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Case Study Questions for Class 7 Maths Chapter 2 Fractions and Decimals

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Case Study Questions for Class 7 Maths Chapter 1 Integers

Here in this article, we are providing case study questions for Class 7 Maths Chapter 2 Fractions and Decimals.

Maths Class 7 Chapter List

Latest chapter list (2023-24).

There is total 13 chapters.

Chapter 1 Integers Case Study Questions Chapter 2 Fractions and Decimals Case Study Questions Chapter 3 Data Handling Case Study Questions Chapter 4 Simple Equations Case Study Questions Chapter 5 Lines and Angles Case Study Questions Chapter 6 The Triangles and its Properties Case Study Questions Chapter 7 Comparing Quantities Case Study Questions Chapter 8 Rational Numbers Case Study Questions Chapter 9 Perimeter and Area Case Study Questions Chapter 10 Algebraic Expressions Case Study Questions Chapter 11 Exponents and Powers Case Study Questions Chapter 12 Symmetry Case Study Questions Chapter 13 Visualising Solid Shapes Case Study Questions

Old Chapter List

Chapter 1 Integers Chapter 2 Fractions and Decimals Chapter 3 Data Handling Chapter 4 Simple Equations Chapter 5 Lines and Angles Chapter 6 The Triangles and its Properties Chapter 7 Congruence of Triangles Chapter 8 Comparing Quantities Chapter 9 Rational Numbers Chapter 10 Practical Geometry Chapter 11 Perimeter and Area Chapter 12 Algebraic Expressions Chapter 13 Exponents and Powers Chapter 14 Symmetry Chapter 15 Visualising Solid Shapes

Deleted Chapter:

Chapter 7 Congruence of Triangles
Chapter 10 Practical Geometry

Tips for Answering Case Study Questions for Class 7 Maths in Exam

1. Comprehensive Reading for Context: Prioritize a thorough understanding of the provided case study. Absorb the contextual details and data meticulously to establish a strong foundation for your solution.

2. Relevance Identification: Pinpoint pertinent mathematical concepts applicable to the case study. By doing so, you can streamline your thinking process and apply appropriate methods with precision.

3. Deconstruction of the Problem: Break down the complex problem into manageable components or steps. This approach enhances clarity and facilitates organized problem-solving.

4. Highlighting Key Data: Emphasize critical information and data supplied within the case study. This practice aids quick referencing during the problem-solving process.

5. Application of Formulas: Leverage pertinent mathematical formulas, theorems, and principles to solve the case study. Accuracy in formula selection and unit usage is paramount.

6. Transparent Workflow Display: Document your solution with transparency, showcasing intermediate calculations and steps taken. This not only helps track progress but also offers insight into your analytical process.

7. Variable Labeling and Definition: For introduced variables or unknowns, offer clear labels and definitions. This eliminates ambiguity and reinforces a structured solution approach.

8. Step Explanation: Accompany each step with an explanatory note. This reinforces your grasp of concepts and demonstrates effective application.

9. Realistic Application: When the case study pertains to real-world scenarios, infuse practical reasoning and logic into your solution. This ensures alignment with real-life implications.

10. Thorough Answer Review: Post-solving, meticulously review your answer for accuracy and coherence. Assess its compatibility with the case study’s context.

11. Solution Recap: Before submission, revisit your solution to guarantee comprehensive coverage of the problem and a well-organized response.

12. Previous Case Study Practice: Boost your confidence by practicing with past case study questions from exams or textbooks. This familiarity enhances your readiness for the question format.

13. Efficient Time Management: Strategically allocate time for each case study question based on its complexity and the overall exam duration.

14. Maintain Composure and Confidence: Approach questions with poise and self-assurance. Your preparation equips you to conquer the challenges presented.

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case study questions on decimals class 7

CBSE 7th Standard CBSE Mathematics question papers, important notes , study materials , Previuous Year questions, Syllabus and exam patterns. Free 7th Standard CBSE Mathematics books and syllabus online. Practice Online test for free in QB365 Study Material. Important keywords, Case Study Questions and Solutions. Updates about latest education news and Scholorships in one place.

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Fractions and Decimals class 7 |Practice questions and worksheet PDF Download

Fractions and decimals class 7

Fractions and decimals class 7 ( Short Answer type questions)

$\frac{5}{3}$

Hence the required number is 9.

$20\frac{1}{2}+30\frac{1}{3}-15\frac{1}{6}$

Another Method : 7 x 89= 623 and 14 x 45 = 630

$\frac{3}{4}$

Question 7 : Round off 86.953 to tenths place. Solution: For rounding off to tenths place, we look at the hundredths place. Here the digit is 5.So, the digit at the tenths place (9)

will be increased by 1 (i.e., it will become 9 + 1). Hence, rounding off 86.953 to tenths place, we get 87.0

Question 8: Arrange the following in ascending order

(i) 0.20 , 0.002, 0.02, 2.2 , 2.02, 2.22

(ii) 9.99, 9.099, 99.9, 99.09 , 9.009

Solution : (i) 0.002 < 0.02< 0.20< 2.02< 2.2 < 2.22

(ii) 9.009< 9.099 < 9.99 < 99 .09 < 99.9

$\frac{12}{9}$

Question 10. Arrange the following in descending order.

(i) 9.45, 9.054, 9.504, 9.405, 9.54, 9.045

(ii) 77.7, 7.77, 0.777, 7.07, 0.707, 7.077

Solution. (i) 9.54 > 9.504 > 9.45 > 9.405> 9.054> 9.045

(ii) 77.7 > 7.77 > 7.077> 7.07> 0.777 > 0.707

Question 11: (i) 5.9 ÷ 10 = _____

(ii) 5.9 ÷ 100 = _____

(iii) 5.9 ÷ 1000 = _____

$5.9 \div 10 =5.9 \times \frac{1}{10} =\frac{5.9}{10}$

Example 13. Find the average of 4.21, 3.82 and 7.63 .

$\frac{4.21+3.82+7.63}{3}$

Example 14 : Divide (a) 0.5176 by 8 (b) 3.45 by 25

Fractions and decimals class 7 (Fill in the blanks type questions)

$6\frac{7}{8} \times 0 =\square$

(vii) Decimal 8.125 is equal to the fraction ……………

(viii) 6.29- 3.78 = ………..

