lesson 7 homework 5.3 answer key

Chapter 5: Ratios and Proportions

Chapter 5 homework solutions.

5.1-5.3 Extra Practice Worksheet

5.1 Ratios and Rates

5.1 Lesson Preso

5.1 Textbook Exercises: page 167

Ba: 1-6, 11-27 odd;

Avg: 1-6, 11-21 odd, 24-28 even, 29, 31;

Adv: 1-6, 18-38 even

5.2 Proportions

5.2 Textbook Exercises page 174

Ba: 1-4, 5-13 odd, 21-27 odd;

Avg 1-4, 5-13 odd, 22-30 even;

Adv: 1-4, 6-14 even, 22-32 even

5.3 Writing Proportions

5.3 Lesson Preso

5.3 Textbook Exercises page 182

Ba: 1-3, 9, 11, 12, 13-23 odd

Avg: 1-3, 8-14 even, 19-23

Adv: 1-3, 8-24 even, 25

5.4 Solving Proportions

5.4 Lesson Preso

5.4 Textbook Exercises page 190

Ba: 1-3, 5-9 odd, 15-21 odd, 22, 23-27 odd

Avg: 1-3, 5-9 odd, 15-21 odd, 22, 29, 30, 32-35

Adv: 1-3, 4-8 even, 14-38 even

5.5 Lesson Preso

5.5 Textbook Exercises page 196

Ba: 1-3, 5-11 odd, 12, 13-17 odd

Avg: 1-3, 5-11 odd, 12, 14-17

Adv: 1-3, 4-18 even

5.6 Direct Variation

5.6 Lesson Preso

5.6 Textbook Exercises page 202

Ba: 1-3, 7-17 odd, 18, 19-25 odd

Avg: 1-3, 7-17 odd, 18-28 even

Adv: 1-3, 8-28 even

Chapter 5 Review

5.1-5.3 Review Quizizz:

5.4-5.6 Review Quizizz:

Chapter 5 Review Quizizz:

• Barretts Elementary
• Bellerive Elementary
• Carman Trails Elementary
• Claymont Elementary
• Craig Elementary
• Green Trails Elementary
• Hanna Woods Elementary
• Henry Elementary
• Highcroft Ridge Elementary
• Mason Ridge Elementary
• McKelvey Elementary
• McKelvey Primary Elementary
• Oak Brook Elementary
• Pierremont Elementary
• River Bend Elementary
• Ross Elementary
• Shenandoah Valley Elementary
• Sorrento Springs Elementary
• Wren Hollow Elementary
• Central Middle
• Northeast Middle
• South Middle
• Southwest Middle
• West Middle
• Central High
• Fern Ridge High
• Early Childhood Center
• Alumni Association

Higher Expectations. Brighter Futures.

Page Navigation

• 5th Grade Home
• Clever (Parkway Apps)
• Leader In Me Parent Guide
• Social Studies
• MAP Practice
• 5th Grade Schedule
• 5th Grade Curriculum Information

Math Homework Pages and Answers

Topic 1: understand place value.

1-1: Patterns with Exponents and Powers of 10

• Homework Page

1-2: Understand Whole-Number Place Value

1-3: Decimals to Thousandths

1-4: Understand Decimal Place Value

1-5: Compare Decimals

1-6: Round Decimals

Topic 2: Use Models and Strategies to Add and Subtract Decimals

2-2: Estimate Sums and Differences of Decimals

2-3: Use Models to Add and Subtract Decimals

2-4: Use Strategies to Add Decimals

2-5: Use Strategies to Subtract Decimals

2-6: Model with Math

Topic 3: Fluently Multiply Multi-Digit Whole Numbers

3-1: Multiply Greater Numbers by Powers of 10

3-2: Estimate Products

3-3: Multiply by 1-Digit Numbers

3-4: Multiply 2-Digit by 2-Digit Numbers

3-5: Multiply 3-Digit by 2-Digit Numbers

3-6: Multiply Whole Numbers with Zeros

3-7: Practice Multiplying Multi-Digit Numbers

3-8: Solve Word Problems

3-9: Critique Reasoning

Topic 4: Use Models and Strategies to Multiply Decimals

4-1:Multiply Decimals by Powers of 10

4-2: Estimate the Product of a Decimal and a Whole Number 

4-3: Use Models to Multiply a Decimal and a Whole Number

4-4: Multiply a Decimal and a Whole Number

4-5: Use Models to Multiply a Decimal and a Decimal

4-6: Multiply Decimals Using Partial Products

4-7: Use Properties to Multiply Decimals

4-8: Use Number Sense to Multiply Decimals

4-9: Model with Math

Topic 5: Use Models and Strategies to Divide Whole Numbers

Topic 5-1: Use Patterns and Mental Math to Divide

Topic 5-2: Estimate Quotients with 2-Digit Divisors

Topic 5-3: Use Models and Properties to Divide with 2-Digit Divisors

Topic 5-4: Use Partial Quotients to Divide

Topic 5-5: Use Sharing to Divide: Two Digit Divisors

Topic 5-6: Use Sharing to Divide: Greater Dividends

Topic 5-7: Choose a Strategy to Divide 

Lesson 5-8: Make Sense and Persevere

Topic 6: Use Models and Strategies to Divide Decimals

6-1: Patterns for Dividing with Decimals

6-2: Estimate Decimals Quotients

6-3: Use Models to Divide by a 1-Digit Number

6-4: Divide by a 2-digit Whole Number

6-5: Divide by a Decimal

6-6: Reasoning 

Topic 7: Use Equivalent Fractions to Add and Subtract Fractions

7-2: Find Common Denominators

•   Answers

7-3: Add Fractions with Unlike Denominators

7-4: Subtract Fractions with Unlike Denominators

7-5: Add and Subtract Fractions

7-6: Estimate Sums and Differences of Mixed Numbers

7-7: Use Models to Add Mixed Numbers

7-8: Add Mixed Numbers

7-9: Use Models to Subtract Mixed Numbers

7-10: Subtract Mixed Numbers

7-11: Add and Subtract Mixed Numbers

Topic 8: Apply Understanding of Multiplication to Multiply Fractions

8-1: Multiply a Fraction by a Whole Number

8-2: Multiply a Whole Number by a Fraction

8-3: Multiply Fractions and Whole Numbers

8-4: Use Models to Multiply Two Fractions

8-5: Multiply Two Fractions

8-6: Area of a Rectangle

8-7: Multiply Mixed Numbers

Topic 9: Apply Understanding of Division to Divide Fractions

Lesson 9-1: Fractions and Division

Lesson 9-2: Fractions and Mixed Numbers as Quotients

Lesson 9-3: Use Multiplication to Divide

Lesson 9-4: Divide Whole Numbers by Unit Fractions

Lesson 9-5: Divide Unit Fractions by Non-Zero Whole Numbers

Lesson 9-6: Divide Whole Numbers and Unit Fractions

Lesson 9-7: Solve Problems Using Division

Lesson 9-8: Repeated Reasoning

Topic 10: Represent and Interpret Data

Lesson 10-1: Analyze Line Plots

Lesson 10-2: Make Line Plots

Lesson 10-3: Solve Word Problems Using Measurement Data

Lesson 10-4: Critique Reasoning 

Topic 11: Understand Volume Concepts

Lesson 11-1: Model Volume

Lesson 11-2: Develop a Formula

Lesson 11-3: Combine Volume of Prisms

Lesson 11-4: Solve Word Problems Using Volume

Lesson 11-5: Use Appropriate Tools

5th Grade Homework Policy

We value your family time. therefore, we will be intentional with any homework we send home. students’ daily homework will be required reading of at least 30 minutes., students will have nightly math homework which supports our learning in class. there are a lot of new math concepts in 5th grade and it is important for students' growth and understanding. additionally, study guides and other assignments may be sent home periodically throughout the year., please note: if a student exhibits off-task behaviors, fails to complete an assignment, or is struggling to understand a concept, an assignment will be sent home for completion..

