Ncert solutions for class 10 science chapters:.
What is meant by power of a lens, what is absolute refractive index, when a convex lens will act as magnifying glass, which mirror give an erect and enlarged image of an object, contact form.
Case Study Question 01
Read the following and answer any four questions from 1 to 5.
The refraction of light on going from one medium to another takes place according to two laws which are known as the laws of refraction of light. These laws are 1. The ratio of sine of angle of incidence to the sine of angle of refraction is always constant for the pair of media in contact. \frac{\sin i}{\sin r} = μ = constant This constant is called refractive index of the second medium with respect to the first medium. Refractive index is also defined as the ratio of speed of light in vacuum to the speed of light in medium. 2. The incident ray, refracted ray and normal all lie in the same plane. This law is called Snell’s law of refraction.
Question.1. When light travels from air to glass,
(a) angle of incidence > angle of refraction (b) angle of incidence < angle of refraction (c) angle of incidence = angle of refraction (d) can’t say
Question.2. When light travels from air to medium, the angle of incidence is 45° and angle of refraction is 30°. The refractive index of second medium with respect to the first medium is
(a) 1.41 (b) 1.50 (c) 1.23 (d) 1
Question.3. In which medium, the speed of light is minimum?
(a) Air (b) Glass (c) Water (d) Diamond
Question.4. If the refractive index of glass is 1.5 and speed of light in air is 3 \times 10^{8} m/s. The speed of light in glass is
(a) 2 \times 10^{8} m/s (b) 2.9 \times 10^{8} m/s (c) 4.5 \times 10^{8} m/s (d) 3 \times 10^{8} m/s
Question.5. Refractive index of a with respect to b is 2. Find the refractive index of b with respect to a.
(a) 0.4 (b) 0.5 (c) 0.25 (d) 2.
Ans.1. (a) According to Snell’s law of refraction, \frac{\sin i}{\sin r} >1 or i > r Ans.2. (a) As, _{1}\mu^{2}=\frac{\sin i}{\sin r} ⇒ \frac{\sin 45°}{\sin 30°}=\frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}}= 1.41 Ans.3. (d) As diamond has maximum value of refractive index, therefore it has minimum speed of light in medium. Ans.4. (a) As, \mu_{glass}= 1.5, c= 3\times 10^{8} m/s ⇒ \mu = \frac{c}{v} ⇒ 1.5 = \frac{3\times 10^{8}}{v} ⇒ v = 2\times 10^{8} m/s Ans.5. (b) Given, refractive index of a with respect to b is _{b}\mu^{a}=2 Therefore, Refractive index of b with respect to a is \frac{1}{_{b}\mu^{a}} ⇒ _{a}\mu^{b}=\frac{1}{2} =0.5
Case Study Question 02
Question.1. Which of the following lenses would you prefer to use while reading small letters found in dictionary?
(a) A convex lens of focal length 50 cm (b) A concave lens of focal length 50 cm (c) A convex lens of focal length 5 cm (d) A concave lens of focal length 5 cm
(a) Plano concave, concavo convex (b) Plano convex, convexo concave (c) Double concave, concave convex (d) Convexo concave, double convex
Question.3. A small bulb is placed at the focal point of a converging lens. When the bulb is switched on, the lens produces
(a) a convergent beam of light (b) a divergent beam of light (c) a parallel beam of light (d) a patch of coloured light.
Question.4. The part of lens through which the refraction takes place is called
(a) aperture (b) centre of curvature (c) principal axis (d) focus
Question.5. A water drop acts as a
(a) convex lens (b) concave lens (c) double concave lens (d) none of these
Ans.1. (c) Convex lens is used as magnifying glass. For better performance its focal length should be small. Ans.2. (a) Ans.3. (c) Ans.4. (a) A aperture is the area of the lens available for refraction. Ans.5. (a) Water droplets behave like a convex lens only as refraction takes place on outer surface.
Case Study Question 03
The lenses forms different types of images when object placed at different locations. When a ray is incident parallel to the principal axis, then after refraction, it passes through the focus or appears to come from the focus. When a ray goes through the optical centre of the lens, it passes without any deviation.
If the object is placed between focus and optical center of the convex lens, erect and magnified image is formed. As the object is brought closer to the convex lens from infinity to focus, the image moves away from the convex lens from focus to infinity. Also the size of image goes on increasing and the image is always real and inverted. A concave lens always gives a virtual, erect and diminished image irrespective to the position of the object.
Question.1. The location of image formed by a convex lens when the object is placed at infinity is
(a) at focus (b) at 2F (c) at optical center (d) between F and 2F
Question.2. When the object is placed at the focus of concave lens, the image formed is
(a) real and smaller (b) virtual and inverted (c) virtual and smaller (d) real and erect
Question.3. The size of image formed by a convex lens when the object is placed at the focus of convex lens is
(a) small (b) point in size (c) highly magnified (d) same as that of object
Question.4. When the object is placed at 2F in front of convex lens, the location of image is
(a) at F (b) at 2F on the other side (c) at infinity (d) between F and optical center
Question.5. At which location of object in front of concave lens, the image between focus and optical centre is formed
(a) anywhere between centre and infinity (c) at 2F (b) at F (d) infinity
Ans.1. (a) When an object is placed at infinity of convex lens, image will be formed at focus F. Ans.2. (b) Virtual and inverted image is formed, when object is placed at focus of the concave lens. Ans.3. (c) When object is placed at focus of a convex lens, highly enlarged or magnified image is formed. Ans.4. (b) When an object is placed at distance 2F in front of a convex lens, then the image formed is at a distance 2F on the other of the lens. Ans.5. (a) Image if formed between focus and optical centre when the object is placed anywhere between optical centre and infinity.
