onramps college algebra homework answers

9.1 Sequences and Their Notations

The first five terms are { 1 , 6 ,   11 ,   16 ,   21 } . { 1 , 6 ,   11 ,   16 ,   21 } .

The first five terms are { − 2 ,   2 ,   − 3 2 ,   1 , − 5 8 } . { − 2 ,   2 ,   − 3 2 ,   1 , − 5 8 } .

The first six terms are { 2 , 5 , 54 , 10 , 250 , 15 } . { 2 , 5 , 54 , 10 , 250 , 15 } .

a n = ( − 1 ) n + 1 9 n a n = ( − 1 ) n + 1 9 n

a n = − 3 n 4 n a n = − 3 n 4 n

a n = e n − 3 a n = e n − 3

{ 2 ,   5 ,   11 ,   23 ,   47 } { 2 ,   5 ,   11 ,   23 ,   47 }

{ 0 ,   1 ,   1 ,   1 ,   2 ,   3 ,   5 2 , 17 6 } . { 0 ,   1 ,   1 ,   1 ,   2 ,   3 ,   5 2 , 17 6 } .

The first five terms are { 1 ,   3 2 ,   4 , 15 , 72 } . { 1 ,   3 2 ,   4 , 15 , 72 } .

9.2 Arithmetic Sequences

The sequence is arithmetic. The common difference is – 2. – 2.

The sequence is not arithmetic because 3 − 1 ≠ 6 − 3. 3 − 1 ≠ 6 − 3.

{ 1 ,   6 ,   11 ,   16 ,   21 } { 1 ,   6 ,   11 ,   16 ,   21 }

a 2 = 2 a 2 = 2

a 1 = 25 a n = a n − 1 + 12 , for  n ≥ 2 a 1 = 25 a n = a n − 1 + 12 , for  n ≥ 2

a n = 53 − 3 n a n = 53 − 3 n

There are 11 terms in the sequence.

The formula is T n = 10 + 4 n , T n = 10 + 4 n , and it will take her 42 minutes.

9.3 Geometric Sequences

The sequence is not geometric because 10 5 ≠ 15 10 10 5 ≠ 15 10 .

The sequence is geometric. The common ratio is 1 5 1 5 .

{ 18 , 6 , 2 , 2 3 , 2 9 } { 18 , 6 , 2 , 2 3 , 2 9 }

a 1 = 2 a n = 2 3 a n − 1 for  n ≥ 2 a 1 = 2 a n = 2 3 a n − 1 for  n ≥ 2

a 6 = 16 , 384 a 6 = 16 , 384

a n = − ( − 3 ) n − 1 a n = − ( − 3 ) n − 1

• ⓐ P n   =   293 ⋅ 1.026 a n P n   =   293 ⋅ 1.026 a n
• ⓑ The number of hits will be about 333.

9.4 Series and Their Notations

26 .4 26 .4

≈ 2 , 000.00 ≈ 2 , 000.00

$275,513.31

The sum is not defined.

The sum of the infinite series is defined.

The series is not geometric.

− 3 11 − 3 11

9.5 Counting Principles

There are 60 possible breakfast specials.

P ( 7 , 7 ) = 5 , 040 P ( 7 , 7 ) = 5 , 040

P ( 7 , 5 ) = 2 , 520 P ( 7 , 5 ) = 2 , 520

C ( 10 , 3 ) = 120 C ( 10 , 3 ) = 120

9.6 Binomial Theorem

• ⓐ x 5 − 5 x 4 y + 10 x 3 y 2 − 10 x 2 y 3 + 5 x y 4 − y 5 x 5 − 5 x 4 y + 10 x 3 y 2 − 10 x 2 y 3 + 5 x y 4 − y 5
• ⓑ 8 x 3 + 60 x 2 y + 150 x y 2 + 125 y 3 8 x 3 + 60 x 2 y + 150 x y 2 + 125 y 3

− 10 , 206 x 4 y 5 − 10 , 206 x 4 y 5

9.7 Probability

a .  1 91 ; b .  5 91 ; c .  86 91 a .  1 91 ; b .  5 91 ; c .  86 91

9.1 Section Exercises

A sequence is an ordered list of numbers that can be either finite or infinite in number. When a finite sequence is defined by a formula, its domain is a subset of the non-negative integers. When an infinite sequence is defined by a formula, its domain is all positive or all non-negative integers.