• Questions or Feedback? |
• Web Community Manager Privacy Policy (Updated) |

• Texas Go Math
• Big Ideas Math
• Engageny Math
• McGraw Hill My Math
• enVision Math
• 180 Days of Math
• Math in Focus Answer Key
• Math Expressions Answer Key
• Privacy Policy

Eureka Math Grade 5 Module 3 Lesson 5 Answer Key

Engage ny eureka math 5th grade module 3 lesson 5 answer key, eureka math grade 5 module 3 lesson 5 sprint answer key.

Question 1. 4 – \(\frac{1}{2}\) = Answer: 4 – \(\frac{1}{2}\) = 3\(\frac{1}{2}\) Explanation : 4 – \(\frac{1}{2}\) = \(\frac{8}{2}\) – \(\frac{1}{2}\) = \(\frac{7}{2}\) = 3\(\frac{1}{2}\)

Question 2. 3 – \(\frac{1}{2}\) = Answer: 3 – \(\frac{1}{2}\) = 2\(\frac{1}{2}\) Explanation : 3 – \(\frac{1}{2}\) = \(\frac{6}{2}\) – \(\frac{1}{2}\) = \(\frac{5}{2}\) = 2\(\frac{1}{2}\)

Question 3. 2 – \(\frac{1}{2}\) = Answer: 2 – \(\frac{1}{2}\) = 1\(\frac{1}{2}\) Explanation : 2 – \(\frac{1}{2}\) = \(\frac{4}{2}\) – \(\frac{1}{2}\) = \(\frac{3}{2}\) = 1\(\frac{1}{2}\)

Question 4. 1 – \(\frac{1}{2}\) = Answer: 1 – \(\frac{1}{2}\) = \(\frac{1}{2}\) Explanation : 1 – \(\frac{1}{2}\) = \(\frac{2}{2}\) – \(\frac{1}{2}\) = \(\frac{1}{2}\)

Question 5. 1 – \(\frac{1}{3}\) = Answer: 1 – \(\frac{1}{3}\) = \(\frac{2}{3}\) Explanation : 1 – \(\frac{1}{3}\) = \(\frac{3}{3}\) – \(\frac{1}{3}\) = \(\frac{2}{3}\)

Question 6. 2 – \(\frac{1}{3}\) = Answer: 2 – \(\frac{1}{3}\) = 1\(\frac{2}{3}\) Explanation : 2 – \(\frac{1}{3}\) = \(\frac{6}{3}\) – \(\frac{1}{3}\) = \(\frac{5}{3}\) = 1\(\frac{2}{3}\)

Question 7. 4 – \(\frac{1}{3}\) = Answer: 4 – \(\frac{1}{3}\) = 3\(\frac{2}{3}\) Explanation : 4 – \(\frac{1}{3}\) = \(\frac{12}{3}\) – \(\frac{1}{3}\) = \(\frac{11}{3}\) = 3\(\frac{2}{3}\)

Question 8. 4 – \(\frac{2}{3}\) = Answer: 4 – \(\frac{2}{3}\) = 3\(\frac{1}{3}\) Explanation : 4 – \(\frac{2}{3}\) = \(\frac{12}{3}\) – \(\frac{2}{3}\) = \(\frac{10}{3}\) = 3\(\frac{1}{3}\)

Question 9. 2 – \(\frac{2}{3}\) = Answer: 2 – \(\frac{1}{3}\) = 1\(\frac{2}{3}\) Explanation : 2 – \(\frac{1}{3}\) = \(\frac{6}{3}\) – \(\frac{1}{3}\) = \(\frac{5}{3}\) = 1\(\frac{2}{3}\)

Question 10. 2 – \(\frac{1}{4}\) = Answer: 2 – \(\frac{1}{4}\) = 1\(\frac{3}{4}\) Explanation : 2 – \(\frac{1}{4}\) = \(\frac{8}{4}\) – \(\frac{1}{4}\) = \(\frac{7}{4}\) = 1\(\frac{3}{4}\)

Question 11. 2 – \(\frac{3}{4}\) = Answer: 2 – \(\frac{3}{4}\) = 1\(\frac{1}{4}\) Explanation : 2 – \(\frac{3}{4}\) = \(\frac{8}{4}\) – \(\frac{3}{4}\) = \(\frac{5}{4}\) = 1\(\frac{1}{4}\)

Question 12. 3 – \(\frac{3}{4}\) = Answer: 3 – \(\frac{3}{4}\) = 2\(\frac{1}{4}\) Explanation : 3 – \(\frac{3}{4}\) = \(\frac{12}{4}\) – \(\frac{3}{4}\) = \(\frac{9}{4}\) = 2\(\frac{1}{4}\)

Question 13. 3 – \(\frac{1}{4}\) = Answer: 3 – \(\frac{1}{4}\) = 2\(\frac{3}{4}\) Explanation : 3 – \(\frac{1}{4}\) = \(\frac{12}{4}\) – \(\frac{1}{4}\) = \(\frac{11}{4}\) = 2\(\frac{3}{4}\)

Question 14. 4 – \(\frac{3}{4}\) = Answer: 4 – \(\frac{3}{4}\) = 3\(\frac{1}{4}\) Explanation : 4 – \(\frac{3}{4}\) = \(\frac{16}{4}\) – \(\frac{3}{4}\) = \(\frac{13}{4}\) = 3\(\frac{1}{4}\)

Question 15. 2 – \(\frac{1}{10}\) = Answer: 2 – \(\frac{1}{10}\) = 1\(\frac{9}{10}\) Explanation : 2 – \(\frac{1}{10}\) = \(\frac{20}{10}\) – \(\frac{1}{10}\) = \(\frac{19}{10}\) = 1\(\frac{9}{10}\)

Question 16. 3 – \(\frac{9}{10}\) = Answer: 3 – \(\frac{9}{10}\) = 2\(\frac{1}{10}\) Explanation : 3 – \(\frac{9}{10}\) = \(\frac{30}{10}\) – \(\frac{9}{10}\) = \(\frac{21}{10}\) = 2\(\frac{1}{10}\)

Question 17. 2 – \(\frac{7}{10}\) = Answer: Answer: 2 – \(\frac{7}{10}\) = 1\(\frac{3}{10}\) Explanation : 2 – \(\frac{7}{10}\) = \(\frac{20}{10}\) – \(\frac{7}{10}\) = \(\frac{13}{10}\) = 1\(\frac{3}{10}\)

Question 18. 4 – \(\frac{3}{10}\) = Answer: 4 – \(\frac{1}{10}\) = 3\(\frac{9}{10}\) Explanation : 4 – \(\frac{1}{10}\) = \(\frac{40}{10}\) – \(\frac{1}{10}\) = \(\frac{39}{10}\) = 3\(\frac{9}{10}\)

Question 19. 3 – \(\frac{1}{5}\) = Answer: 3 – \(\frac{1}{5}\) = 2\(\frac{4}{5}\) Explanation : 3 – \(\frac{1}{5}\) = \(\frac{15}{5}\) – \(\frac{1}{5}\) = \(\frac{14}{5}\) = 2\(\frac{4}{5}\)