Case Study Question 04
The relationship between the distance of object from the lens ( u ), distance of image from the lens ( v ) and the focal length ( f ) of the lens is called lens formula. It can be written as \frac{1}{f}=\frac{1}{v}-\frac{1}{u} The size of image formed by a lens depends on the position of the object from the lens. A lens of short focal length has more power whereas a lens of long focal length has less power. When the lens is convex, the power is positive and for concave lens, the power is negative. The magnification produced by a lens is the ratio of height of image to the height of object as the size of the image relative to the object is given by linear magnification ( m ). When, m is negative, image formed is real and when m is positive, image formed is virtual. If m<1 , size of image is smaller than the object. If m>1 , size of image is larger than the object.
Question.1. An object 4 cm in height is placed at a distance of 10 cm from a convex lens of focal length 20 cm. The position of image is
(a) – 20 cm (b) 20 cm (c) -10 cm (d) 10 cm
Question.2. In the above question, the size of image is
(a) 16 cm (b) 8 cm (c) 4 cm (d) 2 cm
Question.3. An object is placed 50 cm from a concave lens and produces a virtual image at a distance of 10 cm infront of lens. The focal length of lens is
(a) -25 cm (b) -12.5 cm (c) 12.5 cm (d) 10 cm
Question.4. A convex lens forms an image of magnification -2 of the height of image is 6 cm, the height of object is
(a) 6 cm (b) 4 cm (c) 3 cm (d) 2 cm
Question.5. A concave lens of focal length 5 cm, the power of lens is
(a) 20 D (b) -20 D (c) 90 D (d) -5 D
Ans.1. (a) Given, f = 20 cm , u = -10 cm Using, \frac{1}{f} = \frac{1}{v}- \frac{1}{u} ⇒ \frac{1}{20} = \frac{1}{(v)} – \frac{1}{-10} ⇒ v = -20 cm Ans.2. (b) As, m = \frac{v}{u}= \frac{-20}{-10}=2 Therefore, m = \frac{h_{2}}{h_{1}} ⇒ 2 = \frac{h_{2}}{4} ⇒ h_{2} = 8 cm Ans.3. (b) Here u = -50 cm, v = 10 cm, v = 10 cm, f = ? Using, \frac{1}{f} = \frac{1}{10}- \frac{1}{50} ⇒ f = -12.5 cm Ans.4. (c) Here, m = -2 , h_{2} = -6 cm, h_{1} = ? As, m = \frac{h_{2}}{h_{1}} ⇒ -2 = \frac{-6}{h_{1}} ⇒ h_{1} = 3 cm Ans.5. (b) As P = \frac{1}{f} (Since, f = 5 cm) ⇒ P = \frac{-1}{0.05 m}=-20 D
Case Study Question 05
The curved surface of a spoon can be considered as a spherical mirror. A highly smooth polished surface is called mirror. The mirror whose reflecting surface is curved inwards or outwards is called a spherical mirror. Inner part works as a concave mirror and the outer bulging part acts as a convex mirror. The center of the reflecting surface of a spherical mirror is called pole and the radius of the sphere of which the mirror is formed is called radius of curvature.
Question.1. When a concave mirror is held towards the sun and its sharp image is formed on a piece of carbon paper for some time, a hole is burnt in the carbon paper. What is the name given to the distance between the mirror and carbon paper?
(a) Radius of curvature (c) Principal focus (b) Focal length (d) Principal axis
Question.2. The distance between pole and focal point of a spherical mirror is equal to the distance between
(a) pole and center of curvature (b) focus point and center of curvature (c) pole and object (d) object and image.
Question.3. The focal length of a mirror is 15 cm. The radius of curvature is
(a) 15 cm (b) 30 cm (c) 45 cm (d) 60 cm
Question.4. The normal at any point on the mirror passes through
(a) focus (b) pole (c) center of curvature (d) any point
Question.5. In a convex spherical mirror, reflection of light takes place at
(a) a flat surface (b) a bent-in surface (c) a bulging-out surface (d) an uneven surface
Case Study Question 06
The spherical mirror forms different types of images when the object is placed at different locations. When the image is formed on screen, the image is real and when the image does not form on screen, the image is virtual. When the two reflected rays meet actually, the image is real and when they appear to meet, the image is virtual. A concave mirror always forms a real and inverted image for different positions of the object. But if the object is placed between the focus and pole, the image formed is virtual and erect. A convex mirror always forms a virtual, erect and diminished image. A concave mirror is used as doctor’s head mirror to focus light on body parts like eyes, ears, nose etc., to be examined because it can form erect and magnified image of the object. The convex mirror is used as a rear view mirrors in automobiles because it can form an small and erect image of an object.
Question.1. When an object is placed at the centre of curvature of a concave mirror, the image formed is
(a) larger than the object (b) smaller than the object (c) same size as that of the object (d) highly enlarged.
Question.2. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be
(a) plane (b) concave (c) convex (d) either plane or convex.
Question.3. A child is standing in front of a magic mirror. She finds the image of her head bigger, the middle portion of her body of the same size and that of the legs smaller. The following is the order of combinations for the magic mirror from the top.
(a) Plane, convex and concave (b) Convex, concave and plane (c) Concave, plane and convex (d) Convex, plane and concave
Question.4. To get an image larger than the object, one can use
(a) convex mirror but not a concave mirror (b) a concave mirror but not a convex mirror (c) either a convex mirror or a concave mirror (d) a plane mirror.
Question.5. A convex mirror has wider field of view because
(a) the image formed is much smaller than the object and large number of images can be seen. (b) the image formed is much closer to the mirror (c) both (a) and (b) (d) none of these.