Yes, both sets go on indefinitely, so they are both infinite sequences.

A factorial is the product of a positive integer and all the positive integers below it. An exclamation point is used to indicate the operation. Answers may vary. An example of the benefit of using factorial notation is when indicating the product It is much easier to write than it is to write out 13 ⋅ 12 ⋅ 11 ⋅ 10 ⋅ 9 ⋅ 8 ⋅ 7 ⋅ 6 ⋅ 5 ⋅ 4 ⋅ 3 ⋅ 2 ⋅ 1 . 13 ⋅ 12 ⋅ 11 ⋅ 10 ⋅ 9 ⋅ 8 ⋅ 7 ⋅ 6 ⋅ 5 ⋅ 4 ⋅ 3 ⋅ 2 ⋅ 1 .

First four terms: − 8 , − 16 3 , − 4 , − 16 5 − 8 , − 16 3 , − 4 , − 16 5

First four terms: 2 , 1 2 , 8 27 , 1 4 2 , 1 2 , 8 27 , 1 4 .

First four terms: 1.25 , − 5 , 20 , − 80 1.25 , − 5 , 20 , − 80 .

First four terms: 1 3 , 4 5 , 9 7 , 16 9 1 3 , 4 5 , 9 7 , 16 9 .

First four terms: − 4 5 , 4 , − 20 , 100 − 4 5 , 4 , − 20 , 100

1 3 , 4 5 , 9 7 , 16 9 , 25 11 , 31 , 44 , 59 1 3 , 4 5 , 9 7 , 16 9 , 25 11 , 31 , 44 , 59

− 0.6 , − 3 , − 15 , − 20 , − 375 , − 80 , − 9375 , − 320 − 0.6 , − 3 , − 15 , − 20 , − 375 , − 80 , − 9375 , − 320

a n = n 2 + 3 a n = n 2 + 3

a n = 2 n 2 n or  2 n − 1 n a n = 2 n 2 n or  2 n − 1 n

a n = ( − 1 2 ) n − 1 a n = ( − 1 2 ) n − 1

First five terms: 3 , − 9 , 27 , − 81 , 243 3 , − 9 , 27 , − 81 , 243

First five terms: − 1 , 1 , − 9 , 27 11 , 891 5 − 1 , 1 , − 9 , 27 11 , 891 5

1 24 , 1,  1 4 , 3 2 , 9 4 , 81 4 , 2187 8 , 531 , 441 16 1 24 , 1,  1 4 , 3 2 , 9 4 , 81 4 , 2187 8 , 531 , 441 16

2 , 10 , 12 , 14 5 , 4 5 , 2 , 10 , 12 2 , 10 , 12 , 14 5 , 4 5 , 2 , 10 , 12

a 1 = − 8 , a n = a n − 1 + n a 1 = − 8 , a n = a n − 1 + n

a 1 = 35 , a n = a n − 1 + 3 a 1 = 35 , a n = a n − 1 + 3

665 , 280 665 , 280

First four terms: 1 , 1 2 , 2 3 , 3 2 1 , 1 2 , 2 3 , 3 2

First four terms: − 1 , 2 , 6 5 , 24 11 − 1 , 2 , 6 5 , 24 11

a n = 2 n − 2 a n = 2 n − 2

a 1 = 6 , a n = 2 a n − 1 − 5 a 1 = 6 , a n = 2 a n − 1 − 5

First five terms: 29 37 29 37 , 152 111 152 111 , 716 333 716 333 , 3188 999 3188 999 , 13724 2997 13724 2997