Question 20. 3 – \(\frac{2}{5}\) = Answer: 3 – \(\frac{2}{5}\) = 2\(\frac{3}{5}\) Explanation : 3 – \(\frac{2}{5}\) = \(\frac{15}{5}\) – \(\frac{2}{5}\) = \(\frac{13}{5}\) = 2\(\frac{3}{5}\)

Question 21. 3 – \(\frac{4}{5}\) = Answer: 3 – \(\frac{4}{5}\) = 2\(\frac{1}{5}\) Explanation : 3 – \(\frac{4}{5}\) = \(\frac{15}{5}\) – \(\frac{4}{5}\) = \(\frac{11}{5}\) = 2\(\frac{1}{5}\)

Question 22. 3 – \(\frac{3}{5}\) = Answer: 3 – \(\frac{3}{5}\) = 2\(\frac{2}{5}\) Explanation : 3 – \(\frac{3}{5}\) = \(\frac{15}{5}\) – \(\frac{3}{5}\) = \(\frac{12}{5}\) = 2\(\frac{2}{5}\)

Question 23. 3 – \(\frac{1}{8}\) = Answer: 3 – \(\frac{1}{8}\) = 2\(\frac{7}{8}\) Explanation : 3 – \(\frac{1}{8}\) = \(\frac{24}{8}\) – \(\frac{1}{8}\) = \(\frac{23}{8}\) = 2\(\frac{7}{8}\)

Question 24. 3 – \(\frac{3}{8}\) = Answer: 3 – \(\frac{3}{8}\) = 2\(\frac{5}{8}\) Explanation : 3 – \(\frac{3}{8}\) = \(\frac{24}{8}\) – \(\frac{3}{8}\) = \(\frac{21}{8}\) = 2\(\frac{5}{8}\)

Question 25. 3 – \(\frac{5}{8}\) = Answer: 3 – \(\frac{5}{8}\) = 2\(\frac{3}{8}\) Explanation : 3 – \(\frac{5}{8}\) = \(\frac{24}{8}\) – \(\frac{5}{8}\) = \(\frac{19}{8}\) = 2\(\frac{3}{8}\)

Question 26. 3 – \(\frac{7}{8}\) = Answer: 3 – \(\frac{7}{8}\) = 2\(\frac{1}{8}\) Explanation : 3 – \(\frac{7}{8}\) = \(\frac{24}{8}\) – \(\frac{7}{8}\) = \(\frac{17}{8}\) = 2\(\frac{1}{8}\)

Question 27. 2 – \(\frac{7}{8}\) = Answer: 2 – \(\frac{7}{8}\) = 1\(\frac{1}{8}\) Explanation : 2 – \(\frac{7}{8}\) = \(\frac{16}{8}\) – \(\frac{7}{8}\) = \(\frac{9}{8}\) = 1\(\frac{1}{8}\)

Question 28. 4 – \(\frac{1}{7}\) = Answer: 4 – \(\frac{1}{7}\) = 3\(\frac{6}{7}\) Explanation : 4 – \(\frac{1}{7}\) = \(\frac{28}{7}\) – \(\frac{1}{7}\) = \(\frac{27}{7}\) = 3\(\frac{6}{7}\)

Question 29. 3 – \(\frac{6}{7}\) = Answer: 3 – \(\frac{6}{7}\) = 2\(\frac{1}{7}\) Explanation : 3 – \(\frac{6}{7}\) = \(\frac{21}{7}\) – \(\frac{6}{7}\) = \(\frac{15}{7}\) = 2\(\frac{1}{7}\)

Question 30. 2 – \(\frac{3}{7}\) = Answer: 2 – \(\frac{3}{7}\) = Answer: 2 – \(\frac{3}{7}\) = 1\(\frac{4}{7}\) Explanation : 2 – \(\frac{3}{7}\) = \(\frac{14}{7}\) – \(\frac{3}{7}\) = \(\frac{11}{7}\) = 1\(\frac{4}{7}\)

Question 31. 4 – \(\frac{4}{7}\) = Answer: 4 – \(\frac{4}{7}\) = Answer: 4 – \(\frac{4}{7}\) = 3\(\frac{3}{7}\) Explanation : 4 – \(\frac{4}{7}\) = \(\frac{28}{7}\) – \(\frac{4}{7}\) = \(\frac{24}{7}\) = 3\(\frac{3}{7}\)

Question 32. 3 – \(\frac{5}{7}\) = Answer: 3 – \(\frac{5}{7}\) = 2\(\frac{2}{7}\) Explanation : 3 – \(\frac{5}{7}\) = \(\frac{21}{7}\) – \(\frac{5}{7}\) = \(\frac{16}{7}\) = 2\(\frac{2}{7}\)

Question 33. 4 – \(\frac{3}{4}\) = Answer: 4 – \(\frac{3}{4}\) = 3\(\frac{1}{4}\) Explanation : 4 – \(\frac{3}{4}\) = \(\frac{16}{4}\) – \(\frac{3}{4}\) = \(\frac{13}{4}\) = 3\(\frac{1}{4}\)

Question 34. 2 – \(\frac{5}{8}\) = Answer: 2 – \(\frac{5}{8}\) = 1\(\frac{3}{8}\) Explanation : 2 – \(\frac{5}{8}\) = \(\frac{16}{8}\) – \(\frac{5}{8}\) = \(\frac{11}{8}\) = 1\(\frac{3}{8}\)

Question 35. 3 – \(\frac{3}{10}\) = Answer: 3 – \(\frac{3}{10}\) = 2\(\frac{7}{10}\) Explanation : 3 – \(\frac{3}{10}\) = \(\frac{30}{10}\) – \(\frac{3}{10}\) = \(\frac{27}{10}\) = 2\(\frac{7}{10}\)

Question 36. 4 – \(\frac{2}{5}\) = Answer: 4 – \(\frac{2}{5}\) = 3\(\frac{3}{5}\) Explanation : 4 – \(\frac{2}{5}\) = \(\frac{20}{5}\) – \(\frac{2}{5}\) = \(\frac{18}{5}\) = 3\(\frac{3}{5}\)

Question 37. 4 – \(\frac{3}{7}\) = Answer: 4 – \(\frac{3}{7}\) = Answer: 4 – \(\frac{3}{7}\) = 3\(\frac{4}{7}\) Explanation : 4 – \(\frac{3}{7}\) = \(\frac{28}{7}\) – \(\frac{3}{7}\) = \(\frac{25}{7}\) = 3\(\frac{4}{7}\)

Question 38. 3 – \(\frac{7}{10}\) = Answer: 3 – \(\frac{7}{10}\) = 2\(\frac{3}{10}\) Explanation : 3 – \(\frac{7}{10}\) = \(\frac{30}{10}\) – \(\frac{7}{10}\) = \(\frac{23}{10}\) = 2\(\frac{3}{10}\)

Question 39. 3 – \(\frac{5}{10}\) = Answer: 3 – \(\frac{5}{10}\) = 2\(\frac{5}{10}\) Explanation : 3 – \(\frac{5}{10}\) = \(\frac{30}{10}\) – \(\frac{5}{10}\) = \(\frac{25}{10}\) = 2\(\frac{5}{10}\)

Question 40. 4 – \(\frac{2}{8}\) = Answer: 4 – \(\frac{2}{8}\) = 3\(\frac{6}{8}\) Explanation : 4 – \(\frac{2}{8}\) = \(\frac{32}{8}\) – \(\frac{2}{8}\) = \(\frac{30}{8}\) = 3\(\frac{6}{8}\)