Case Study Question 07
The relation between distance of an object from the mirror ( u ), distance of image from the mirror ( v ) and the focal length ( f ) is called mirror formula. This formula is valid in all situations for all spherical mirrors for all positions of the object. The size of image formed by a spherical mirror depends on the position of the object from the mirror. The image formed by a spherical mirror can be bigger than the object, equal to the object or smaller than the object. The size of the image relative to the object is given by the linear magnification (m). Thus, the magnification is given by the ratio of height of image to the height of object. If magnification is negative, image is real and if it is positive, image is virtual.
Question.1. What is the position of an image when an object is placed at a distance of 20 cm from a concave mirror of focal length 20 cm?
(a) 5 cm (b) 20 cm (c) 10 cm (d) infinity
(a) Figure A (b) Figure B (c) Figure C (d) Figure D
Question.3. If the magnification of an image is -2, the characteristic of image will be
(a) real and inverted (b) virtual and enlarged (c) virtual and inverted (d) real and small
Question.4. The mirror formula holds for
(a) concave mirror (b) convex mirror (c) plane mirror (d) all of these
Question.5. A parallel beam of light is made to fall on a concave mirror. An image is formed at a distance of 7.5 from the mirror. The focal length of the mirror is
(a) 15 cm (b) 7.5 cm (c) 3.75 cm (d) 10 cm
Ans.1. (d) When an object is placed at the focus of a concave mirror, the image is formed at infinity. Ans.2. (d) When a light ray parallel to the principal axis is incident on a concave mirror, it passes through the principal focus after reflection. Therefore, figure D is correct. Ans.3. (a) If m is negative, the image will be real and inverted. Ans.4. (d) Ans.5. (b) The distance of object from mirror = ∞ Using, \frac{1}{v}+ \frac{1}{u}= \frac{1}{f} ⇒ \frac{1}{∞}- \frac{1}{(-7.5)}= \frac{1}{f} ⇒ f = 7.5 cm
Case Study Question 08
Question.1. When light travels from air to glass, the ray of light bends
(a) towards the normal (b) away from normal (c) anywhere (d) none of these
Question.2. A ray of light passes from a medium A to another medium B. No bending of light occurs if the ray of light hits the boundary of medium B at an angle of
(a) 0° (b) 45° (c) 90° (d) 120°
Question.3. When light passes from one medium to another, the frequency of light
(a) increases (b) decreases (c) remains same (d) none of these
Question.4. When light passes from glass to water, the speed of light
(a) increases (b) decreases (c) remains same (d) first increases then decrease
Question.5. The bottom of pool filled with water appears to be __________ due to refraction of light.
(a) shallower (b) deeper (c) at same depth (d) empty
Ans.1. (a) When, a ray of light travels from air to glass, it bends towards the normal. Ans.2. (c) No bending of light occurs when light is incident normally or perpendicularly on a boundary of two media since angle of incidence and angle of refraction both are zero. Ans.3. (c) When light goes from one medium to other medium, its frequency does not change. Ans.4. (a) The speed to light increases when light passes from glass to water as water is optically rarer medium. Ans.5. (a) The bottom of a pool of water appears to be less deep than it actually is due to refraction.
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Ncert solutions class 10 science chapter 10 – cbse free pdf download.
* According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 9.
NCERT Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction is structured in a way to present a comprehensible coverage of scientific topics related to our daily life. Basic science has been laid out to students with no sharp divisions in disciplines such as Physics, Chemistry and Biology. NCERT is accepted and recommended throughout schools in the nation. Following are a few reasons to rely on NCERT Solutions :
Download most important questions for class 10 science chapter – 10 light reflection and refraction.
NCERT Solutions are popular among students, especially for Science and Mathematics. NCERT Solutions for Class 10 Science Chapter 10 – Light Reflection and Refraction provided here consists of well-explained solutions to all the questions asked in the textbook. Get your hands on the comprehensive NCERT Solutions for Chapter 10 Light Reflection and Refraction, here, for free!
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Questions Page: 168
1. Define the principal focus of a concave mirror.
Light rays that are parallel to the principal axis of a concave mirror converge at a specific point on its principal axis after reflecting from the mirror. This point is called the principal focus of the concave mirror.
2. The radius of curvature of a spherical mirror is 20 cm. What is its focal length?
Radius of curvature (R) = 20 cm
Radius of curvature of the spherical mirror = 2 × Focal length (f)
f= R/2 = 20 / 2 = 10
Therefore, the focal length of the spherical mirror is 10 cm.
3. Name the mirror that can give an erect and enlarged image of an object.
The mirror that can give an erect and enlarged image of an object is a Concave Mirror.
4. Why do we prefer a convex mirror as a rear-view mirror in vehicles?
A convex mirror is preferred as a rear-view mirror in cars and vehicles as it gives a wider field of view, which helps the driver see most of the traffic behind him. Convex mirrors always form an erect, virtual, and diminished image of the objects placed in front of it.
Page No: 171
1. Find the focal length of a convex mirror whose radius of curvature is 32 cm.
Radius of curvature (R) = 32 cm
Radius of curvature = 2 × Focal length (f)
f = R/2 = 32/2 = 16
Therefore, the focal length of the given convex mirror is 16 cm.
2. A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located?
Magnification produced by a spherical mirror:
Object distance (u) = – 10 cm
v = 3 × (- 10) = – 30 cm
Therefore, the negative sign indicates that an inverted image is formed in front of the given concave mirror at a distance of 30 cm.
Page No: 176
1. A ray of light travelling in air enters obliquely into water. Does the light ray bend towards the normal or away from the normal? Why?
The light ray bends towards the normal. When a light ray enters from an optically rarer medium (which has a low refractive index) to an optically denser medium (which has a high refractive index), its speed slows down and bends towards the normal. As water is optically denser than air, a ray of light entering from air into water will bend towards the normal.