First five terms: 2, 3, 5, 17, 65537

a 10 = 7 , 257 , 600 a 10 = 7 , 257 , 600

First six terms: 0.042, 0.146, 0.875, 2.385, 4.708

First four terms: 5.975, 2.765, 185.743, 1057.25, 6023.521

If a n = − 421 a n = − 421 is a term in the sequence, then solving the equation − 421 = − 6 − 8 n − 421 = − 6 − 8 n for n n will yield a non-negative integer. However, if − 421 = − 6 − 8 n , − 421 = − 6 − 8 n , then n = 51.875 n = 51.875 so a n = − 421 a n = − 421 is not a term in the sequence.

a 1 = 1 , a 2 = 0 , a n = a n − 1 − a n − 2 a 1 = 1 , a 2 = 0 , a n = a n − 1 − a n − 2

( n + 2 ) ! ( n − 1 ) ! = ( n + 2 ) · ( n + 1 ) · ( n ) · ( n − 1 ) · ... · 3 · 2 · 1 ( n − 1 ) · ... · 3 · 2 · 1 = n ( n + 1 ) ( n + 2 ) = n 3 + 3 n 2 + 2 n ( n + 2 ) ! ( n − 1 ) ! = ( n + 2 ) · ( n + 1 ) · ( n ) · ( n − 1 ) · ... · 3 · 2 · 1 ( n − 1 ) · ... · 3 · 2 · 1 = n ( n + 1 ) ( n + 2 ) = n 3 + 3 n 2 + 2 n

9.2 Section Exercises

A sequence where each successive term of the sequence increases (or decreases) by a constant value.

We find whether the difference between all consecutive terms is the same. This is the same as saying that the sequence has a common difference.

Both arithmetic sequences and linear functions have a constant rate of change. They are different because their domains are not the same; linear functions are defined for all real numbers, and arithmetic sequences are defined for natural numbers or a subset of the natural numbers.

The common difference is 1 2 1 2

The sequence is not arithmetic because 16 − 4 ≠ 64 − 16. 16 − 4 ≠ 64 − 16.

0 , 2 3 , 4 3 , 2 , 8 3 0 , 2 3 , 4 3 , 2 , 8 3

0 , − 5 , − 10 , − 15 , − 20 0 , − 5 , − 10 , − 15 , − 20

a 4 = 19 a 4 = 19

a 6 = 41 a 6 = 41

a 1 = 2 a 1 = 2

a 1 = 5 a 1 = 5

a 1 = 6 a 1 = 6

a 21 = − 13.5 a 21 = − 13.5

− 19 , − 20.4 , − 21.8 , − 23.2 , − 24.6 − 19 , − 20.4 , − 21.8 , − 23.2 , − 24.6

a 1 = 17 ;   a n = a n − 1 + 9 n ≥ 2 a 1 = 17 ;   a n = a n − 1 + 9 n ≥ 2

a 1 = 12 ;   a n = a n − 1 + 5 n ≥ 2 a 1 = 12 ;   a n = a n − 1 + 5 n ≥ 2

a 1 = 8.9 ;   a n = a n − 1 + 1.4 n ≥ 2 a 1 = 8.9 ;   a n = a n − 1 + 1.4 n ≥ 2

a 1 = 1 5 ;   a n = a n − 1 + 1 4 n ≥ 2 a 1 = 1 5 ;   a n = a n − 1 + 1 4 n ≥ 2

1 = 1 6 ;   a n = a n − 1 − 13 12 n ≥ 2 1 = 1 6 ;   a n = a n − 1 − 13 12 n ≥ 2

a 1 = 4 ; a n = a n − 1 + 7 ; a 14 = 95 a 1 = 4 ; a n = a n − 1 + 7 ; a 14 = 95

First five terms: 20 , 16 , 12 , 8 , 4. 20 , 16 , 12 , 8 , 4.

a n = 1 + 2 n a n = 1 + 2 n

a n = − 105 + 100 n a n = − 105 + 100 n

a n = 1.8 n a n = 1.8 n

a n = 13.1 + 2.7 n a n = 13.1 + 2.7 n

a n = 1 3 n − 1 3 a n = 1 3 n − 1 3

There are 10 terms in the sequence.