$\frac{8}{45}\, \square \, \frac{16}{89}$

(xi) The reciprocal of fraction more than 1 is always less than 1.

$\square$

Fractions and decimals class 7 (Word problems)

$5\frac{2}{5}$

Question 2: A car covers a distance of 99.1 km in 2.5 hours. What is the average distance covered by it in 1 hour?

Solution. Distance covered by the car = 99.1 km.

Time required to cover this distance = 2. 5 hours.

$\frac{99.1}{2.5}$

Weight of good apples = total weight of apples – weight of rotten apples

$\frac{3}{2} kg$

Question 5: Mr. Amit distributed Rs. 560 among N.C.C. Cadets for refreshment . If each cadet receive Rs. 8.75 , How many cadets were there?

Solution: Total amount distributed = Rs. 560

Amount received by each cadet= Rs. 8.75

$\frac{560}{8.75}=\frac{560 \times 100}{8.75 \times 100}=\frac{56000}{875} =64$

Hence, the number of cadets is 64.

Fractions and decimals (worksheet)

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Chapter 2 Class 7 Fractions and Decimals

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Updated from 2023-24 NCERT Book.

Get solutions of all questions of Chapter 2 Class 7 Fractions & Decimals free at teachoo. All NCERT exercise questions and examples have been solved with detailed explanation of each solution. Concepts have also been explained in the concept wise.

In this chapter, we will study

What is a fraction
What is proper , improper and mixed fraction
What are equivalent fractions
Comparing fractions
Adding and Subtracting Fractions
Then, we will learn how to Multiply Fractions and Mixed Fractions
And how to divide Fractions
And do some statement questions on multiplication and division of fractions
What are Decimal Numbers
Place value of Decimals
Comparing Decimal Numbers
Converting g → kg, mm → cm, mm → m, mm → km, cm → m, cm → km
Addition and Subtraction of Decimal Numbers
We will learn how to Multiply Decimal Numbers
and How to divide Decimals
And do some statement questions

Click on an exercise, or a topic below to start.

Serial order wise

Concept wise.

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Revision Notes on Fractions and Decimals

Fractions tell about “a part of a whole” .

Here the pizza is divided into 4 equal parts and there are 3 parts left with us.

We will write it in a fraction as 3/4, in which 3 is numerator which tells the number of parts we have and 4 is denominator which tells the total parts in a whole.

The General form of a Fraction

Where, denominator ≠ 0

If numerator = denominator then the fraction becomes a whole i.e. 1. This is called unity of fraction.

Types of Fraction

Converting a mixed fraction into an improper fraction.

Converting an Improper Fraction into a Mixed Fraction

Divide the Numerator by the denominators that the quotient will be the whole number and remainder will be the numerator, while denominator will remain the same.

How to find the equivalent fractions?

To find the equivalent fraction of proper and improper fraction, we have the multiply both the numerator and denominator with the same number.

Reciprocal of a Fraction

If we have two non-zero numbers whose product is one then these numbers must be the reciprocals of each other.

To find the reciprocal of any fraction, we just need to flip the numerator with the denominator.

Multiplication of Fractions

1. How to multiply a fraction with a whole number?

a. If we have to multiply the proper or improper fraction with the whole number then we simply multiply the numerator with that whole number and the denominator will remain the same.

b. If we have to multiply the mixed fraction with the whole number then first convert it in the form of improper fraction then multiply as above.

c. Fraction as an operator “of” .

If it is written that find the 1/2 of 24 then what does ‘of’ means here?

Here ‘of’ represents the multiplication.

2. How to multiply a fraction with another fraction?

If we have to multiply the proper or improper fraction with another fraction then we simply multiply the numerator of both the fractions and the denominator of both the fractions separately and write them as the new fraction.

Value of the products of the fractions

Generally when we multiply two numbers then we got the result which is greater than the numbers.

5 × 6 = 30, where, 30 > 5 and 30 > 6

But in case of a fraction, it is not always like that.

a. The product of two proper fractions

If we multiply two proper fractions then their product will be less than the given fractions.

b. The product of two improper fractions

If we multiply two improper fractions then their product will be greater than the given fractions.

c. The product of one proper and one improper fraction

If we multiply proper fraction with the improper fraction then the product will be less than the improper fraction and greater than the proper fraction.

Division of Fractions

1. How to divide a whole number by a Fraction?

a. If we have to divide the whole number with the proper or improper fraction then we will multiply that whole number with the reciprocal of the given fraction.

b. If we have to divide the whole number with the mixed fraction then we will convert it into improper fraction then multiply it’s reciprocal with the whole number.

2. How to divide a Fraction with a whole number?

To divide the fraction with a whole number, we have to take the reciprocal of the whole number then divide it with the whole number as usual

3. How to divide a fraction with another Fraction?

To divide a fraction with another fraction, we have to multiply the first fraction with the reciprocal of the second fraction.

Decimal Numbers

Fractions which has denominator 10, 100, 1000 etc are called Decimal Fractions .

A decimal number is a number with a decimal point. Numbers left to the decimal are 10 greater and numbers to the right of the decimal are 10 smaller.

Multiplication of Decimal Numbers

1. How to multiply a decimal number with a whole number?

If we have to multiply the whole number with a decimal number then we will multiply them as normal numbers but the decimal place will remain the same as it was in the original decimal number.

35 × 3.45 = 120.75

Here we have multiplied the number 35 with 345 as normal whole numbers and we put the decimal at the same place from the right as it was in 3.45.

2. How to multiply Decimal numbers by 10,100 and 1000?

a. If we have to multiply a decimal number by 10 then we will transfer the decimal point to the right by one place.

5.37 × 10 = 53.7

b. If we have to multiply a decimal number by 100 then we will transfer the decimal point to the right by two places.

5.37 × 100 = 537

c. If we have to multiply a decimal number by 1000 then we will transfer the decimal point to the right by three places.

5.37 × 1000 = 5370

3. How to multiply a decimal number by another decimal number?

To multiply a decimal number with another decimal number we have to multiply them as the normal whole numbers then put the decimal at such place so that the number of decimal place in the product is equal to the sum of the decimal places in the given decimal numbers.

Division of Decimal Numbers

1. How to divide a decimal number with a whole number?

If we have to divide the whole number with a decimal number then we will divide them as whole numbers but the decimal place will remain the same as it was in the original decimal number.