Question 41. 2 – \(\frac{9}{12}\) = Answer: 2 – \(\frac{9}{12}\) = 2 – \(\frac{3}{4}\) = 1\(\frac{1}{4}\) Explanation : 2 – \(\frac{3}{4}\) = \(\frac{8}{4}\) – \(\frac{3}{4}\) = \(\frac{5}{4}\) = 1\(\frac{1}{4}\)

Question 42. 4 – \(\frac{2}{12}\) = 3\(\frac{5}{6}\) Answer: 4 – \(\frac{2}{12}\) = 4 – \(\frac{1}{6}\) = 3\(\frac{5}{6}\) Explanation : 4 – \(\frac{1}{6}\) = \(\frac{24}{6}\) – \(\frac{1}{6}\) = \(\frac{23}{6}\) = 3\(\frac{5}{6}\)

Question 43. 3 – \(\frac{2}{6}\) = Answer: 3 – \(\frac{2}{6}\) = 3 – \(\frac{1}{3}\) = 2\(\frac{2}{3}\) Explanation : 3 – \(\frac{1}{3}\) = \(\frac{9}{3}\) – \(\frac{1}{3}\) = \(\frac{8}{3}\) = 2\(\frac{2}{3}\)

Question 44. 2 – \(\frac{8}{12}\) = Answer: 2 – \(\frac{8}{12}\) = 2 – \(\frac{2}{3}\) = 1\(\frac{1}{3}\) Explanation : 2 – \(\frac{2}{3}\) = \(\frac{6}{3}\) – \(\frac{2}{3}\) = \(\frac{4}{3}\) = 2\(\frac{1}{3}\)

Question 1. 1 – \(\frac{1}{2}\) = Answer: 1 – \(\frac{1}{2}\) = \(\frac{1}{2}\) Explanation : 1 – \(\frac{1}{2}\) = \(\frac{2}{2}\) – \(\frac{1}{2}\) = \(\frac{1}{2}\)

Question 2. 2 – \(\frac{1}{2}\) = Answer: 2 – \(\frac{1}{2}\) = 1\(\frac{1}{2}\) Explanation : 2 – \(\frac{1}{2}\) = \(\frac{4}{2}\) – \(\frac{1}{2}\) = \(\frac{3}{2}\) = 1\(\frac{1}{2}\)

Question 3. 3 – \(\frac{1}{2}\) = Answer: 3 – \(\frac{1}{2}\) = 2\(\frac{1}{2}\) Explanation : 3 – \(\frac{1}{2}\) = \(\frac{6}{2}\) – \(\frac{1}{2}\) = \(\frac{5}{2}\) = 2\(\frac{1}{2}\)

Question 4. 4 – \(\frac{1}{2}\) = Answer: 4 – \(\frac{1}{2}\) = 3\(\frac{1}{2}\) Explanation : 4 – \(\frac{1}{2}\) = \(\frac{8}{2}\) – \(\frac{1}{2}\) = \(\frac{7}{2}\) = 3\(\frac{1}{2}\)

Question 5. 1 – \(\frac{1}{4}\) = Answer: 1 – \(\frac{1}{4}\) = \(\frac{3}{4}\) Explanation : 1 – \(\frac{1}{4}\) = \(\frac{4}{4}\) – \(\frac{1}{4}\) = \(\frac{3}{4}\)

Question 6. 2 – \(\frac{1}{4}\) = Answer: 2 – \(\frac{1}{4}\) = 1\(\frac{3}{4}\) Explanation : 2 – \(\frac{1}{4}\) = \(\frac{8}{4}\) – \(\frac{1}{4}\) = \(\frac{7}{4}\) = 1\(\frac{3}{4}\)

Question 7. 4 – \(\frac{1}{4}\) = Answer: 4 – \(\frac{1}{4}\) = 3\(\frac{3}{4}\) Explanation : 4 – \(\frac{1}{4}\) = \(\frac{16}{4}\) – \(\frac{1}{4}\) = \(\frac{15}{4}\) = 3\(\frac{3}{4}\)

Question 8. 4 – \(\frac{3}{4}\) = Answer: 4 – \(\frac{3}{4}\) = 3\(\frac{1}{4}\) Explanation : 4 – \(\frac{3}{4}\) = \(\frac{16}{4}\) – \(\frac{3}{4}\) = \(\frac{13}{4}\) = 3\(\frac{1}{4}\)

Question 9. 2 – \(\frac{3}{4}\) = Answer: 2 – \(\frac{3}{4}\) = 1\(\frac{1}{4}\) Explanation : 2 – \(\frac{3}{4}\) = \(\frac{8}{4}\) – \(\frac{3}{4}\) = \(\frac{5}{4}\) = 1\(\frac{1}{4}\)

Question 10. 2 – \(\frac{1}{3}\) = Answer: 2 – \(\frac{1}{3}\) = 1\(\frac{2}{3}\) Explanation : 2 – \(\frac{1}{3}\) = \(\frac{6}{3}\) – \(\frac{1}{3}\) = \(\frac{5}{3}\) = 1\(\frac{2}{3}\)

Question 11. 2 – \(\frac{2}{3}\) = Answer: 2 – \(\frac{2}{3}\) = 1\(\frac{1}{3}\) Explanation : 2 – \(\frac{2}{3}\) = \(\frac{6}{3}\) – \(\frac{2}{3}\) = \(\frac{4}{3}\) = 1\(\frac{1}{3}\)

Question 12. 3 – \(\frac{2}{3}\) = Answer: 3 – \(\frac{2}{3}\) = 2\(\frac{1}{3}\) Explanation : 3 – \(\frac{2}{3}\) = \(\frac{9}{3}\) – \(\frac{2}{3}\) = \(\frac{7}{3}\) = 2\(\frac{1}{3}\)

Question 13. 3 – \(\frac{1}{3}\) = Answer: 3 – \(\frac{1}{3}\) = 2\(\frac{2}{3}\) Explanation : 3 – \(\frac{1}{3}\) = \(\frac{9}{3}\) – \(\frac{1}{3}\) = \(\frac{8}{3}\) = 2\(\frac{2}{3}\)

Question 14. 4 – \(\frac{2}{3}\) = Answer: 4 – \(\frac{2}{3}\) = 3\(\frac{1}{3}\) Explanation : 4 – \(\frac{2}{3}\) = \(\frac{12}{3}\) – \(\frac{2}{3}\) = \(\frac{10}{3}\) = 3\(\frac{1}{3}\)

Question 15. 3 – \(\frac{1}{10}\) = Answer: 3 – \(\frac{1}{10}\) = 2\(\frac{9}{10}\) Explanation : 3 – \(\frac{1}{10}\) = \(\frac{30}{10}\) – \(\frac{9}{10}\) = \(\frac{21}{10}\) = 2\(\frac{1}{10}\)

Question 16. 2 – \(\frac{9}{10}\) = Answer: 2 – \(\frac{9}{10}\) = 1\(\frac{1}{10}\) Explanation : 2 – \(\frac{9}{10}\) = \(\frac{20}{10}\) – \(\frac{9}{10}\) = \(\frac{11}{10}\) = 1\(\frac{1}{10}\)

Question 17. 4 – \(\frac{7}{10}\) = Answer: 4 – \(\frac{7}{10}\) = 3\(\frac{3}{10}\) Explanation : 4 – \(\frac{7}{10}\) = \(\frac{40}{10}\) – \(\frac{7}{10}\) = \(\frac{33}{10}\) = 3\(\frac{3}{10}\)