There are 6 terms in the sequence.

The graph does not represent an arithmetic sequence.

1 , 4 , 7 , 10 , 13 , 16 , 19 1 , 4 , 7 , 10 , 13 , 16 , 19

Answers will vary. Examples: a n = 20.6 n a n = 20.6 n and a n = 2 + 20.4 n. a n = 2 + 20.4 n.

a 11 = − 17 a + 38 b a 11 = − 17 a + 38 b

The sequence begins to have negative values at the 13 th term, a 13 = − 1 3 a 13 = − 1 3

Answers will vary. Check to see that the sequence is arithmetic. Example: Recursive formula: a 1 = 3 , a n = a n − 1 − 3. a 1 = 3 , a n = a n − 1 − 3. First 4 terms: 3 , 0 , − 3 , − 6 a 31 = − 87 3 , 0 , − 3 , − 6 a 31 = − 87

9.3 Section Exercises

A sequence in which the ratio between any two consecutive terms is constant.

Divide each term in a sequence by the preceding term. If the resulting quotients are equal, then the sequence is geometric.

Both geometric sequences and exponential functions have a constant ratio. However, their domains are not the same. Exponential functions are defined for all real numbers, and geometric sequences are defined only for positive integers. Another difference is that the base of a geometric sequence (the common ratio) can be negative, but the base of an exponential function must be positive.

The common ratio is − 2 − 2

The sequence is geometric. The common ratio is 2.

The sequence is geometric. The common ratio is − 1 2 . − 1 2 .

The sequence is geometric. The common ratio is 5. 5.

5 , 1 , 1 5 , 1 25 , 1 125 5 , 1 , 1 5 , 1 25 , 1 125

800 , 400 , 200 , 100 , 50 800 , 400 , 200 , 100 , 50

a 4 = − 16 27 a 4 = − 16 27

a 7 = − 2 729 a 7 = − 2 729

7 , 1.4 , 0.28 , 0.056 , 0.0112 7 , 1.4 , 0.28 , 0.056 , 0.0112

a = 1 − 32 , a n = 1 2 a n − 1 a = 1 − 32 , a n = 1 2 a n − 1

a 1 = 10 , a n = − 0.3 a n − 1 a 1 = 10 , a n = − 0.3 a n − 1

a 1 = 3 5 , a n = 1 6 a n − 1 a 1 = 3 5 , a n = 1 6 a n − 1

a 1 = 1 512 , a n = − 4 a n − 1 a 1 = 1 512 , a n = − 4 a n − 1

12 , − 6 , 3 , − 3 2 , 3 4 12 , − 6 , 3 , − 3 2 , 3 4

a n = 3 n − 1 a n = 3 n − 1

a n = 0.8 ⋅ ( − 5 ) n − 1 a n = 0.8 ⋅ ( − 5 ) n − 1

a n = − ( 4 5 ) n − 1 a n = − ( 4 5 ) n − 1

a n = 3 ⋅ ( − 1 3 ) n − 1 a n = 3 ⋅ ( − 1 3 ) n − 1

a 12 = 1 177 , 147 a 12 = 1 177 , 147

There are 12 12 terms in the sequence.

The graph does not represent a geometric sequence.

Answers will vary. Examples: a 1 = 800 , a n = 0.5 a n − 1 a 1 = 800 , a n = 0.5 a n − 1 and a 1 = 12.5 , a n = 4 a n − 1 a 1 = 12.5 , a n = 4 a n − 1

a 5 = 256 b a 5 = 256 b

The sequence exceeds 100 100 at the 14 th term, a 14 ≈ 107. a 14 ≈ 107.

a 4 = − 32 3 a 4 = − 32 3 is the first non-integer value

Answers will vary. Example: Explicit formula with a decimal common ratio: a n = 400 ⋅ 0.5 n − 1 ; a n = 400 ⋅ 0.5 n − 1 ; First 4 terms: 400 , 200 , 100 , 50 ; a 8 = 3.125 400 , 200 , 100 , 50 ; a 8 = 3.125

9.4 Section Exercises

An n th n th partial sum is the sum of the first n n terms of a sequence.