12.96 ÷ 4 = 3.24

Here we divide the number 1296 with 4 as normal whole numbers and we put the decimal at the same place from the right as it was in 12.96.

2. How to divide Decimal numbers by 10,100 and 1000?

a. If we have to divide a decimal number by 10 then we will transfer the decimal point to the left by one place.

5.37 ÷ 10 = 0.537

b. If we have to divide a decimal number by 100 then we will transfer the decimal point to the left by two places.

253.37 × 100 = 2.5337

c. If we have to divide a decimal number by 1000 then we will transfer the decimal point to the left by three places.

255.37 × 1000 = 0.25537

3. How to divide a decimal number by another decimal number?

To divide a decimal number with another decimal number

First, we have to convert the denominator as the whole number by multiplying both the numerator and denominator by 10, 100 etc

Now we can divide them as we had done before.

Here we had converted denominator 2.4 in the whole number by multiplying by 10.Then divide it as usual.

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CBSE Class 7 Math

Class 7 Maths Fractions And Decimals Important Questions

by Sanjusha · Published March 14, 2020 · Updated March 14, 2020

IMPORTANT QUESTIONS FOR CBSE EXAMINATION | CLASS 7 MATHEMATICS FRACTIONS AND DECIMALS – Chapter 2

Answer the following (2 mark)

a) ½ of 24 b) ½ of 46

a) 2/3 of 18 b) 2/3 of 27

3. Write three rational numbers between -4/5 and -2/3.

4. Find 9/2 x -5/3.

5. Find five equivalent fractions of 2/3.

6. Express as rupees using decimals:

a) 5 paise ii) 235 paise

7. How much less is 25 km than 48.5 km?

8. Rani bought 3 kg 500 g apples and 5 kg 750g grapes. Raju bought 5 kg 450g mangoes and 6 kg 450g oranges. Who bought more fruits?

9. The side of an equilateral triangle is 5.5 cm. Find its perimeter.

a) 12.3 x 10 b) 3.45 x 100

11. The sum of two numbers is 100. If one number if 48.75, find the other number?

12. Write the reciprocal of each of the following fractions:

a) 3/5 b) 1/8

13. Which is greater?

a) 2.50 or 2.05 b) 0.7 or 0.77

14. Vijay walked 4.96 km on Monday and 3.86 km on Tuesday and some distance on Wednesday. If he travelled 10km on these three days, how much distance did he walked on Wednesday?

15. The length of a rectangle is 5.8 cm and its breadth is 3.5 cm. What is the area of the rectangle?

1. a) ½ of 24 = ½ x 24 = 12 b) ½ of 46 = ½ x 46 = 23

2. a) 2/3 of 18 = 2/3 x 18 = 36/3 = 12 b) 2/3 of 27 = 2/3 x 27 = 54/3 = 18

3. -4/5 = -4/5 x 3/3 = -12/15 -12/15 x 2/2 = -24/30 -2/3 = -2/3 x 5/5 = -10/15 -10/15 x 2/2 = -20/30. Three rational numbers between -4/5 and -2/3 are -23/30, -22/30, and -21/30.

4. 9/2 x -5/3 = -45/6 = -15/2.

5. Equivalent fractions of 2/3 are 2/3, 4/6, 6/9, 8/12, 10/15.

6.a) 5 paise = 0.05 rupees b) 235 paise = 2.35 rupees

7. 48.5 – 25 = 23.5 km

8. Weight of fruits bought by Rani = 3.500 + 5.750 = 9.250 kg Weight of fruits bought by Raju = 5.450 + 6.450 = 11.900 kg Therefore, Raju bought more fruits.

9. Perimeter = 3 x side = 3 x 5.5 = 16.5 cm

10. a) 12.3 x 10 = 123 b) 3.45 x 100 = 345

11. Sum of two numbers = 100 One number = 48.75 Other number = 100 – 48.75 = 51.25

12. a) 5/3 b) 8

13. a) 2.50 > 2.05 b) 0.77 >0.7

14. Distance walked on Monday = 4.96 km Distance walked on Tuesday = 3.86 km Total distance walked on Monday and Tuesday = 4.96 + 3.86 = 8.82 km Distance walked on Wednesday = 10 – 8.82 = 1.18 km

15. l = 5.8 cm B = 3.5 cm Area = l x b = 5.8 x 3.5 = 20.3 square cm.

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CBSE Class 7 Mathematics Chapter 2 - Fractions and Decimals with Important Questions - Free PDF Download

The important questions for class 7 maths chapter 2 are always available for the students right here. They can download a PDF version of all the questions along with their solutions from the different links which are provided right there. There is simply not a single speck of doubt about the fact that when it comes to class 7, it can be considered as a very important stage in the academic growth of the students. The students are on the verge of being introduced to new and interesting topics, especially in the subject of Mathematics. This is why having some extra questions for the class 7 maths fractions and decimals chapter can actually be a very good idea for them to be familiar with the concept. We are pretty sure that with the help of these questions, students can gain an insight into the chapter and hence will be able to perform in a better way in their examinations.

Vedantu is a platform that provides free CBSE Solutions (NCERT) and other study materials for students. Maths Students who are looking for better solutions, they can download Class 7 Maths NCERT Solutions to help you to revise the complete syllabus and score more marks in your examinations. Register Online for NCERT Solutions Class 7 Science tuition on Vedantu.com to score more marks in CBSE board examination.

Important Topics Under CBSE Class 7 Maths Chapter 2 - Fractions and Decimals

CBSE Class 7 Maths Chapter 2 - Fractions and Decimals will cover the following topics:

Addition and subtraction of fractions

Multiplication of fraction by a whole number and fraction

Division of fraction by a whole number and a fraction

Reciprocal of fraction

Multiplication and division of decimal numbers

Multiplication and division of decimal numbers by 10, 100 and 1000

Division of a decimal number by a whole number.

Study Important Questions for Class 7 Maths Chapter 2 - Fractions and Decimals

1 Mark Questions:

1. Convert the given fraction into mixed fraction \[\dfrac{{22}}{7}\].

Ans. A fraction can be written in the form of mixed fraction in the following way:

\[Q\dfrac{R}{D}\] , where Q is the quotient, R is the remainder and D is the divisor of the fraction.

So, \[\dfrac{{22}}{7}\] in mixed fraction form will be \[3\dfrac{1}{7}\] .