Question 18. 3 – \(\frac{3}{10}\) = Answer: 3 – \(\frac{3}{10}\) = 2\(\frac{7}{10}\) Explanation : 3 – \(\frac{3}{10}\) = \(\frac{30}{10}\) – \(\frac{3}{10}\) = \(\frac{27}{10}\) = 2\(\frac{7}{10}\)

Question 19. 2 – \(\frac{1}{5}\) = Answer: 2 – \(\frac{1}{5}\) = 1\(\frac{4}{5}\) Explanation : 2 – \(\frac{1}{5}\) = \(\frac{10}{5}\) – \(\frac{1}{5}\) = \(\frac{9}{5}\) = 1\(\frac{4}{5}\)

Question 20. 2 – \(\frac{2}{5}\) = Answer: 2 – \(\frac{2}{5}\) = 1\(\frac{3}{5}\) Explanation : 2 – \(\frac{2}{5}\) = \(\frac{10}{5}\) – \(\frac{2}{5}\) = \(\frac{8}{5}\) = 1\(\frac{3}{5}\)

Question 21. 2 – \(\frac{4}{5}\) = Answer: 2 – \(\frac{4}{5}\) = 1\(\frac{1}{5}\) Explanation : 2 – \(\frac{1}{5}\) = \(\frac{10}{5}\) – \(\frac{4}{5}\) = \(\frac{6}{5}\) = 1\(\frac{1}{5}\)

Question 23. 2 – \(\frac{1}{8}\) = Answer: 2 – \(\frac{1}{8}\) = 1\(\frac{7}{8}\) Explanation : 2 – \(\frac{1}{8}\) = \(\frac{16}{8}\) – \(\frac{1}{8}\) = \(\frac{15}{8}\) = 1\(\frac{7}{8}\)

Question 24. 2 – \(\frac{3}{8}\) = Answer: 2 – \(\frac{3}{8}\) = 1\(\frac{5}{8}\) Explanation : 2 – \(\frac{3}{8}\) = \(\frac{16}{8}\) – \(\frac{3}{8}\) = \(\frac{13}{8}\) = 1\(\frac{4}{8}\)

Question 25. 2 – \(\frac{5}{8}\) = Answer: 2 – \(\frac{5}{8}\) = 1\(\frac{3}{8}\) Explanation : 2 – \(\frac{5}{8}\) = \(\frac{16}{8}\) – \(\frac{5}{8}\) = \(\frac{11}{8}\) = 1\(\frac{3}{8}\)

Question 26. 2 – \(\frac{7}{8}\) = Answer: 2 – \(\frac{7}{8}\) = 1\(\frac{1}{8}\) Explanation : 2 – \(\frac{7}{8}\) = \(\frac{16}{8}\) – \(\frac{7}{8}\) = \(\frac{9}{8}\) = 1\(\frac{1}{8}\)

Question 27. 4 – \(\frac{7}{8}\) = Answer: 4 – \(\frac{7}{8}\) = 3\(\frac{1}{8}\) Explanation : 4 – \(\frac{7}{8}\) = \(\frac{32}{8}\) – \(\frac{3}{8}\) = \(\frac{13}{8}\) = 1\(\frac{4}{8}\)

Question 28. 3 – \(\frac{1}{7}\) = Answer: 3 – \(\frac{1}{7}\) = 2\(\frac{6}{7}\) Explanation : 3 – \(\frac{1}{7}\) = \(\frac{21}{7}\) – \(\frac{1}{7}\) = \(\frac{20}{7}\) = 2\(\frac{6}{7}\)

Question 29. 2 – \(\frac{6}{7}\) = Answer: 2 – \(\frac{6}{7}\) = 1\(\frac{1}{7}\) Explanation : 2 – \(\frac{6}{7}\) = \(\frac{14}{7}\) – \(\frac{6}{7}\) = \(\frac{8}{7}\) = 1\(\frac{1}{7}\)

Question 30. 4 – \(\frac{3}{7}\) = Answer: 4 – \(\frac{3}{7}\) = 3\(\frac{4}{7}\) Explanation : 4 – \(\frac{3}{7}\) = \(\frac{28}{7}\) – \(\frac{3}{7}\) = \(\frac{25}{7}\) = 3\(\frac{4}{7}\)

Question 31. 3 – \(\frac{4}{7}\) = Answer: 3 – \(\frac{4}{7}\) = 2\(\frac{3}{7}\) Explanation : 3 – \(\frac{4}{7}\) = \(\frac{21}{7}\) – \(\frac{4}{7}\) = \(\frac{17}{7}\) = 2\(\frac{3}{7}\)

Question 32. 2 – \(\frac{5}{7}\) = Answer: 2 – \(\frac{5}{7}\) = 1\(\frac{2}{7}\) Explanation : 2 – \(\frac{5}{7}\) = \(\frac{14}{7}\) – \(\frac{5}{7}\) = \(\frac{9}{7}\) = 1\(\frac{2}{7}\)

Question 33. 3 – \(\frac{3}{4}\) = Answer: 3 – \(\frac{3}{4}\) = 2\(\frac{1}{4}\) Explanation : 3 – \(\frac{3}{4}\) = \(\frac{12}{4}\) – \(\frac{3}{4}\) = \(\frac{9}{4}\) = 2\(\frac{1}{4}\)

Question 34. 4 – \(\frac{5}{8}\) = Answer: 4 – \(\frac{5}{8}\) = 3\(\frac{3}{8}\) Explanation : 4 – \(\frac{5}{8}\) = \(\frac{32}{8}\) – \(\frac{5}{8}\) = \(\frac{27}{8}\) = 3\(\frac{3}{8}\)

Question 35. 2 – \(\frac{3}{10}\) = Answer: 2 – \(\frac{3}{10}\) = 1\(\frac{7}{10}\) Explanation : 2 – \(\frac{3}{10}\) = \(\frac{20}{10}\) – \(\frac{3}{10}\) = \(\frac{17}{10}\) = 1\(\frac{7}{10}\)

Question 36. 3 – \(\frac{2}{5}\) = Answer: 3 – \(\frac{2}{5}\) = 2\(\frac{3}{5}\) Explanation : 3 – \(\frac{2}{5}\) = \(\frac{15}{5}\) – \(\frac{2}{5}\) = \(\frac{13}{5}\) = 2\(\frac{3}{5}\)

Question 37. 3 – \(\frac{3}{7}\) = Answer: 3 – \(\frac{3}{7}\) = 2\(\frac{4}{7}\) Explanation : 3 – \(\frac{3}{7}\) = \(\frac{21}{7}\) – \(\frac{3}{7}\) = \(\frac{18}{7}\) = 2\(\frac{4}{7}\)

Question 38. 2 – \(\frac{7}{10}\) = Answer: 2 – \(\frac{7}{10}\) = 1\(\frac{3}{10}\) Explanation : 2 – \(\frac{7}{10}\) = \(\frac{20}{10}\) – \(\frac{7}{10}\) = \(\frac{13}{10}\) = 1\(\frac{3}{10}\)

Question 39. 2 – \(\frac{5}{10}\) = Answer: 2 – \(\frac{5}{10}\) = 1\(\frac{1}{2}\) Explanation : 2 – \(\frac{5}{10}\) = \(\frac{20}{10}\) – \(\frac{5}{10}\) = \(\frac{15}{10}\) = \(\frac{3}{2}\) = 1\(\frac{1}{2}\)