2. Light enters from air to glass, having a refractive index 1.50. What is the speed of light in the glass? The speed of light in vacuum is 3 x 10 8 ms -1 .
Refractive index of a medium (nm) = Speed of light in vacuum/Speed of light in the medium
Speed of light in vacuum (c) = 3 × 10 8 m/s
Refractive index of glass (ng) = 1.50
Speed of light in the glass (v) = Speed of light in vacuum/ Refractive index of glass
=3 × 10 8 /1.50 = 2x 10 8 ms -1 .
3. Find out, from the table, the medium having the highest optical density. Also, find the medium with the lowest optical density.
|
| ||
1.0003 | Canada Balsam | 1.53 | |
1.31 | – | – | |
1.33 | Rock salt | 1.54 | |
1.36 | – | – | |
1.44 | Carbon disulphide | 1.63 | |
| 1.46 | Dense flint glass | 1.65 |
1.47 | Ruby | 1.71 | |
1.50 | Sapphire | 1.77 | |
| 1.52 | Diamond | 2.42 |
Lowest optical density = Air
Highest optical density = Diamond
The optical density of a medium is directly related to its refractive index. A medium with the highest refractive index will have the highest optical density and vice-versa.
It can be observed from the table that air and diamond, respectively have the lowest and highest refractive index. Hence, air has the lowest optical density and diamond has the highest optical density.
4. You are given kerosene, turpentine and water. In which of these does the light travel fastest? Use the information given in the table.
Light travels faster in water as compared to kerosene & turpentine, as the refractive index of water is lower than that of kerosene and turpentine. The speed of light is inversely proportional to the refractive index.
5. The refractive index of diamond is 2.42. What is the meaning of this statement?
A diamond has a refractive index of 2.42, which means that the speed of light in a diamond will reduce by a factor of 2.42 as compared to its speed in the air.
In other words, the speed of light in a diamond is 1/2.42 times the speed of light in a vacuum.
Page No: 184
1. Define 1 dioptre of power of a lens.
Dioptre is the SI unit of power of lens is denoted by the letter D. 1 dioptre can be defined as the power of a lens of focal length 1 metre.
2. A convex lens forms a real and inverted image of a needle at a distance of 50 cm from it. Where is the needle placed in front of the convex lens if the image is equal to the size of the object? Also, find the power of the lens.
The position of the image should be at 2F since the image is real and the same size.
It is given that the image of the needle is formed at a distance of 50 cm from the convex lens. Therefore, the needle is placed in front of the lens at a distance of 50 cm.
Object distance (u) = – 50 cm
Image distance, (v) = 50 cm
Focal length = f
According to the lens formula,
3. Find the power of a concave lens of focal length 2 m.
The focal length of the concave lens (f) = 2 m
Power of lens (P) = 1/f = 1/ (-2) = -0.5D
Page No: 185
1. Which one of the following materials cannot be used to make a lens?
(c) Plastic
Answer –
(d) Clay cannot be used to make a lens because if the lens is made up of clay, the light rays cannot pass through it
2. The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object?
(a) Between the principal focus and the centre of curvature
(b) At the centre of curvature
(c) Beyond the centre of curvature
(d) Between the pole of the mirror and its principal focus.
(d) The position of the object should be between the pole of the mirror and its principal focus.
3. Where should an object be placed in front of a convex lens to get a real image of the size of the object?
(a) At the principal focus of the lens
(b) At twice the focal length
(c) At infinity
(d) Between the optical centre of the lens and its principal focus.
(b) The object should be placed at twice the focal length
4. A spherical mirror and a thin spherical lens have a focal length of -15 cm. The mirror and the lens are likely to be
(a) both concave
(b) both convex
(c) the mirror is concave, and the lens is convex
(d) the mirror is convex, but the lens is concave
(a) Both are likely to be concave.
Page No: 186
5. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be
(b) concave
(d) either plane or convex
(d) The mirrors are likely to be either plane or convex
6. Which of the following lenses would you prefer to use while reading small letters found in a dictionary?
(a) A convex lens of focal length 50 cm
(b) A concave lens of focal length 50 cm
(c) A convex lens of focal length 5 cm
(d) A concave lens of focal length 5 cm
(c) A convex lens of focal length 5 cm can be used while reading small letters found in a dictionary
7. We wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. What should be the range of distance of the object from the mirror? What is the nature of the image? Is the image larger or smaller than the object? Draw a ray diagram to show the image formation in this case.
Range of the distance of the object = 0 to 15 cm from the pole of the mirror.
Nature of the image = virtual, erect, and larger than the object.
8. Name the type of mirror used in the following situations.
(a) Headlights of a car
(b) Side/rear-view mirror of a vehicle
(c) Solar furnace
Support your answer with a reason.
(a) Concave Mirror: Concave mirrors can produce a powerful parallel beam of light when the light source is placed at their principal focus.
(b) Convex Mirror: Because of its largest field of view.
(c) Concave Mirror: Because it concentrates the parallel rays of the sun at a principal focus.
9. One-half of a convex lens is covered with black paper. Will this lens produce a complete image of the object? Verify your answer experimentally. Explain your observations.
Yes, it will produce a complete image of the object, as shown in the figure. This can be verified experimentally by observing the image of a distant object, like a tree on a screen, when the lower half of the lens is covered with black paper. However, the intensity or brightness of the image will reduce.
10. An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and nature of the image formed.
Height of the object, h 0 = 5 cm
Distance of the object from converging lens, u = -25 cm
Focal length of a converging lens, f = 10 cm
Using the lens formula,
Thus, the image is inverted and formed at a distance of 16.7 cm behind the lens and measures 3.3 cm. The ray diagram is shown below.