2. Write an equivalent fraction of \[\dfrac{9}{{15}}\].

Ans. To find an equivalent fraction, we simply multiply the numerator and denominator of the given fraction with the same number.

A fraction equivalent to \[\dfrac{9}{{15}}\] will be \[\dfrac{9}{{15}} \times \dfrac{2}{2} = \dfrac{{18}}{{30}}\] .

3. Find the value of \[3\dfrac{4}{7} \div 7\].

Ans. We solve the expression \[3\dfrac{4}{7} \div 7\] as follows:

\[ \Rightarrow \dfrac{{25}}{7} \div 7\]

\[ \Rightarrow \dfrac{{25}}{7} \times \dfrac{1}{7}\]

\[ \Rightarrow \dfrac{{25}}{{49}}\]

4. Express \[8\] rupee \[5\] paise in decimal.

Ans. \[8\] rupees and \[5\] paise in decimal form can be written as Rs. \[8.05\].

5. Write the place value of \[5\] in \[498.05\].

Ans. The place value of \[5\] in \[498.05\] is hundredths.

Refer to page 2 - 6 for 2 Mark Questions

6. Find the value of \[\dfrac{5}{6}\] of:

Ans. The value of \[\dfrac{5}{6}\] of \[30\] is:

\[\dfrac{5}{6} \times 30 = 25\]

(ii) \[54\]

Ans. The value of \[\dfrac{5}{6}\] of \[54\] is:

\[\dfrac{5}{6} \times 54 = 45\]

7. Multiply and reduce to lowest form:

(i) \[\dfrac{3}{8} \times \dfrac{4}{9}\]

Ans. Multiplying and simplifying \[\dfrac{3}{8} \times \dfrac{4}{9}\] :

\[ \Rightarrow \dfrac{{12}}{{72}}\]

\[ \Rightarrow \dfrac{1}{6}\]

(ii) \[\dfrac{{11}}{{10}} \times \dfrac{2}{5}\]

Ans. Multiplying and simplifying \[\dfrac{{11}}{{10}} \times \dfrac{2}{5}\] :

\[ \Rightarrow \dfrac{{22}}{{50}}\]

\[ \Rightarrow \dfrac{{11}}{{25}}\]

8. Multiply and express as mixed fractions:

(i) \[4 \times 6\dfrac{2}{3}\]

Ans. Solving the expression:

\[4 \times 6\dfrac{2}{3}\]

\[ \Rightarrow 4 \times \dfrac{{20}}{3}\]

\[ \Rightarrow \dfrac{{80}}{3}\]

\[ \Rightarrow 26\dfrac{2}{3}\]

(ii) \[3\dfrac{2}{3} \times 5\]

\[3\dfrac{2}{3} \times 5\]

\[ \Rightarrow \dfrac{{11}}{3} \times 5\]

\[ \Rightarrow \dfrac{{55}}{3}\]

\[ \Rightarrow 18\dfrac{1}{3}\]

(i) \[\dfrac{1}{3}\] of the ice creams in box:

Ans. There are total \[9\] ice creams in the box. We have to shade \[\dfrac{1}{3}\] , that is, \[\dfrac{1}{3} \times 9 = 3\] ice creams.

(ii) \[\dfrac{3}{4}\] of the apples in box:

Ans. There are a total of \[16\] apples in the box. We have to shade \[\dfrac{3}{4}\] , that is, \[\dfrac{3}{4} \times 16 = 12\] apples.

10. Sarah and Darshan went for a picnic. Their mother gave them a juice bottle of \[3\] litres.

Sarah consumed \[{\dfrac{1}{3}^{rd}}\] of the juice. Darshan consumed the rest.

(a) How much did Sarah drink?

Ans. Total quantity of juice in the bottle is \[3\] litres.

Sarah consumed \[{\dfrac{1}{3}^{rd}}\] of the juice, that is, \[\dfrac{1}{3} \times 3 = 1\] litre.

(b) What fraction of the total quantity did Darshan drink?

Ans. Darshan consumed \[1 - \dfrac{1}{3} = \dfrac{2}{3}\] of the total juice.

(i) \[\dfrac{2}{9} \div 4\]

Ans. Solving:

\[\dfrac{2}{9} \div 4\]

\[ \Rightarrow \dfrac{2}{9} \times \dfrac{1}{4}\]

\[ \Rightarrow \dfrac{2}{{36}}\]

\[ \Rightarrow \dfrac{1}{{18}}\]

(ii) \[\dfrac{{11}}{7} \div 2\]

\[\dfrac{{11}}{7} \div 2\]

\[ \Rightarrow \dfrac{{11}}{7} \times \dfrac{1}{2}\]

\[ \Rightarrow \dfrac{{11}}{{14}}\]

(i) \[\dfrac{{12}}{7} \div \dfrac{3}{{14}}\]

\[\dfrac{{12}}{7} \div \dfrac{3}{{14}}\]

\[ \Rightarrow \dfrac{{12}}{7} \times \dfrac{{14}}{3}\]

\[ \Rightarrow \dfrac{{168}}{{21}}\]

\[ \Rightarrow 8\]

(ii) \[\dfrac{2}{5} \div \dfrac{4}{5}\]

\[\dfrac{2}{5} \div \dfrac{4}{5}\]

\[ \Rightarrow \dfrac{2}{5} \times \dfrac{5}{4}\]

\[ \Rightarrow \dfrac{2}{4}\]

\[ \Rightarrow \dfrac{1}{2}\]

13. Which is greater:

(i) \[{\bf{0}}.{\bf{02}}\] or \[{\bf{0}}.{\bf{2}}\]

Ans. We convert the decimals into equivalent fractions:

\[0.02 = \dfrac{2}{{100}}\] and \[0.2 = \dfrac{{20}}{{100}}\]

On comparing, we conclude that \[\dfrac{{20}}{{100}} > \dfrac{2}{{100}}\] .

Hence, \[0.2\] is greater.

(ii) \[1.98\] or \[1.98\]

\[1.98 = \dfrac{{198}}{{100}}\] and \[1.89 = \dfrac{{189}}{{100}}\]

On comparing, we conclude that \[\dfrac{{198}}{{100}} > \dfrac{{189}}{{100}}\] .

Hence, \[1.98\] is greater.

14. How much \[5.6\] kg is less than \[9.4\] kg?

Ans. Calculating the difference:

\[9.4 - 5.6 = 3.8\] kg

Hence, \[5.6\] kg is \[3.8\] kg less than \[9.4\] kg.