Question 40. 3 – \(\frac{6}{8}\) = Answer: 3 – \(\frac{6}{8}\) = 2\(\frac{1}{4}\) Explanation : 3 – \(\frac{6}{8}\) = \(\frac{24}{8}\) – \(\frac{6}{8}\) = \(\frac{18}{8}\) = 2\(\frac{1}{4}\)

Question 41. 4 – \(\frac{3}{12}\) = Answer: 4 – \(\frac{3}{12}\) = 4 – \(\frac{1}{4}\) = 3\(\frac{3}{4}\) Explanation : 4 – \(\frac{1}{4}\) = \(\frac{16}{4}\) – \(\frac{1}{4}\) = \(\frac{15}{4}\) = 3\(\frac{3}{4}\)

Question 42. 3 – \(\frac{10}{12}\) = Answer: 3 – \(\frac{10}{12}\) = 3 – \(\frac{5}{6}\) = 2\(\frac{1}{6}\) Explanation : 3 – \(\frac{5}{6}\) = \(\frac{18}{6}\) – \(\frac{5}{6}\) = \(\frac{13}{6}\) = 2\(\frac{1}{6}\)

Question 43. 2 – \(\frac{4}{6}\) = Answer: 2 – \(\frac{4}{6}\) = 2 – \(\frac{2}{3}\) = 1\(\frac{1}{3}\) Explanation : 2 – \(\frac{2}{3}\) = \(\frac{6}{3}\) – \(\frac{2}{3}\) = \(\frac{4}{3}\) = 1\(\frac{1}{3}\)

Question 44. 4 – \(\frac{4}{12}\) = Answer: 4 – \(\frac{4}{12}\) = 4 – \(\frac{1}{3}\) = 3\(\frac{2}{3}\) Explanation : 4 – \(\frac{1}{3}\) = \(\frac{12}{3}\) – \(\frac{1}{3}\) = \(\frac{11}{3}\) = 3\(\frac{2}{3}\)

Eureka Math Grade 5 Module 3 Lesson 5 Problem Set Answer Key

Question 2. Mr. Penman had \(\frac{2}{3}\) liter of salt water. He used \(\frac{1}{5}\) of a liter for an experiment. How much salt water does Mr. Penman have left? Answer: Quantity of salt water = \(\frac{2}{3}\) Quantity of salt water used = \(\frac{1}{5}\) Quantity of salt water left = \(\frac{2}{3}\) – \(\frac{1}{5}\) = \(\frac{10}{15}\) – \(\frac{3}{15}\) = \(\frac{7}{15}\) .

Eureka Math Grade 5 Module 3 Lesson 5 Exit Ticket Answer Key

Eureka Math Grade 5 Module 3 Lesson 5 Homework Answer Key

Question 3. Robin used \(\frac{1}{4}\) of a pound of butter to make a cake. Before she started, she had \(\frac{7}{8}\) of a pound of butter. How much butter did Robin have when she was done baking? Give your answer as a fraction of a pound. Answer: Quantity of butter used to make cake = \(\frac{1}{4}\)  pound Quantity of butter with Robin before baking cake = \(\frac{7}{8}\)  pound . Total Quantity of butter with Robin after baking = \(\frac{7}{8}\)  – \(\frac{1}{4}\) pound  = \(\frac{7}{8}\)  – \(\frac{2}{8}\) = \(\frac{5}{8}\) pound Therefore, Robin have \(\frac{5}{8}\) pound  when she was done baking .

Question 4. Katrina needs \(\frac{3}{5}\) kilogram of flour for a recipe. Her mother has \(\frac{3}{7}\) kilogram of flour in her pantry. Is this enough flour for the recipe? If not, how much more will she need? Answer: Quantity of Flour Required for Recipe = \(\frac{3}{5}\) Quantity of Flour with her mother = \(\frac{3}{7}\) Quantity of Flour Enough or not = \(\frac{3}{7}\) – \(\frac{3}{5}\)  = \(\frac{15}{35}\) – \(\frac{21}{35}\) = – \(\frac{6}{35}\) that means negative indicate doenot enough. She needs more \(\frac{6}{35}\) Quantity of Flour for the Recipe .

Leave a Comment Cancel Reply

You must be logged in to post a comment.

• Texas Go Math
• Big Ideas Math
• enVision Math
• EngageNY Math
• McGraw Hill My Math
• 180 Days of Math
• Math in Focus Answer Key
• Math Expressions Answer Key
• Privacy Policy

Texas Go Math Grade 5 Lesson 5.3 Answer Key Estimate Fraction Sums and Differences

Refer to our Texas Go Math Grade 5 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 5 Lesson 5.3 Answer Key Estimate Fraction Sums and Differences.

Unlock the Problem

Kimberly will be riding her bike to school this year. The distance from her house to the end of the Street is \(\frac{1}{62}\)mile. The distance from the end of the Street to the school is \(\frac{3}{8}\) mile. About how far is Kimberly’s house from school?

You can use benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

STEP 3: Add the rounded fractions.

Another Way

Use mental math. You can compare the numerator and the denominator to round a fraction and find a reasonable estimate.

Estimate. \(\frac{9}{10}\) – \(\frac{5}{8}\) STEP 1: Round \(\frac{9}{10}\). Think: The numerator is about the same as the denominator. Round the fraction \(\frac{9}{10}\) to __________.

Remember A fraction with the same numerator and denominator, such as \(\frac{2}{2}, \frac{5}{5}, \frac{12}{12}\) or \(\frac{96}{96}\), is equal to 1.

STEP 2: Round \(\frac{5}{8}\) Think: The numerator is about half the denominator. Round the fraction \(\frac{5}{8}\) to ___________.

STEP 1: Round \(\frac{9}{10}\). Think: The numerator is about the same as the denominator. Round the fraction \(\frac{9}{10}\) to \(\frac{10}{10}\)

STEP 2: Round \(\frac{5}{8}\) Think: The numerator is about half the denominator. Round the fraction \(\frac{5}{8}\) to \(\frac{4}{8}\)

Math Talk Mathematical Processes

Explain another way you could use benchmarks to estimate \(\frac{9}{10}\) – \(\frac{5}{8}\). Answer: \(\frac{9}{10}\) – \(\frac{5}{8}\) = \(\frac{1}{6}\) \(\frac{1}{6}\) is very near to \(\frac{1}{5}\) Explanation: Used bench marks to find the sum

Share and Show

Estimate the sum or difference.