A geometric series is the sum of the terms in a geometric sequence.

An annuity is a series of regular equal payments that earn a constant compounded interest.

∑ n = 0 4 5 n ∑ n = 0 4 5 n

∑ k = 1 5 4 ∑ k = 1 5 4

∑ k = 1 20 8 k + 2 ∑ k = 1 20 8 k + 2

S 5 = 5 ( 3 2 + 7 2 ) 2 S 5 = 5 ( 3 2 + 7 2 ) 2

S 13 = 13 ( 3.2 + 5.6 ) 2 S 13 = 13 ( 3.2 + 5.6 ) 2

∑ k = 1 7 8 ⋅ 0.5 k − 1 ∑ k = 1 7 8 ⋅ 0.5 k − 1

S 5 = 9 ( 1 − ( 1 3 ) 5 ) 1 − 1 3 = 121 9 ≈ 13.44 S 5 = 9 ( 1 − ( 1 3 ) 5 ) 1 − 1 3 = 121 9 ≈ 13.44

S 11 = 64 ( 1 − 0.2 11 ) 1 − 0.2 = 781 , 249 , 984 9 , 765 , 625 ≈ 80 S 11 = 64 ( 1 − 0.2 11 ) 1 − 0.2 = 781 , 249 , 984 9 , 765 , 625 ≈ 80

The series is defined. S = 2 1 − 0.8 S = 2 1 − 0.8

The series is defined. S = − 1 1 − ( − 1 2 ) S = − 1 1 − ( − 1 2 )

Sample answer: The graph of S n S n seems to be approaching 1. This makes sense because ∑ k = 1 ∞ ( 1 2 ) k ∑ k = 1 ∞ ( 1 2 ) k is a defined infinite geometric series with S = 1 2 1 – ( 1 2 ) = 1. S = 1 2 1 – ( 1 2 ) = 1.

S 7 = 147 2 S 7 = 147 2

S 11 = 55 2 S 11 = 55 2

S 7 = 5208.4 S 7 = 5208.4

S 10 = − 1023 256 S 10 = − 1023 256

S = − 4 3 S = − 4 3

S = 9.2 S = 9.2

$695,823.97

a k = 30 − k a k = 30 − k

r = 4 5 r = 4 5

$400 per month

9.5 Section Exercises

There are m + n m + n ways for either event A A or event B B to occur.

The addition principle is applied when determining the total possible of outcomes of either event occurring. The multiplication principle is applied when determining the total possible outcomes of both events occurring. The word “or” usually implies an addition problem. The word “and” usually implies a multiplication problem.

A combination; C ( n , r ) = n ! ( n − r ) ! r ! C ( n , r ) = n ! ( n − r ) ! r !

4 + 2 = 6 4 + 2 = 6

5 + 4 + 7 = 16 5 + 4 + 7 = 16

2 × 6 = 12 2 × 6 = 12

10 3 = 1000 10 3 = 1000

P ( 5 , 2 ) = 20 P ( 5 , 2 ) = 20

P ( 3 , 3 ) = 6 P ( 3 , 3 ) = 6

P ( 11 , 5 ) = 55 , 440 P ( 11 , 5 ) = 55 , 440

C ( 12 , 4 ) = 495 C ( 12 , 4 ) = 495

C ( 7 , 6 ) = 7 C ( 7 , 6 ) = 7

2 10 = 1024 2 10 = 1024

2 12 = 4096 2 12 = 4096

2 9 = 512 2 9 = 512

8 ! 3 ! = 6720 8 ! 3 ! = 6720

12 ! 3 ! 2 ! 3 ! 4 ! 12 ! 3 ! 2 ! 3 ! 4 !