(i) \[1.08 \times 0.3\]

Ans. Converting into fractions and solving:

\[1.08 \times 0.3\]

\[ \Rightarrow \dfrac{{108}}{{100}} \times \dfrac{3}{{10}}\]

\[ \Rightarrow \dfrac{{324}}{{1000}}\]

\[ \Rightarrow 0.324\]

(ii) \[158.3 \times 2.9\]

\[158.3 \times 2.9\]

\[ \Rightarrow \dfrac{{1583}}{{10}} \times \dfrac{{29}}{{10}}\]

\[ \Rightarrow \dfrac{{45907}}{{100}}\]

\[ \Rightarrow 459.07\]

3 Mark Questions

16. Arrange in ascending order \[\dfrac{3}{5},\dfrac{4}{7},\dfrac{3}{{10}},\dfrac{4}{5}\] .

Ans. To arrange given fractions in ascending order, we first make their denominators equivalent.

L.C.M. of all the denominators \[5,7,10\] is \[70\] .

\[\dfrac{3}{5} \times \dfrac{{14}}{{14}} = \dfrac{{42}}{{70}}\]

\[\dfrac{4}{7} \times \dfrac{{10}}{{10}} = \dfrac{{40}}{{70}}\]

\[\dfrac{3}{{10}} \times \dfrac{7}{7} = \dfrac{{21}}{{70}}\]

\[\dfrac{4}{5} \times \dfrac{{14}}{{14}} = \dfrac{{56}}{{70}}\]

Now, \[\dfrac{{21}}{{70}} < \dfrac{{40}}{{70}} < \dfrac{{42}}{{70}} < \dfrac{{56}}{{70}}\] .

Hence, \[\dfrac{3}{{10}} < \dfrac{4}{7} < \dfrac{3}{5} < \dfrac{4}{5}\] .

17. Find the perimeter of the rectangle whose length is \[7\dfrac{3}{{10}}\] cm and breadth is \[\dfrac{3}{5}\] cm.

Ans. We know that the perimeter of a rectangle is twice the sum of its length and breadth, that is, \[2(l + b)\] .

\[ \Rightarrow 2(7\dfrac{3}{{10}} + \dfrac{3}{5})\]

\[ \Rightarrow 2(\dfrac{{73}}{{10}} + \dfrac{6}{{10}})\]

\[ \Rightarrow 2(\dfrac{{79}}{{10}})\]

\[ \Rightarrow \dfrac{{79}}{5}\]

\[ \Rightarrow 15\dfrac{4}{5}\] cm

18. Find \[\dfrac{3}{7}\] of:

(i) \[3\dfrac{5}{8}\]

Ans. The value of \[\dfrac{3}{7}\] of \[3\dfrac{5}{8}\] is:

\[\dfrac{3}{7} \times 3\dfrac{5}{8} = \dfrac{3}{7} \times \dfrac{{29}}{8}\]

\[ \Rightarrow \dfrac{{87}}{{56}}\]

\[ \Rightarrow 1\dfrac{{31}}{{56}}\]

(ii) \[4\dfrac{3}{9}\]

Ans. The value of \[\dfrac{3}{7}\] of \[4\dfrac{3}{9}\] is:

\[\dfrac{3}{7} \times 4\dfrac{3}{9} = \dfrac{3}{7} \times \dfrac{{39}}{9}\]

\[ \Rightarrow \dfrac{{13}}{7}\]

\[ \Rightarrow 1\dfrac{6}{7}\]

(i) \[3\dfrac{1}{8} \div 2\dfrac{1}{4}\]

\[3\dfrac{1}{8} \div 2\dfrac{1}{4}\]

\[ \Rightarrow \dfrac{{25}}{8} \times \dfrac{4}{9}\]

\[ \Rightarrow \dfrac{{25}}{{18}}\]

\[ \Rightarrow 1\dfrac{7}{{18}}\]

(ii) \[4\dfrac{4}{3} \div 6\dfrac{1}{2}\]

\[4\dfrac{4}{3} \div 6\dfrac{1}{2}\]

\[ \Rightarrow \dfrac{{16}}{3} \times \dfrac{2}{{13}}\]

\[ \Rightarrow \dfrac{{32}}{{39}}\]

20. Write the following decimal number in expanded form:

(i) \[208.183\]

Ans. In expanded form, the given decimal can be written as:

\[(2 \times 100) + (0 \times 10) + (8 \times 1) + (1 \times \dfrac{1}{{10}}) + (8 \times \dfrac{1}{{100}}) + (3 \times \dfrac{1}{{1000}})\]

(ii) \[5.018\]

\[(5 \times 1) + (0 \times \dfrac{1}{{10}}) + (1 \times \dfrac{1}{{100}}) + (8 \times \dfrac{1}{{1000}})\]

(iii) \[360.05\]

\[(6 \times 100) + (3 \times 10) + (0 \times 1) + (0 \times \dfrac{1}{{10}}) + (5 \times \dfrac{1}{{100}})\]

CBSE Class 7 Maths Chapter - 2 Important Questions - Free PDF Download

Download extra questions for class 7 maths fractions and decimals from here .

We have a collection of all the different types of questions that are available in the class 7 maths chapter 2. This chapter has a lot of interesting questions that will draw the attention of the students. They can practice those questions online or actually download the PDF version that is provided right here. While learning all about the facts of the chapter is important, students also need to have some help regarding the class 7 maths chapter 2 important questions. This is where we come to help them out in the best way.

In chapter 2 of class 7 maths, students will get to know about different topics related to decimals and fractions. There are some very important techniques that they will be able to learn from the chapter. Having the assistance of class 7 important questions for maths fractions and decimals surely is going to be a great help for them.

Students can get familiar with the concepts of subtraction and addition of different fractions. Along with that, they will also learn about multiplying fractions with whole numbers and other fractions as well. Techniques of division and finding reciprocals will also be taught in the chapter. There are many exercises in the chapter and students need to find out the class 7 maths important questions Ch 2 from there. We have absolutely no doubt about the fact that once students find out the important questions, they will surely have no trouble in understanding the concepts and hence will be able to prepare well for their final exams. Clearing out the basics is essential during the starting stages of studying and this is exactly what students are going to learn from these chapters.

Why Choose Our Services To Have Class 7th Maths Chapter 2 Important Questions?