Question 1. \(\frac{5}{6}\) + \(\frac{3}{8}\) a. Round \(\frac{5}{6}\) to its closest benchmark. Answer:  \(\frac{6}{6}\)

b. Round \(\frac{3}{8}\) to its closest benchmark. Answer: \(\frac{4}{8}\)

c. Add to find the estimate.   \(\frac{6}{6}\) +\(\frac{4}{8}\)  = 1\(\frac{1}{2}\) Answer: 1\(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Go Math Lesson 5.3 5th Grade Answer Key Question 2. \(\frac{5}{9}\) – \(\frac{3}{8}\) Answer: a. Round \(\frac{5}{9}\) to its closest benchmark. Answer:  \(\frac{5}{9}\)

c. Add to find the estimate.   \(\frac{5}{9}\) – \(\frac{4}{8}\)  = 1\(\frac{1}{18}\) Answer: 1\(\frac{1}{18}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 3. \(\frac{5}{6}\) + \(\frac{2}{5}\) Answer: a. Round \(\frac{5}{6}\) to its closest benchmark. Answer:  \(\frac{6}{6}\)

b. Round \(\frac{2}{5}\) to its closest benchmark. Answer: \(\frac{2}{5}\)

c. Add to find the estimate.   \(\frac{6}{6}\) +\(\frac{2}{5}\)  = 1\(\frac{1}{2}\) Answer: 1\(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 4. \(\frac{9}{10}\) – \(\frac{1}{9}\) Answer: a. Round \(\frac{9}{10}\) to its closest benchmark. Answer:  \(\frac{10}{10}\)

b. Round \(\frac{1}{9}\) to its closest benchmark. Answer: \(\frac{0}{9}\)

c. Add to find the estimate.   \(\frac{10}{10}\) – \(\frac{0}{9}\)  = 1 Answer: 1 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Problem Solving

Lesson 5.3 Answer Key 5th Grade Go Math Question 5. How do you know whether your estimate for \(\frac{9}{10}\) + 3\(\frac{6}{7}\) would be greater than or less than the actual sum? Explain. Answer: Greater than the actual sum \(\frac{9}{10}\) + 3\(\frac{6}{7}\) = close to bench marks \(\frac{10}{10}\) + 3\(\frac{7}{7}\) =  4 Explanation: Is greater than the actual sum used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 6. Write Math Nick estimated that \(\frac{5}{8}\) + \(\frac{4}{7}\) is about 2. Explain how you know his estimate is not reasonable. Answer: \(\frac{5}{8}\) + \(\frac{4}{7}\) close to benchmarks \(\frac{4}{8}\) + \(\frac{4}{7}\) = 1 Explanation: Nick estimated that \(\frac{5}{8}\) + \(\frac{4}{7}\) is about 2. used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1. so, his estimation is wrong

Question 7. Lisa and Valerie are picnicking in Trough Creek State Park in Pennsylvania. Lisa has brought a salad that she made with \(\frac{3}{4}\) cup of strawberries, \(\frac{7}{8}\) cup of peaches, and \(\frac{1}{6}\) cup of blueberries. About how many total cups of fruit are in the salad? Answer: \(\frac{3}{4}\) + \(\frac{7}{8}\) + \(\frac{1}{6}\) very close to bench marks \(\frac{4}{4}\) + \(\frac{8}{8}\) + \(\frac{0}{6}\) =2 \(\frac{1}{2}\) Explanation: Lisa and Valerie are picnicking in Trough Creek State Park in Pennsylvania. Lisa has brought a salad that she made with \(\frac{3}{4}\) cup of strawberries, \(\frac{7}{8}\) cup of peaches, and \(\frac{1}{6}\) cup of blueberries. 2\(\frac{1}{2}\)   total cups of fruit are in the salad

Go Math 5th Grade Lesson 5.3 How to Estimate Fractions Question 9. H.O.T Explain how you know that \(\frac{5}{8}\) + \(\frac{6}{10}\) is greater than 1. Answer: No Explanation: Close to the bench marks \(\frac{8}{8}\) + \(\frac{5}{10}\) = 1 actual sum is greater than 1

Daily Assessment Task

Fill in the bubble completely to show your answer.

Question 10. Mia uses \(\frac{1}{5}\) of a bag of gravel in the morning and \(\frac{11}{12}\) of a bag in the afternoon. About how much gravel does she use in one day? (A) 0 bags (B) \(\frac{1}{2}\) bag (C) 1 bag (D) 2\(\frac{1}{2}\) bags Answer:  C \(\frac{1}{5}\) + \(\frac{11}{12}\) nearest benchmarks are \(\frac{0}{5}\) + \(\frac{12}{12}\)  = 1 Explanation: Mia uses \(\frac{1}{5}\) of a bag of gravel in the morning and \(\frac{11}{12}\) of a bag in the afternoon. she use 1 bag of gravel

Question 11. Evaluate Reasonableness Hector and Veronica are going hiking. They made a trail mix that has \(\frac{2}{3}\) cup of almonds, \(\frac{7}{8}\) cup of peanuts, and \(\frac{4}{5}\) cup of raisins in it. Hector estimates that they made about 3 cups of trail mix. Is the estimate greater than or less than the actual sum? How do you know? (A) The estimate is greater because each fraction is rounded up to a benchmark. (B) The estimate is less because each fraction is rounded down to a benchmark. (C) The estimate is greater because they really made more than 3 cups. (D) The estimate is less because each fraction is rounded up to a benchmark. Answer: A Explanation: \(\frac{2}{3}\) + \(\frac{7}{8}\) + \(\frac{4}{5}\) rounded to the nearest benchmarks \(\frac{3}{3}\) + \(\frac{8}{8}\) + \(\frac{5}{5}\) = 3 Evaluated Reasonableness Hector and Veronica are going hiking. They made a trail mix that has \(\frac{2}{3}\) cup of almonds, ” \(\frac{7}{8}\) cup of peanuts, and \(\frac{4}{5}\) cup of raisins in it. Hector estimates that they made about 3 cups of trail mix.

Lesson 5.3 Go Math 5th Grade Answer Key Question 12. Multi-Step Amanda picked \(\frac{3}{5}\) pound of blueberries at her local farm yesterday. She used \(\frac{3}{8}\) pound of blueberries. Today she picked \(\frac{4}{5}\) pound of blueberries. About how many pounds of blueberries does Amanda have now? (A) \(\frac{1}{5}\)lb (B) 1 lb (C) \(\frac{1}{2}\)lb (D) 1\(\frac{1}{2}\)lbs Answer: B Explanation: what she bought is that she used yesterday in today marked to nearest benchmarks \(\frac{4}{5}\)  is \(\frac{5}{5}\) that is 1

Texas Test Prep

Question 13. Jake added \(\frac{1}{8}\) cup of sunflower seeds and \(\frac{4}{5}\) cup of banana chips to his sundae. Which is the best estimate of the total amount of toppings Jake added to his sundae? (A) about 2 cups (B) about 1 cup (C) about 1\(\frac{1}{2}\) cups (D) about \(\frac{1}{2}\) cup Answer: B Explanation: Jake added \(\frac{1}{8}\) cup of sunflower seeds and \(\frac{4}{5}\) cup of banana chips to his sundae. The best estimate of the total amount of toppings Jake added to his sundae is 1 cup

Texas Go Math Grade 5 Lesson 5.3 Homework and Practice Answer Key

Question 1. \(\frac{3}{8}\) + \(\frac{4}{5}\) = ___________ Answer: \(\frac{3}{8}\) + \(\frac{4}{5}\) rounded to the nearest benchmarks \(\frac{4}{8}\) + \(\frac{5}{5}\) = 1 \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