Yes, for the trivial cases r = 0 r = 0 and r = 1. r = 1. If r = 0 , r = 0 , then C ( n , r ) = P ( n , r ) = 1 .  C ( n , r ) = P ( n , r ) = 1 .  If r = 1 , r = 1 , then r = 1 , r = 1 , C ( n , r ) = P ( n , r ) = n . C ( n , r ) = P ( n , r ) = n .

6 ! 2 ! × 4 ! = 8640 6 ! 2 ! × 4 ! = 8640

6 − 3 + 8 − 3 = 8 6 − 3 + 8 − 3 = 8

4 × 2 × 5 = 40 4 × 2 × 5 = 40

4 × 12 × 3 = 144 4 × 12 × 3 = 144

P ( 15 , 9 ) = 1 , 816 , 214 , 400 P ( 15 , 9 ) = 1 , 816 , 214 , 400

C ( 10 , 3 ) × C ( 6 , 5 ) × C ( 5 , 2 ) = 7 , 200 C ( 10 , 3 ) × C ( 6 , 5 ) × C ( 5 , 2 ) = 7 , 200

2 11 = 2048 2 11 = 2048

20 ! 6 ! 6 ! 8 ! = 116 , 396 , 280 20 ! 6 ! 6 ! 8 ! = 116 , 396 , 280

9.6 Section Exercises

A binomial coefficient is an alternative way of denoting the combination C ( n , r ). C ( n , r ). It is defined as ( n r ) = C ( n , r ) = n ! r ! ( n − r ) ! . ( n r ) = C ( n , r ) = n ! r ! ( n − r ) ! .

The Binomial Theorem is defined as ( x + y ) n = ∑ k = 0 n ( n k ) x n − k y k ( x + y ) n = ∑ k = 0 n ( n k ) x n − k y k and can be used to expand any binomial.

64 a 3 − 48 a 2 b + 12 a b 2 − b 3 64 a 3 − 48 a 2 b + 12 a b 2 − b 3

27 a 3 + 54 a 2 b + 36 a b 2 + 8 b 3 27 a 3 + 54 a 2 b + 36 a b 2 + 8 b 3

1024 x 5 + 2560 x 4 y + 2560 x 3 y 2 + 1280 x 2 y 3 + 320 x y 4 + 32 y 5 1024 x 5 + 2560 x 4 y + 2560 x 3 y 2 + 1280 x 2 y 3 + 320 x y 4 + 32 y 5

1024 x 5 − 3840 x 4 y + 5760 x 3 y 2 − 4320 x 2 y 3 + 1620 x y 4 − 243 y 5 1024 x 5 − 3840 x 4 y + 5760 x 3 y 2 − 4320 x 2 y 3 + 1620 x y 4 − 243 y 5

1 x 4 + 8 x 3 y + 24 x 2 y 2 + 32 x y 3 + 16 y 4 1 x 4 + 8 x 3 y + 24 x 2 y 2 + 32 x y 3 + 16 y 4

a 17 + 17 a 16 b + 136 a 15 b 2 a 17 + 17 a 16 b + 136 a 15 b 2

a 15 − 30 a 14 b + 420 a 13 b 2 a 15 − 30 a 14 b + 420 a 13 b 2

3 , 486 , 784 , 401 a 20 + 23 , 245 , 229 , 340 a 19 b + 73 , 609 , 892 , 910 a 18 b 2 3 , 486 , 784 , 401 a 20 + 23 , 245 , 229 , 340 a 19 b + 73 , 609 , 892 , 910 a 18 b 2

x 24 − 8 x 21 y + 28 x 18 y x 24 − 8 x 21 y + 28 x 18 y

− 720 x 2 y 3 − 720 x 2 y 3

220 , 812 , 466 , 875 , 000 y 7 220 , 812 , 466 , 875 , 000 y 7

35 x 3 y 4 35 x 3 y 4

1 , 082 , 565 a 3 b 16 1 , 082 , 565 a 3 b 16

1152 y 2 x 7 1152 y 2 x 7

f 2 ( x ) = x 4 + 12 x 3 f 2 ( x ) = x 4 + 12 x 3

f 4 ( x ) = x 4 + 12 x 3 + 54 x 2 + 108 x f 4 ( x ) = x 4 + 12 x 3 + 54 x 2 + 108 x

590 , 625 x 5 y 2 590 , 625 x 5 y 2

k − 1 k − 1

The expression ( x 3 + 2 y 2 − z ) 5 ( x 3 + 2 y 2 − z ) 5 cannot be expanded using the Binomial Theorem because it cannot be rewritten as a binomial.