When it comes to preparing for the exams and having some sort of revision, one of the most important questions that students ask is how can they find the class 7th maths chapter 2 important questions. Well, all of the important questions are provided right here at Vedantu. With the help of our expert teachers and professors, we have managed to create a list of different important questions for the 2nd chapter of maths class 7. Students need to make sure that they are practicing these questions long enough so that they can get the hang of it in the best way. These questions have solutions that are step-wise and hence will be very easy to understand for sure. We definitely urge you to choose important questions for class 7 maths chapter 2.

Benefits of CBSE Class 7 Maths Important Questions

There are several benefits of solving CBSE Class 7 Maths Important Questions. They are:

These important questions are made by our experts referring to the CBSE syllabus, therefore, solving the CBSE Class 7 Maths Important Questions will help you to be more clear with the Math topics, formulas, and concepts.

These questions will help you prepare for the examination and you will be able to self-analyse your mistakes and work on them.

Solving these important questions will boost your confidence and you will be able to solve any sum easily.

CBSE Class 7 Maths Important Questions available at Vedantu are solved by our experts with 100% accuracy, therefore, you can completely rely on them for your preparation.

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Conclusion

Vedantu's collection of Important Questions for CBSE Class 7 Maths Chapter 2 - Fractions and Decimals proves to be an invaluable resource for students seeking comprehensive understanding and proficiency in this fundamental subject. With meticulous curation and a focus on core concepts, the platform equips learners with a diverse set of questions that foster critical thinking and problem-solving skills. By addressing the intricacies of fractions and decimals, Vedantu empowers students to tackle complex mathematical challenges with confidence. The interactive and engaging nature of the material ensures an enjoyable learning experience, encouraging students to excel academically and build a strong foundation for future mathematical endeavors. Vedantu's commitment to educational excellence shines through this well-crafted resource.

FAQs on Important Questions for CBSE Class 7 Maths Chapter 2 - Fractions and Decimals

1. Do I need to practise all the questions provided in Chapter 2 of Class 7 Maths?

Ans: Practising all the questions provided in NCERT Solutions of Chapter 2 of Class 7 Maths ensures clear concepts and understanding of the applications of the various methods in solving the sums. Fractions and Decimals is a short chapter with a fair weightage in the exam. Hence, it is essential to grasp all the topics covered in this chapter to be well prepared and for better learning, regular practice is extremely important.

2. How many questions are there in NCERT Solutions Chapter 2 of Class 7 Maths?

Ans: Chapter 2 of Class 7 Maths has a total of six exercises with 42 questions. These questions are divided unevenly based on different methods for multiplication and division of fractions and decimals. Long questions have multiple steps that the students need to ensure are correct because each step holds some marks in the examinations. It is suggested that you make a habit of rechecking the solution while at the learning stage so you make fewer errors.

3. Where can I find ‘Important Questions’ for Chapter 2 of Class 7 Maths?

Ans: Vedantu provides you with important questions PDF free of cost. These questions include all the methods by which you can solve all the problems given in this particular chapter. You can also download the PDF of important questions, notes and other study materials from Vedantu website and mobile app. The important questions are the best way to prepare if you are running short on time since they cover all the fundamental topics and formulas.

4. How are ‘Important Questions’ for Chapter 2 of Class 7 Maths helpful?

Ans: Solving the important questions establishes basic clarity on the application for each type of problem in the chapter. It helps you revise better around the exams so you do not miss out on any kind of question that may be vital with respect to the exam. In case you are late in starting your preparation you can easily solve the important question to cover the majority of the course in a short span of time.

5. How should I prepare Chapter-Fractions and Decimals for Class 7 Maths?

Ans: Fractions and decimals in Class 7 is a relatively simple chapter. You should focus on learning the methods used in solving the questions. The chapter helps you revise the addition and subtraction of fractions and decimals and further introduces multiplication and division of the same. Practicing all problems is the easiest way to prepare the chapter. Right before the exams is a time crunch for the students so, these important questions come in handy at the time.

Chapterwise Important Questions for CBSE Class 7 Maths

Cbse study materials.

RS Aggarwal Solutions Class 7 Chapter 3 Decimals

RS Aggarwal Solutions for Class 7 Maths Chapter 3 Decimals are available here. This chapter has a total of six exercises. Study path has prepared solutions to these exercises by our expert math teachers to help you to get good marks in exams. RS Aggarwal Solutions for Class 7 Chapter 3 has a ton of questions. We at Study Path solved each questions step by step with detailed explanations. Students must practice from practice these problems to score high marks in Maths.

Class 7 RS Aggarwal Solutions Chapter 3 Decimals

Class 7 rs aggarwal solutions chapter 3 ex 3a.

RS Aggarwal Solutions Class 7 Chapter 3 Decimals Exercise 3A 00001

Class 7 RS Aggarwal Solutions Chapter 3 Ex 3B

RS Aggarwal Solutions Class 7 Chapter 3 Decimals Exercise 3B 0001

Class 7 RS Aggarwal Solutions Chapter 3 Ex 3C

RS Aggarwal Solutions Class 7 Chapter 3 Decimals Exercise 3C 001

Class 7 RS Aggarwal Solutions Chapter 3 Ex 3D

RS Aggarwal Solutions Class 7 Chapter 3 Decimals Exercise 3D 00001

Class 7 RS Aggarwal Solutions Chapter 3 Ex 3E

RS Aggarwal Solutions Class 7 Chapter 3 Decimals Exercise 3E MCQs 0001

Class 7 RS Aggarwal Solutions Chapter 3 Test Paper

RS Aggarwal Solutions Class 7 Chapter 3 Decimals Test Paper 00001

Chapter Brief of Chapter 3 Decimals Class 7 RS Aggarwal Solutions

Below we have summarised the topics that have been discussed in this chapter.

Method of Converting a Decimal into a Fraction
Converting a Fraction into Decimal
Addition and Subtraction of Decimals
Addition of Decimals
Subtraction of Decimals
Multiplication of Decimals
Multiplication of a Decimal by 10, 100, 1000, etc.
Multiplication of a Decimal by a Whole Number
Multiplication of a Decimal by a Decimal
Division of Decimals
Dividing a Decimal By a Whole Number

We at Study Path work hard to provide you with the best solutions and study materials for free. We hope these solutions help you in your studies. Now, if have any doubts on RS Aggarwal Class 7 Solutions, please Comment below. We will definitely try to help you with this.