11. A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram.
Focal length of concave lens (OF 1 ), f = – 15 cm
Image distance, v= – 10 cm
The negative value of u indicates that the object is placed 30 cm in front of the lens. This is shown in the following ray diagram.
12. An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.
Focal length of convex mirror (f) = +15 cm
According to the mirror formula,
The image is located at a distance of 6 cm from the mirror on the other side of the mirror.
The positive and a value of less than 1 magnification indicates that the image formed is virtual, erect, and diminished.
13. The magnification produced by a plane mirror is +1. What does this mean?
The positive sign means an image formed by a plane mirror is virtual and erect. Since the magnification is 1, it means that the size of the image is equal to the size of the object.
14. An object 5 cm is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position, nature and size of the image.
Object distance (u) = – 20 cm
Object height (h) = 5 cm
Radius of curvature (R) = 30 cm
Radius of curvature = 2 × Focal length
The positive value of image height indicates that the image formed is erect.
Hence, the image formed is erect, virtual, and smaller in size.
15. An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed so that a sharply focused image can be obtained? Find the size and nature of the image.
Object distance (u) = – 27 cm
Object height (h) = 7 cm
Focal length (f) = – 18 cm
The negative value of image height indicates that the image formed is inverted.
16. Find the focal length of a lens of power -2.0 D. What type of lens is this?
Power of lens (P) = 1/f
f = -1/2 = -0.5 m
A concave lens has a negative focal length. Therefore, it is a concave lens.
17. A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?
f = 1/1.5 = 10/15 = 0.66 m
A convex lens has a positive focal length. Therefore, it is a convex lens or a converging lens.
Chapter 10 Light Reflection and Refraction are one of the important chapters in Class 10 Science, and the expected marks weightage of the chapter, according to the latest marking scheme is 7 marks. In Chapter 10 of Class 10 Science, students will get well-versed in light phenomena such as refraction and reflection. One will learn about spherical mirrors, image formation and to draw ray diagrams.
Topics covered in this chapter:
Have you ever wondered what makes things visible to us? The answer to the question is light. During the day, it is sunlight that helps us see objects. When light falls on an object, it reflects. This reflected ray, when received by our eyes, helps us see things. Numerous wonderful phenomena are associated with light, such as the formation of the rainbow, of stars, and many more. In Chapter 10 Light Reflection and Refraction of Class 10 Science, let us study the phenomena of refraction and reflection using straight-line propagation of light. We shall also try to understand the reflection of light by spherical mirrors in this chapter using the NCERT Solutions from BYJU’S.
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NCERT Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction
July 13, 2020 by Veerendra
These Solutions are part of NCERT Solutions for Class 10 Science . Here we have given NCERT Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction. Learn Insta provides you the Free PDF download of NCERT Solutions for Class 10 Science (Physics) Chapter 10 – Light Reflection and Refraction solved by Expert Teachers as per NCERT (CBSE) Book guidelines. All Chapter 10 – Light Reflection and Refraction Exercise Questions with Solutions to help you to revise complete Syllabus and Score More marks.
NCERT Questions
In Text Book Questions
Question 1. Define the principal focus of a concave mirror. Answer: A point on the principal axis where the parallel rays of light after reflecting from a concave mirror meet.
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Question 3. Name a mirror that can give an erect and magnified image of an object. Answer: A concave mirror.
Question 4. Why do we prefer a convex mirror as a rear-view mirror in vehicles ? [CBSE (All India) 2007, 2011, 2012] Answer: This is because a convex mirror forms an erect and diminished (small in size) images of the objects behind the vehicle and hence the field of view behind the vehicle is increased.
Question 5. Find the focal length of a convex mirror whose radius of curvature is 32 cm. Answer: R = +32 cm. Therefore, f = R/2 = +32/2 = +16 cm. Thus, focal length of the convex mirror = +16 cm.
Question 6. A concave mirror produces three times magnified (enlarged) real image of an object placed at 10 cm in front of it. Where is the image located ? Answer: m – -3, But m = -v/u, so v = 3u u = -10 cm v = 3 (-10 cm) =-30 cm Thus, the image is located at a distance of 30 cm to the left side of the concave mirror.
Question 7. A ray of light travelling in air enters obliquely into water. Does the light ray bend towards the normal or away from the normal ? Why ? Answer: The ray of light bends towards the normal because the speed of light decreases when it goes from air (rarer medium) into water (denser medium).
Question 9. You are given kerosene, turpentine and water. In which of these does the light travel faster ? Answer: We know, v = c/n. Refractive index (n) of water is 1.333, whereas refractive index of kerosene is 1.44 and that of turpentine is 1.47. As refractive index of water is least, so speed of light in water is more than in kerosene and turpentine. Hence, light travels faster in water.
Question 11. Define 1 dioptre of power of a lens. Answer: Power = I/f (in m). Power of a lens is 1 dioptre if focal length of the lens is 1 metre or 100 cm.
NCERT Chapter End Exercises
Question 1. Which one of the following materials cannot be tised to make a lens 1 (a) water (b) glass (c) plastic (d) clay. Answer: (d). This is because clay is opaque (i.e. light cannot pass through it).
Question 2. The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object ? (a) between the principal focus and the centre of curvature (b) at the centre of curvature (c) beyond the centre of curvature (d) between the pole of the mirror and its principal focus. Answer: (d).
Question 3. Where should an object be placed in front of a convex lens to get a real image of the size of the object ? (Bihar Board 2012) (a) at the principal focus of the lens (b) at twice the focal length (c) at infinity (d) between the optical centre of the lens and its principal focus. Answer: (b).
Question 4. A spherical mirror and a thin spherical lens have each a focal length of — 15 cm. The mirror and the lens are likely to be (a) both are concave (b) both are convex (c) the mirror is concave and the lens is convex (d) the mirror is convex but the lens is concave. Answer: (a).