9.7 Section Exercises

probability; The probability of an event is restricted to values between 0 0 and 1 , 1 , inclusive of 0 0 and 1. 1.

An experiment is an activity with an observable result.

The probability of the union of two events occurring is a number that describes the likelihood that at least one of the events from a probability model occurs. In both a union of sets A   and  B A   and  B and a union of events A   and   B , A   and   B , the union includes either A   or   B A   or   B or both. The difference is that a union of sets results in another set, while the union of events is a probability, so it is always a numerical value between 0 0 and 1. 1.

1 2 . 1 2 .

5 8 . 5 8 .

3 8 . 3 8 .

1 4 . 1 4 .

3 4 . 3 4 .

1 8 . 1 8 .

15 16 . 15 16 .

1 13 . 1 13 .

1 26 . 1 26 .

12 13 . 12 13 .

5 12 . 5 12 .

4 9 . 4 9 .

C ( 12 , 5 ) C ( 48 , 5 ) = 1 2162 C ( 12 , 5 ) C ( 48 , 5 ) = 1 2162

C ( 12 , 3 ) C ( 36 , 2 ) C ( 48 , 5 ) = 175 2162 C ( 12 , 3 ) C ( 36 , 2 ) C ( 48 , 5 ) = 175 2162

C ( 20 , 3 ) C ( 60 , 17 ) C ( 80 , 20 ) ≈ 12.49 % C ( 20 , 3 ) C ( 60 , 17 ) C ( 80 , 20 ) ≈ 12.49 %

C ( 20 , 5 ) C ( 60 , 15 ) C ( 80 , 20 ) ≈ 23.33 % C ( 20 , 5 ) C ( 60 , 15 ) C ( 80 , 20 ) ≈ 23.33 %

20.50 + 23.33 − 12.49 = 31.34 % 20.50 + 23.33 − 12.49 = 31.34 %

C ( 40000000 , 1 ) C ( 277000000 , 4 ) C ( 317000000 , 5 ) = 36.78 % C ( 40000000 , 1 ) C ( 277000000 , 4 ) C ( 317000000 , 5 ) = 36.78 %

C ( 40000000 , 4 ) C ( 277000000 , 1 ) C ( 317000000 , 5 ) = 0.11 % C ( 40000000 , 4 ) C ( 277000000 , 1 ) C ( 317000000 , 5 ) = 0.11 %

Review Exercises

2 , 4 , 7 , 11 2 , 4 , 7 , 11

13 , 103 , 1003 , 10003 13 , 103 , 1003 , 10003

The sequence is arithmetic. The common difference is d = 5 3 . d = 5 3 .

18 , 10 , 2 , − 6 , − 14 18 , 10 , 2 , − 6 , − 14

a 1 = − 20 , a n = a n − 1 + 10 a 1 = − 20 , a n = a n − 1 + 10

a n = 1 3 n + 13 24 a n = 1 3 n + 13 24

r = 2 r = 2

4, 16, 64, 256, 1024

3 , 12 , 48 , 192 , 768 3 , 12 , 48 , 192 , 768

a n = − 1 5 ⋅ ( 1 3 ) n − 1 a n = − 1 5 ⋅ ( 1 3 ) n − 1

∑ m = 0 5 ( 1 2 m + 5 ) . ∑ m = 0 5 ( 1 2 m + 5 ) .