LetsPlayMaths.Com

Class vii math, class 7 - decimals worksheet 1.

1. Convert 7348 ⁄ 100 into decimal. a) 734.8 b) 73.48 c) 743.8 d) 7.348

2. Convert 823 ⁄ 100000 into decimal. a) 8.23 b) 832.000 c) 0.00823 d) 0.0823

3. What is the number of decimal places in 8.02456? a) 5 b) 3 c) 2 d) 6

4. Convert 32.35 into fraction. a) 3235 ⁄ 100 b) 3235 ⁄ 10 c) 3235 ⁄ 10000 d) 3235 ⁄ 1000

5. convert 5 9 ⁄ 12 into decimal fraction. a) 0.75 b) 57.5 c) 035 d) 5.75

6. 5.4 + _____ = 20.9. a) 2.6 b) 15.5 c) 1.2 d) 20

7. 25.63 + 6.5 − 2.3 = _______. a) 21.45 b) 15.42 c) 29.83 d) 38.29

8. 22.356 − 131.6 + 23.5 + 689.4 = ______. a) 569.53 b) 4563.2 c) 603.656 d) 632.56

9. The cost of one kg salt increases from 28.47 to 39.45. find the increases in cost. a) 9.26 b) 10.98 c) 1.98 d) 25.45

10. 0.095 ÷ 10 = _____. a) 0.095 b) 0.95 c) 9.5 d) 0.0095

11. Evaluate 0.3 × 3.6 × 0.9 = _____. a) 9.72 b) 0.972 c) 97.2 d) 18.2

12. The cost of one dozen egg is 93.6 rupees. Find the cost of each egg. a) 7.8 b) 20.2 c) 5.63 d) 96.4

13. Simplify to the nearest hundredth 18.35 × 1.2 = _____. a) 2.202 b) 220.2 c) 22.02 d) 2.200

14. Convert 0.245 into a fraction in its simplest form. a) 15 ⁄ 20 b) 256 ⁄ 100 c) 49 ⁄ 200 d) None of these

15. Express 634 paise into rupees using decimal. a) Rs. 6.34 b) Rs. 64.3 c) Rs. 63.4 d) Rs. 643.2

16. Express 65 metre into kilometre. a) 6.5 Km. b) 65.00 Km. c) 5.10 Km. d) 0.065 Km.

17. How much less is 40.35 km than 89.2 km? a) 48.85 Km. b) 40.21 Km. c) 47.23 Km. d) 41.21 Km.

18. Find the average of 23.6, 41.6, 2.8, 32.4. a) 48.2 b) 76.1 c) 25.12 d) 22.12

19. 0.008 = _____. a) 4 ⁄ 500 b) 8 ⁄ 10 c) 4 ⁄ 50 d) 20 ⁄ 122

20. 1.1 + 3.2 × 5.0 = _____. a) 20.21 b) 18.23 c) 17.1 d) 12.1

If you want to download the above worksheet, please click below link.

Decimals Worksheet-1 Download the pdf

Decimals Worksheet - 1

Decimals Worksheet - 2

Decimals Worksheet - 3

Decimals Worksheet - 4

Answer Sheet

Decimals-Answer Download the pdf

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CBSE Important Questions Class 7 Maths Chapter 2

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Important Questions Class 7 Mathematics Chapter 2 – Fractions and Decimals

Mathematics is an important subject that you study in school. We need Mathematics in our daily life too. In this chapter, you will learn about decimals and fractions more elaborately. In Class 6, students have learned about fractions and decimals.

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Chapter 2 of Class 7 Mathematics under the CBSE curriculum deals with the addition or multiplication of decimals and fractions. Students must practice questions from the chapter as much as possible. They may take help from other sources because the textbook exercises have limited questions.

Extramarks is a leading company in the educational sector. Our experts have made the Important Questions Class 7 Mathematics Chapter 2 to help students to solve the questions regularly. They have collated the questions from different sources such as the CBSE sample papers, CBSE past years’ question papers, the textbook exercises, NCERT exemplars and important reference books. They have solved the questions too.

Extramarks provides all the important study materials related to CBSE and NCERT. You can download the study materials after registering on our official website. We provide CBSE syllabus, CBSE sample papers, CBSE past years’ question papers, CBSE extra questions, CBSE revision notes, NCERT books, NCERT exemplars, NCERT solutions, NCERT important questions, vital formulas and many more.

Fraction Questions for Class 7 – With Solutions

The subject matter of Extramarks has made the question series so that students can regularly solve questions from the chapter. They have taken help from the textbook exercises, CBSE sample papers, CBSE past years’ question papers, NCERT exemplars and important reference books. They have solved the questions, and experienced professionals have further checked the answers to ensure the best quality of the content. Thus. The Important Questions Class 7 Mathematics Chapter 2 will help students to score better in exams. The important questions are-

Question 1. Ritu ate at least (3/5) part of an apple, and then the remaining apple was eaten by ritu’s brother Shyam. How many parts of the apple did Shyam eat? Who had the larger share? And By how much?

From the above question, it is given that,

The part of apple eaten by Ritu is equal to (3/5)

And the part of apple eaten by Shyam is = 1 – the part of apple eaten by Ritu is?

= 1 – (3/5)

The LCM of numbers 1 and 5 is = 5

Now, let us change these given fractions into an equivalent fraction by taking ten as the denominator number.

= [(1/1) × (5/5)] – [(3/5) × (1/1)]

= (5/5) – (3/5)

= (5 – 3)/5

Hence the part of apple eaten by Shyam is (2/5)

So, (3/5) is greater than (2/5); hence, Ritu ate the larger apple.

Now, the difference between the shares is = (3/5) – (2/5)

= (3 – 2)/5

Thus, Ritu’s share is greater than the share of Shyam by (1/5)

Question 2. Michae finished colouring a picture on (7/12) hour. On the other hand, Vaibhav finished colouring the same picture in (3/4) hour. Who worked longer colouring the picture? By what fraction was it longer?

Time taken by Michae to colour the picture is = (7/12)

Time taken by Vaibhav to colour the picture is = (3/4)

The LCM of numbers 12, 4 = 12

Now, let us change these given fractions into an equivalent fractions by using 12 as the denominator number.