Question 5. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be (a) plane only (b) concave only (c) convex only (d) either plane or convex. Answer: (d).
Question 6. Which of the following lenses would you prefer to use while reading small letters found in a dictionary ? (a) a convex lens of focal length 50 cm (b) a concave lens of focal length 50 cm (c) a convex lens of focal length 5 cm (d) a concave lens of focal length 5 cm. Answer: (c). Magnifying power of a reading glass (Convex lens) = 1/f.
Question 7. We wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. What should be the range of distance of the object from the mirror ? What is the nature of the image ? Is the image larger or smaller than the object ? Draw a ray diagram to show the image formation in this case. Answer: A concave mirror produces an erect image if the object is placed between the pole and the focus of the concave mirror. Thus, object may be placed at any position whose distance is less than 15 cm from the concave mirror. The image is virtual and erect. The image is larger than the object. For a ray diagram, see figure 24.
Question 8. Name the type of mirror used in the following situations : (a) head lights of a car (b) side rear view mirror of a vehicle (c) solar furnace. Support your answer with reason. (CBSE 2012, 2013) Answer: (a) Concave mirror. When a bulb is placed at the focus of a concave mirror, then the beam of light from the bulb after reflection from the concave mirror goes as a parallel beam which lights up the front road. (b) Convex mirror. Image formed by a convex mirror is erect and small in size. The field of view behind the vehicle is large. (c) Concave mirror. Concave mirror focuses rays of light coming from the sun at its focus. So, the temperature at the focus is raised.
Practical Skills Based Questions (2 Marks)
Get 100 percent accurate NCERT Solutions for Class 10 Science Chapter 10 (Light Reflection and Refraction) explained by expert Science teachers. We provide step by step solutions for the questions given in Class 10 Science textbook as per CBSE Board guidelines from the latest NCERT book for Class 10 Science. The topics and sub-topics in Chapter 10 Light Reflection and Refraction
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NCERT Solutions for Class 10 Science Chapter 10 are available to download. Light Reflection and Refraction is organized in such a way that it covers a wide range of scientific topics that are relevant to our daily lives. Students have been taught basic science with no clear distinctions between areas such as physics, chemistry, and biology. NCERT is widely used and recommended in schools around the country. The following are some of the benefits of using NCERT Solutions :
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Class 10 Science ch light NCERT solution are widely used by students, particularly in Science and Mathematics. Here you will find NCERT Solutions for Class 10 Science Chapter 10 – Light Reflection and Refraction , which includes well-explained answers to all of the questions from the textbook. Get the whole NCERT Solutions for Chapter 10 Light Reflection and Refraction for free right here!
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Here are all the to class 10 Light Reflection and Refraction question answer improve your understanding:
1. Which one of the following materials cannot be used to make a lens?
(c) Plastic
Ans. (d) Clay
Reason: Clay is not a suitable material for making lenses due to its properties. Lenses are typically made from materials like glass, plastic, or even water, but clay lacks the necessary optical characteristics required for lens functionality.
2. The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object?
(a) Between the principal focus and the centre of curvature
(b) At the centre of curvature
(c) Beyond the centre of curvature
(d) Between the pole of the mirror and its principal focus.
Ans. (c) Beyond the centre of curvature
Reason: When the image formed by a concave mirror is virtual, erect, and larger than the object, the object must be positioned beyond the centre of curvature. This specific positioning results in the described characteristics of the image formed by the concave mirror.
3. Where should an object be placed in front of a convex lens to get a real image of the size of the object?
(a) At the principal focus of the lens
(b) At twice the focal length
(c) At infinity
(d) Between the optical centre of the lens and its principal focus.
Ans. (b) At twice the focal length
Reason: To obtain a real image of the size of the object with a convex lens, the object should be placed at twice the focal length of the lens. This positioning results in the formation of a real image that is the same size as the object.
4. A spherical mirror and a thin spherical lens have a focal length of -15 cm. The mirror and the lens are likely to be
(a) both concave
(b) both convex
(c) the mirror is concave, and the lens is convex
(d) the mirror is convex, but the lens is concave
Ans. (c) the mirror is concave, and the lens is convex
Reason: Given that the focal length is negative (-15 cm), the mirror is concave, and the lens is convex. This is because the sign convention for focal length distinguishes between concave (negative focal length) and convex (positive focal length) mirrors and lenses.
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5. No matter how far you stand from a mirror, your image appears erect. The mirror is likely to be
(b) concave
(d) either plane or convex
Ans. (a) plane
Reason: If your image appears erect regardless of the distance from the mirror, the mirror is likely to be a plane mirror. Plane mirrors always produce virtual and erect images of objects.
6. Which of the following lenses would you prefer to use while reading small letters found in a dictionary?
(a) A convex lens of focal length 50 cm
(b) A concave lens of focal length 50 cm
(c) A convex lens of focal length 5 cm
(d) A concave lens of focal length 5 cm
Ans. (c) A convex lens of focal length 5 cm
Reason: To read small letters found in a dictionary, a convex lens with a shorter focal length (5 cm) would be preferred. A shorter focal length lens provides greater magnification, making it easier to read small letters with clarity.
7. We wish to obtain an erect image of an object, using a concave mirror of focal length 15 cm. What should be the range of distance of the object from the mirror? What is the nature of the image? Is the image larger or smaller than the object? Draw a ray diagram to show the image formation in this case.
8. Name the type of mirror used in the following situations.
(a) Headlights of a car
(b) Side/rear-view mirror of a vehicle
(c) Solar furnace
Support your answer with a reason.
(a) Headlights of a car – Concave mirror
Concave mirrors are used in the headlights of cars because they can focus the light from the bulb into a parallel beam, providing better illumination of the road ahead. The bulb is placed at the focus of the concave mirror.
