\) = \(\frac{33}{7}\) + \(\frac{15}{4}\) lcm of 7 and 4 is 28 \(\frac{132}{28}\) + \(\frac{105}{28}\) = \(\frac{237}{28}\) = 8\(\frac{13}{28}\)

Eureka Math Grade 5 Module 3 Lesson 9 Homework Answer Key

Question 1. Add. a.2\(\frac{1}{2}\) + 1\(\frac{1}{5}\) = b. 2\(\frac{1}{2}\) + 1\(\frac{3}{5}\) = c. 1\(\frac{1}{5}\) + 3\(\frac{1}{3}\) = d. 3\(\frac{2}{3}\) + 1\(\frac{3}{5}\) = e. 2\(\frac{1}{3}\) + 4\(\frac{4}{7}\) = f. 3\(\frac{5}{7}\) + 4\(\frac{2}{3}\) = g. 1\(\frac{1}{5}\) + 4\(\frac{3}{8}\) = h. 18\(\frac{3}{8}\) + 2\(\frac{2}{5}\) = Answer: a. 2\(\frac{1}{2}\) + 1\(\frac{1}{5}\) = 3\(\frac{7}{10}\) Explanation : 2\(\frac{1}{2}\) + 1\(\frac{1}{5}\) = \(\frac{5}{2}\) + \(\frac{6}{5}\) lcm of 2 and 5 is 10 . \(\frac{25}{10}\) + \(\frac{12}{10}\) = \(\frac{37}{10}\) = 3\(\frac{7}{10}\)

b. 2\(\frac{1}{2}\) + 1\(\frac{3}{5}\) = 4 \(\frac{1}{10}\) Explanation : 2\(\frac{1}{2}\) + 1\(\frac{3}{5}\) = \(\frac{5}{2}\) + \(\frac{8}{5}\) lcm of 2 and 5 is 10 \(\frac{25}{10}\) + \(\frac{16}{10}\) = \(\frac{41}{10}\) = 4 \(\frac{1}{10}\)

c. 1\(\frac{1}{5}\) + 3\(\frac{1}{3}\) =4\(\frac{8}{15}\) Explanation : 1\(\frac{1}{5}\) + 3\(\frac{1}{3}\) = \(\frac{6}{5}\) + \(\frac{10}{3}\) lcm of 5 and 3 is 15. \(\frac{18}{15}\) + \(\frac{50}{15}\) = \(\frac{68}{15}\) = 4\(\frac{8}{15}\)

d. 3\(\frac{2}{3}\) + 1\(\frac{3}{5}\) = 5\(\frac{4}{15}\) Explanation : 3\(\frac{2}{3}\) + 1\(\frac{3}{5}\) = \(\frac{11}{3}\) + \(\frac{8}{5}\) lcm of 3 and 5 = 15 . \(\frac{55}{15}\) + \(\frac{24}{15}\) = \(\frac{79}{15}\) = 5\(\frac{4}{15}\)

e. 2\(\frac{1}{3}\) + 4\(\frac{4}{7}\) = 6\(\frac{19}{21}\) Explanation : 2\(\frac{1}{3}\) + 4\(\frac{4}{7}\) = \(\frac{7}{3}\) + \(\frac{32}{7}\) lcm of 3 and 7 is 21 \(\frac{49}{21}\) + \(\frac{96}{21}\) = \(\frac{145}{21}\) = 6\(\frac{19}{21}\)

f. 3\(\frac{5}{7}\) + 4\(\frac{2}{3}\) = 8 \(\frac{8}{21}\) Explanation : 3\(\frac{5}{7}\) + 4\(\frac{2}{3}\) = \(\frac{26}{7}\) + \(\frac{14}{3}\) lcm of 7 and 3 is 21 \(\frac{78}{21}\) + \(\frac{98}{21}\) = \(\frac{176}{21}\) = 8 \(\frac{8}{21}\)

g. 1\(\frac{1}{5}\) + 4\(\frac{3}{8}\) = 4 \(\frac{23}{40}\) Explanation : 1\(\frac{1}{5}\) + 4\(\frac{3}{8}\) = \(\frac{6}{5}\) + \(\frac{27}{8}\) lcm of 5 and 8 is 40 . \(\frac{48}{40}\) + \(\frac{135}{40}\) = \(\frac{183}{40}\) = 4 \(\frac{23}{40}\)

h. 18\(\frac{3}{8}\) + 2\(\frac{2}{5}\) = Explanation : 18\(\frac{3}{8}\) + 2\(\frac{2}{5}\) = \(\frac{147}{8}\) + \(\frac{12}{5}\) lcm of 8 and 5 is 40 . \(\frac{735}{40}\) + \(\frac{96}{40}\) = \(\frac{831}{40}\) = 20\(\frac{31}{40}\)

Question 2. Angela practiced piano for 2\(\frac{1}{2}\) hours on Friday, 2\(\frac{1}{23}\) hours on Saturday, and 3\(\frac{2}{3}\) hours on Sunday. How much time did Angela practice piano during the weekend? Answer: Fraction of hours practiced piano on Friday = 2\(\frac{1}{2}\) hours = \(\frac{5}{2}\) Fraction of hours practiced piano on Saturday = 2\(\frac{1}{3}\) hours = \(\frac{7}{3}\) Fraction of hours practiced piano on Sunday = 3\(\frac{2}{3}\) hours = \(\frac{11}{3}\) Total Fraction of hours practice piano during the weekend = \(\frac{5}{2}\) + \(\frac{7}{3}\) + \(\frac{11}{3}\) = \(\frac{15}{6}\) + \(\frac{14}{6}\) + \(\frac{22}{6}\) = \(\frac{51}{6}\) = \(\frac{17}{2}\) = 8 \(\frac{1}{2}\) Therefore, Total Fraction of hours practice piano during the weekend = 8 \(\frac{1}{2}\)  .

Question 3.. String A is 3\(\frac{5}{6}\) meters long. String B is 2\(\frac{1}{4}\) meters long. What’s the total length of both strings? Answer: Fraction of length of String A = 3\(\frac{5}{6}\) = \(\frac{23}{6}\) meters Fraction of length of String B = 2\(\frac{1}{4}\) = \(\frac{9}{4}\) meters Fraction of total length of both strings = \(\frac{23}{6}\) + \(\frac{9}{4}\) = \(\frac{46}{12}\) + \(\frac{27}{12}\) = \(\frac{73}{12}\) = 6\(\frac{1}{12}\) meters . Therefore, Fraction of total length of both strings = 6\(\frac{1}{12}\) meters .

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