S 11 = 110 S 11 = 110

S 9 ≈ 23.95 S 9 ≈ 23.95

S = 135 4 S = 135 4

10 4 = 10 , 000 10 4 = 10 , 000

P ( 18 , 4 ) = 73 , 440 P ( 18 , 4 ) = 73 , 440

C ( 15 , 6 ) = 5005 C ( 15 , 6 ) = 5005

2 50 = 1.13 × 10 15 2 50 = 1.13 × 10 15

8 ! 3 ! 2 ! = 3360 8 ! 3 ! 2 ! = 3360

490 , 314 490 , 314

131 , 072 a 17 + 1 , 114 , 112 a 16 b + 4 , 456 , 448 a 15 b 2 131 , 072 a 17 + 1 , 114 , 112 a 16 b + 4 , 456 , 448 a 15 b 2

1 − C ( 350 , 8 ) C ( 500 , 8 ) ≈ 94.4 % 1 − C ( 350 , 8 ) C ( 500 , 8 ) ≈ 94.4 %

C ( 150 , 3 ) C ( 350 , 5 ) C ( 500 , 8 ) ≈ 25.6 % C ( 150 , 3 ) C ( 350 , 5 ) C ( 500 , 8 ) ≈ 25.6 %

Practice Test

− 14 , − 6 , − 2 , 0 − 14 , − 6 , − 2 , 0

The sequence is arithmetic. The common difference is d = 0.9. d = 0.9.

a 1 = − 2 , a n = a n − 1 − 3 2 ; a 22 = − 67 2 a 1 = − 2 , a n = a n − 1 − 3 2 ; a 22 = − 67 2

The sequence is geometric. The common ratio is r = 1 2 . r = 1 2 .

a 1 = 1 , a n = − 1 2 ⋅ a n − 1 a 1 = 1 , a n = − 1 2 ⋅ a n − 1

∑ k = − 3 15 ( 3 k 2 − 5 6 k ) ∑ k = − 3 15 ( 3 k 2 − 5 6 k )

S 7 = − 2604.2 S 7 = − 2604.2

Total in account: $ 140 , 355.75 ; $ 140 , 355.75 ; Interest earned: $ 14 , 355.75 $ 14 , 355.75

5 × 3 × 2 × 3 × 2 = 180 5 × 3 × 2 × 3 × 2 = 180

C ( 15 , 3 ) = 455 C ( 15 , 3 ) = 455

10 ! 2 ! 3 ! 2 ! = 151 , 200 10 ! 2 ! 3 ! 2 ! = 151 , 200

429 x 14 16 429 x 14 16

C ( 14 , 3 ) C ( 26 , 4 ) C ( 40 , 7 ) ≈ 29.2 % C ( 14 , 3 ) C ( 26 , 4 ) C ( 40 , 7 ) ≈ 29.2 %

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• Authors: Jay Abramson
• Publisher/website: OpenStax
• Book title: College Algebra
• Publication date: Feb 13, 2015
• Location: Houston, Texas
• Book URL: https://openstax.org/books/college-algebra/pages/1-introduction-to-prerequisites
• Section URL: https://openstax.org/books/college-algebra/pages/chapter-9

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CHEMISTRY I

CHEMISTRY II

COLLEGE ALGEBRA

PRECALCULUS

COMPUTER SCIENCE

QUANTUM TECHNOLOGIES

HISTORY (FALL)

History (spring).

RHETORIC (FALL)

Rhetoric (spring).

Learn more about eligibility and earning college credit with OnRamps courses, and transferability of college credit.

PROFESSIONAL LEARNING AND DEVELOPMENT

We offer robust  professional development  to teachers and faculty to help advance their content knowledge and expertise and boost student engagement, persistence, and completion.

We  partner with school districts and higher education institutions—whether through offering OnRamps courses or seeking unique, customizable supports—to help students and teachers excel in the classroom and beyond.

DISTANCE LEARNING CATALOG

OnRamps offers a series of online, self-paced professional development modules for educators and faculty, grades 5 and above, who are looking to advance quality and engagement in the virtual classroom. Educators can earn CPE hours on belonging and connectivity, learner-centered course creation and design, and more.