(b) Side/rear-view mirror of a vehicle – Convex mirror
Convex mirrors are used as side/rear-view mirrors in vehicles. They provide a wider field of view, allowing the driver to see more of the traffic behind them. Convex mirrors form virtual, erect, and diminished images, which is desirable for rear-view mirrors.
(c) Solar furnace – Concave mirror
Concave mirrors are used in solar furnaces to concentrate the sun’s rays onto a small area, creating a high-temperature focal point. The parallel rays from the sun are reflected and focused by the concave mirror, heating up the solar furnace placed at the focus.
9. One-half of a convex lens is covered with black paper. Will this lens produce a complete image of the object? Verify your answer experimentally. Explain your observations.
No, a convex lens with one-half covered by black paper will not produce a complete image of the object. This can be verified experimentally by placing such a lens in front of an object and observing the image formed on a screen.
When one-half of a convex lens is covered, only the uncovered portion of the lens can refract light and contribute to the formation of the image. The covered portion blocks the light rays passing through it, resulting in an incomplete or partial image.
Experimentally, you will observe that the image formed is cut off on one side, corresponding to the covered portion of the lens. The image will appear as a semicircle or a partial image of the object.
10. An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and nature of the image formed.
Position of the image: 16.67 cm on the opposite side of the lens.
Size of the image: 3.33 cm (inverted).
Nature of the image: Real and inverted.
The lens formula is 1/f = 1/u – 1/v
Using the lens formula:
1/v = 1/f + 1/u
1/v = 1/10 + 1/-25
v = 16.67 cm
The positive value of v indicates that the image is formed on the opposite side of the lens.
Calculate the magnification (m):
m = h i /h 0 = v/u
m = 16.67/-25
The negative sign indicates that the image is inverted.
Determine the image height (h i ):
h i = m × h 0
h i = -0.67 × 5 = -3.33 cm
11. A concave lens of focal length 15 cm forms an image 10 cm from the lens. How far is the object placed from the lens? Draw the ray diagram.
12. An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.
13. The magnification produced by a plane mirror is +1. What does this mean?
14. An object 5 cm is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position, nature and size of the image.
15. An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed so that a sharply focused image can be obtained? Find the size and nature of the image.
16. Find the focal length of a lens of power -2.0 D. What type of lens is this?
17. A doctor has prescribed a corrective lens of power +1.5 D. Find the focal length of the lens. Is the prescribed lens diverging or converging?
NCERT Exemplar Answers key for Class 10 Science Chapter 10 also are accessible.
Class 10 Science 10th Chapter CBSE Notes
Chapter 10 – Light Reflection and Refraction NCERT Solutions for Class 10 Science
10th Chapter One of the most essential chapters in Class 10 Science is Light Reflection and Refraction, which is worth 7 points according to the most recent grading scheme. Students will learn about light phenomena such as refraction and reflection in Chapter 10 of Class 10 Science. Spherical mirrors, image creation, and how to make ray diagrams will all be covered.
Understanding these concepts is crucial as they form the basis of many optical devices and natural phenomena. Here are the important topics covered in Class 10 Science Chapter 10:
Reflection of Light:
Refraction of Light:
Optical Phenomena:
Have you ever pondered what allows us to see things? The response to the question is simple. During the day, sunlight assists us in seeing items. Light reflects as it strikes an object. When this reflected ray reaches our eyes, it aids our vision. Light is responsible for many spectacular events, including the development of the rainbow, stars, and many others. Let us investigate the phenomena of refraction and reflection using straight-line light propagation in Class 10 Science Chapter 10 Light Reflection and Refraction. In this chapter, we’ll use the NCERT Solutions from INFINITY LEARN to try to comprehend how spherical mirrors reflect light.
What topics are covered in ncert solutions for class 10 science chapter 10.
The NCERT Solutions for Class 10 Science Chapter 10 cover topics like the laws of reflection and refraction, image formation by mirrors and lenses, refraction through a glass slab, and practical applications of these concepts in optical devices.
The NCERT Solutions provide detailed, step-by-step answers to all textbook questions, helping students understand complex concepts and practice problem-solving techniques, which are crucial for performing well in exams.
You can download the NCERT Solutions for Class 10 Science Chapter 10 from various educational websites and platforms that offer free PDF downloads, ensuring you have easy access to study materials anytime.
Yes, the NCERT Solutions for Chapter 10 include comprehensive explanations and ray diagrams for image formation by both concave and convex lenses and mirrors, aiding in a clear understanding of these concepts.
Yes, the NCERT Solutions for Chapter 10 include solved numerical problems related to reflection and refraction, mirror and lens formulas, and magnification, helping students practice and master these important calculations.
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In CBSE Class 10 Science Paper, Students will have to answer some questions based on Assertion and Reason. There will be a few questions based on case studies and passage based as well. In that, a paragraph will be given, and then the MCQ questions based on it will be asked. Here, we have provided case … Continue reading Case Study and Passage Based Questions for Class 10 Science Chapter 10 ...
Contents. Case Study Questions Class 10 Science Chapter 10 Light Reflection and Refraction Case study:1 Case study: 2 Case study:3. At Case Study Questions there will given a Paragraph. In where some Important Questions will made on that respective Case Based Study. There will various types of marks will given 1 marks, 2 marks, 3 marks, 4 marks.
Explanation: In a convex spherical mirror, reflection of light takes place at a bulging-out surface. Question 2: Read the following and answer the questions given below: A lens is a piece of any transparent material bounded by two curved surfaces. There are two types of lenses convex lens and concave lens.