5th Grade Go Math Lesson 5.3 Answer Key Question 2. \(\frac{9}{10}\) – \(\frac{3}{8}\) = ___________ Answer: \(\frac{9}{10}\) – \(\frac{3}{8}\) rounded to the nearest benchmarks \(\frac{10}{10}\) – \(\frac{4}{8}\) = \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 3. \(\frac{5}{8}\) + \(\frac{2}{5}\) = ___________ Answer: \(\frac{5}{8}\) + \(\frac{2}{5}\) rounded to the nearest benchmarks \(\frac{4}{8}\) + \(\frac{2}{5}\) = 1 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 4. \(\frac{6}{7}\) + \(\frac{3}{5}\) = ___________ Answer: \(\frac{6}{7}\) + \(\frac{3}{5}\) rounded to the nearest benchmarks \(\frac{7}{7}\) + \(\frac{2}{5}\) = 1\(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 5. \(\frac{3}{8}\) – \(\frac{1}{6}\) = ___________ Answer: \(\frac{3}{8}\) – \(\frac{1}{6}\) rounded to the nearest benchmarks \(\frac{4}{8}\) – \(\frac{0}{6}\) = \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 6. \(\frac{7}{12}\) + \(\frac{1}{7}\) = ___________ Answer: \(\frac{7}{12}\) + \(\frac{1}{7}\) rounded to the nearest benchmarks \(\frac{6}{12}\) + \(\frac{0}{7}\) = \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Go Math Lesson 5.3 5th Grade Homework Answer Key Question 7. \(\frac{4}{9}\) – \(\frac{5}{8}\) = ___________ Answer: \(\frac{4}{9}\) – \(\frac{5}{8}\) rounded to the nearest benchmarks \(\frac{5}{9}\) – \(\frac{4}{8}\) = 0 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 8. \(\frac{1}{9}\) + \(\frac{5}{6}\) = ___________ Answer: \(\frac{1}{9}\) + \(\frac{5}{6}\) rounded to the nearest benchmark \(\frac{0}{9}\) + \(\frac{6}{6}\) = 1 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 9. \(\frac{7}{8}\) + \(\frac{4}{7}\) = ___________ Answer: \(\frac{7}{8}\) + \(\frac{4}{7}\) rounded to the nearest bench mark \(\frac{8}{8}\) + \(\frac{4}{7}\) =1\(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 10. \(\frac{1}{5}\) + \(\frac{3}{8}\) = ___________ Answer: \(\frac{1}{5}\) + \(\frac{3}{8}\) rounded to the nearest benchmark \(\frac{0}{5}\) + \(\frac{4}{8}\) = \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 11. \(\frac{7}{9}\) – \(\frac{2}{6}\) = ___________ Answer: \(\frac{7}{9}\) – \(\frac{2}{6}\) rounded to the nearest benchmark \(\frac{9}{9}\) – \(\frac{3}{6}\) = \(\frac{1}{2}\) Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Go Math Grade 5 Lesson 5.3 Homework Answer Key Question 12. \(\frac{9}{10}\) – \(\frac{7}{8}\) = ___________ Answer: \(\frac{9}{10}\) – \(\frac{7}{8}\) rounded to the benchmarks \(\frac{10}{10}\) – \(\frac{8}{8}\) = 0 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 13. Explain how you can estimate the sum of \(\frac{4}{5}\) and \(\frac{1}{6}\). Answer: \(\frac{4}{5}\) + \(\frac{1}{6}\) rounded to the nearest bench marks \(\frac{5}{5}\) + \(\frac{0}{6}\) = 1 Explanation: used benchmarks to find reasonable estimates by rounding fractions to 0, \(\frac{1}{2}\), or 1.

Question 14. Jena uses \(\frac{7}{8}\) cup of raisins for muffins and \(\frac{5}{8}\) cup of raisins for a bowl of oatmeal. Does lena need more than or less than 1 cup of raisins to make muffins and oatmeal? Explain. Answer: more than 1 cup of raisins Explanation: Jena uses \(\frac{7}{8}\) cup of raisins for muffins and \(\frac{5}{8}\) cup of raisins for a bowl of oatmeal. \(\frac{7}{8}\) + \(\frac{5}{8}\) rounded the benhmark \(\frac{8}{8}\) + \(\frac{4}{8}\) = 1\(\frac{1}{2}\)

Question 15. A group of students ate \(\frac{5}{12}\) of a cheese pizza, \(\frac{7}{8}\) of a pepperoni pizza, and \(\frac{5}{8}\) of a veggie pizza. About how many pizzas were eaten? Answer: \(\frac{5}{12}\) + \(\frac{7}{8}\) + \(\frac{5}{8}\) rounded to the nearest benchmark \(\frac{6}{12}\) + \(\frac{8}{8}\) + \(\frac{4}{8}\) = 2 Explanation: A group of students ate \(\frac{5}{12}\) of a cheese pizza, \(\frac{7}{8}\) of a pepperoni pizza, and \(\frac{5}{8}\) of a veggie pizza. 2 pizzas were eaten in whole.

Lesson Check

Question 16. On Saturday, the scouts hiked \(\frac{4}{5}\) mile up the mountain. On Sunday, they hiked \(\frac{1}{4}\) mile up the mountain. About how far did the scouts hike up the mountain in all? (A) \(\frac{1}{2}\) mile (B) 1 mile (C) 1\(\frac{1}{2}\) miles (D) 2 miles Answer: \(\frac{4}{5}\) + \(\frac{1}{4}\) rounded to nearest benchmark \(\frac{5}{5}\) + \(\frac{0}{4}\)  is 1 mile Explanation: On Saturday, the scouts hiked \(\frac{4}{5}\) mile up the mountain. On Sunday, they hiked \(\frac{1}{4}\) mile up the mountain. 1 mile far the scouts hike up the mountain in all

Question 17. Which of the following best describes the difference for \(\frac{11}{12}\) – \(\frac{7}{10}\) ? (A) less than \(\frac{1}{2}\) (B) greater than \(\frac{1}{2}\) (C) greater than 1 (D) greater than 1\(\frac{1}{2}\) Answer: A Explanation: \(\frac{11}{12}\) – \(\frac{7}{10}\) is 0 that is less than \(\frac{1}{2}\)

Practice and Homework Lesson 5.3 Answer Key 5th Grade Question 18. Which sum is greatest? Use estimation to decide. (A) \(\frac{2}{7}\) + \(\frac{3}{8}\) (B) \(\frac{1}{10}\) + \(\frac{3}{8}\) (C) \(\frac{1}{6}\) + \(\frac{1}{8}\) (D) \(\frac{2}{9}\) + \(\frac{1}{8}\) Answer: A Explanation: \(\frac{2}{7}\) + \(\frac{3}{8}\) = 1

Question 20. Multi-Step Michaela has \(\frac{11}{12}\) yard of orange fabric and \(\frac{7}{8}\) yard of green fabric. She uses \(\frac{1}{2}\) yard of each color for her sewing project. About how much fabric does Michaela have left if she combines the two colors? (A) 1 yard (B) \(\frac{1}{2}\) yard (C) 1 \(\frac{1}{2}\) yards (D) 2 yards Answer:  D \(\frac{11}{12}\) + \(\frac{7}{8}\) rounded to nearest bench marks \(\frac{12}{12}\) + \(\frac{8}{8}\) = 2 Explanation: 2 yards fabric uses Michaela have left if she combines the two colors.

Question 21. Multi-Step Dustin buys \(\frac{9}{10}\) yard of striped fabric. He uses \(\frac{3}{8}\) yard. He buys \(\frac{7}{8}\) yard more. About how much fabric does Dustin have now? (A) 1 yard (B) \(\frac{1}{2}\) yard (C) 1\(\frac{1}{2}\) yards (D) 2 yards Answer: C Explanation: Dustin buys \(\frac{9}{10}\) yard of striped fabric. He uses \(\frac{3}{8}\) yard. He buys \(\frac{7}{8}\) yard more. \(\frac{9}{10}\) + \(\frac{3}{8}\)  + \(\frac{7}{8}\)  rounded to nearest benchmarks \(\frac{10}{10}\) – \(\frac{4}{8}\)  + \(\frac{8}{8}\)  = 1\(\frac{1}{2}\) yards

Share this:

Leave a comment cancel reply.

You must be logged in to post a comment.