Please practise these case study based Class 10 Science Questions and answers to get more marks in examinations. Case Study Questions Chapter 1 Light Reflection and Refraction. Case/Passage - 1 A 5.0 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 20 cm. The distance of the object from the lens is ...
Here, we have provided case-based/passage-based questions for Class 10 Science Chapter 10 Light Reflection and Refraction. Case Study/Passage-Based Questions. Question 1: The spherical mirror forms different types of images when the object is placed at different locations. When the image is formed on the screen, the image is real and when the ...
CBSE 10th Standard Science Subject Light Reflection and Refraction Case Study Questions With Solution 2021 Answer Keys. (i) (b): The focal length of a concave mirror is the distance between its pole and principal focus. (ii) (b) (iii) (b): Given that, f = 15 cm. Radius of curvature of a spherical mirror is given as. R= 2F.
Students who are studying in CBSE class 10 board, need to get the knowledge about the Light Reflection and Refraction Case Study Based Questions. Case based questions are generally based on the seen passages from the chapter Light Reflection and Refraction. Through solving the case based questions, students can understand each and every concept.
Chapter Light part -2 refraction Case study-based questions. Question 1. Question 2. Question 3. Question 4. Question 5. Answer key. (iv) When light passes from glass to water, the speed of light decreases first increases then decrease due to retraction of light. at same depth (d) empty (a) increases (c) remains same (v) The bottom of pool ...
Here, we have provided case-based/passage-based questions for Class 10 Science Chapter 10 Light Reflection and Refraction. Case Study/Passage-Based Questions. Question 1: The spherical mirror forms different types of images when the object is placed at different locations. When the image is formed on the screen, the image is real and when the ...
The Chapter wise Important case study based questions with their solved answers in CBSE Class 10 Science can be accessed from the table below: CBSE Class 10 Science Chapter 1 Chemical Reactions ...
Sample Papers with Case Study Questions. Class 10 Science Sample Papers with case study questions are available in the myCBSEguide App. There are 4 such questions (Q.No.17 to 20) in the CBSE model question paper. If you analyze the format, you will find that the MCQs are very easy to answer. So, we suggest you, read the given paragraph ...
Case Study Questions Class 10 Science. In board exams, students will find the questions based on assertion and reasoning. Also, there will be a few questions based on case studies. In that, a paragraph will be given, and then the MCQ questions based on it will be asked. Case Study Questions for Chapter 1 Chemical Reactions and Equations.
NCERT Exemplar Solutions Class 10 Science Chapter 10 - Free PDF Download. NCERT Exemplar Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction will boost your confidence in attempting the board exam by providing you with different types of questions that can be asked on the topic of Reflection and Refraction. In Chapter 10, students will understand the phenomena of ...
Get NCERT Solutions, Notes, Numericals, MCQ (with Solutions) for Chapter 10 Class 10 Science, Light - Reflection and Refraction. In addition to providing the notes and solutions, we also provide. MCQ, 1 Mark, 2 Marks - Questions and Answers. (which you can download in PDF) Numericals of Light Class 10 - on both Lens Formula and Mirror Formula.
Full syllabus notes, lecture and questions for Class 10 Science Chapter 9 Case Based Questions - Light Reflection and Refraction - Class 10 ... Students of Class 10 can study Case Based Type Practice Questions: Light- Reflection & Refraction alongwith tests & analysis from the EduRev app, which will help them while preparing for their exam. ...
Spherical Mirrors. Refraction Of Light. Free download NCERT Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction PDF in Hindi Medium as well as in English Medium for CBSE, Uttarakhand, Bihar, MP Board, Gujarat Board, and UP Board students, who are using NCERT Books based on updated CBSE Syllabus for the session 2019-20.
Speed of light is maximum in vacuum. It is 3 × 10^8 m/s. • Cause of refraction : Change in speed of light. Some examples of refraction : (i) The bottom of swimming pool appears higher. (ii) A pencil partially immersed in water appears to be bent at the interface of water and air. (iii) Lemons placed in a glass tumbler appear bigger.
The speed of light in vacuum is 3 x 108 ms-1. Answer. Refractive index of a medium, n m = Speed of light in vacuum/Speed of light in the medium. Speed of light in vacuum, c = 3 × 10 8 ms -1. Refractive index of glass, n g = 1.50. Speed of light in the glass, v = Speed of light in vacuum/ Refractive index of glass. = c/n g.
Answer. Tagged In Case Study Questions Chapter 9 Light Reflection and Refraction. Case Study Question 01 Read the following and answer any four questions from 1 to 5. The refraction of light on going from one medium to another takes place according to two laws which are known as the laws of refraction of light. These laws are 1.
NCERT Solutions Class 10 Science Chapter 10 - CBSE Free PDF Download *According to the CBSE Syllabus 2023-24, this chapter has been renumbered as Chapter 9. NCERT Solutions for Class 10 Science Chapter 10 Light Reflection and Refraction is structured in a way to present a comprehensible coverage of scientific topics related to our daily life. Basic science has been laid out to students with ...
Answer: We know, v = c/n. Refractive index (n) of water is 1.333, whereas refractive index of kerosene is 1.44 and that of turpentine is 1.47. As refractive index of water is least, so speed of light in water is more than in kerosene and turpentine. Hence, light travels faster in water. Question 10.
refraction of light using the straight-line propagation of light. These basic concepts will help us in the study of some of the optical phenomena in nature. We shall try to understand in this Chapter the reflection of light by spherical mirrors and refraction of light and their application in real life situations. 10.1 REFLECTION OF LIGHT
NCERT Solutions Class 10 Science Chapter 10 CBSE Free PDF Download. Download the Class 10 Science ch light NCERT solution in a free PDF format now and boost your understanding and performance in the subject. In this you will get light reflection and refraction class 10 questions and answers pdf which you can use offline.