(7/12) = (7/12) × (1/1) = 7/12

The same method is applied to,

(3/4) = (3/4) × (3/3) = 9/12

As seen, (7/12) is less than (9/12)

Hence, (7/12) < (3/4)

Thus, Vaibhav worked for a longer time as compared.

Now, Vaibhav worked longer time by = (3/4) – (7/12)

= (9/12) – (7/12)

= (9 – 7)/12

= (1/6) of an hour.

Question 3. Vidya and Pratik went on a picnic. Their mother gave them a mineral water bottle that contained 5 litres of water. Vidya consumed around 2/5 of the water, and Pratik consumed the remaining water.

(i) How many litres of water did Vidya drink?

(ii) And What fraction of the total quantity of water did Pratik drink?

(i) From the above question, it is given that,

The amount of water in the water bottle is = 5 litres.

The amount of water consumed by Vidya is = 2/5 of 5 litres.

= (2/5) × 5

Hence, the total amount of water drank by Vidya is 2 litres.

(ii) From the above question, it is given that,

Amount of water present in the water bottle = 5 litres

The amount of water consumed by Pratik = (1 – water consumed by Vidya)

= (1 – (2/5))

Hence the Total Amount of water consumed by Pratik = is 3/5 of 5 litres.

= (3/5) × 5

So, the total amount of water consumed by Pratik is 3 litres.

Question 4. Which of the following is greater:

(i) (2/7) of (3/4) or the fraction (3/5) of (5/8)

We have seen that,

= (2/7) × (3/4) and the (3/5) × (5/8)

Hence, By the rule of Multiplication of the fraction,

The product of fraction is equal to (product of numerator)/ (product of denominator)

= (2/7) × (3/4)

= (2 × 3)/ (7 × 4)

= (1 × 3)/ (7 × 2)

= (3/14) … [i]

= (3/5) × (5/8)

= (3 × 5)/ (5 × 8)

= (3 × 1)/ (1 × 8)

= (3/8) … [ii]

Now, convert the [i] and [ii] into like fractions,

LCM of 14 and 8 become 56

Now, let us change each of these given fractions into an equivalent fraction that has 56 as its denominator number.

[(3/14) × (4/4)] is equal to (12/56) [(3/8) × (7/7)] = (21/56)

Clearly, it is seen,

(12/56) is less than (21/56)

(3/14) is less than (3/8)

(ii) (1/2) of (6/7) or the (2/3) of (3/7)

= (1/2) × (6/7) and the (2/3) × (3/7)

By the rule of Multiplication of the fraction,

Product of fraction = (product of numerator) divided by (product of denominator)

= (1/2) × (6/7)

= (1 × 6)/ (2 × 7)

= (1 × 3)/ (1 × 7)

= (3/7) … [i]

= (2/3) × (3/7)

= (2 × 3)/ (3 × 7)

= (2 × 1)/ (1 × 7)

= (2/7) … [ii]

By comparing [i] and [ii],

(3/7) > (2/7)

Question 5. Saili plants four saplings successively in a row in her garden. The distance between the two adjacent saplings is ¾ m. Now Find the distance between the first and the last planted sapling.

The distance between the two adjacent saplings is = ¾ m

The number of saplings which are planted by Saili in a row is = 4

Then, the number of the gap in the saplings = ¾ × 4

Hence The total distance between the first and the last saplings becomes = three × ¾

Thus, the distance between the first and the last saplings is two ¼ m.

Question 6. Lipika always reads a book for one ¾ hour every day. She reads an entire book in 6 days. How many hours in total were required by her to finish the book?

From the above question, it is clearly given that,

Lipika reads her book for = one ¾ hours every day, which is equal to 7/4 hours for six days.

The number of days she took to finish the entire book = was six days

Hence, the Total number of hours required by her to fully complete the book = (7/4) × 6

= (7/2) × 3

= 10 ½ hours

Thus, the total number of hours required by her to complete the book is 10 ½ hours.

Question 7. A car runs around 16 km using 1 litre of petrol. How much distance will the car cover use two ¾ litres of petrol?

Answers 7:-

The total distance travelled by car in 1 litre of petrol is = 16 km.

The Total quantity of petrol becomes = two ¾ litre = 11/4 litres

The total distance travelled by car in 11/4 litres of petrol is = (11/4) × 16

Hence, the total distance travelled by car in 11/4 litres of petrol is 44 km.

Question 8. Find the reciprocal of each of these following fractions. Also, Classify these reciprocals as proper fractions, improper fractions and whole numbers.

Reciprocal of (3/7) is (7/3) [which is ((3/7) × (7/3)) = 1]

So, it is an improper fraction.

An improper fraction is defined as a fraction in which the numerator is always greater than its denominator.

Reciprocal of (5/8) is (8/5) [which is ((5/8) × (8/5)) = 1]

So, it is also an improper fraction.

An improper fraction is defined as a fraction in which the numerator is greater than its denominator.

Reciprocal of (9/7) is (7/9) [which is ((9/7) × (7/9)) = 1]

Hence, it is a proper fraction.

A proper fraction is defined as that fraction in which the denominator is greater than the numerator of their fraction.

Reciprocal of (6/5) is (5/6) [which is ((6/5) × (5/6)) = 1]

A proper fraction is defined as a fraction in which the denominator is greater than the numerator of any fraction.

Reciprocal of (12/7) is (7/12) [which is ((12/7) × (7/12)) = 1]

A proper fraction is defined as a fraction in which the denominator is greater than the numerator of the given fraction.

Reciprocal of the fraction (1/8) is (8/1) or 8 as [∵ ((1/8) × (8/1)) = 1]

Hence, it is a whole number.

Whole numbers are the total collection of all positive integers, including the number 0.

Reciprocal of the fraction (1/11) is (11/1) or 11 which is [∵ ((1/11) × (11/1)) = 1]

So, it is a whole number.

Whole numbers are the total collection of all positive integers, including 0.

Question 9. Find:

(i) (7/3) ÷ 2

Answer 9:-

= (7/3) × reciprocal of 2

= (7/3) × (1/2)

= (7 × 1) / (3 × 2)

(ii) (4/9) ÷ 5

= (4/9) × reciprocal of 5

= (4/9) × (1/5)

= (4 × 1) / (9 × 5)

(iii) (6/13) ÷ 7

= (6/13) × reciprocal of 7

= (6/13) × (1/7)

= (6 × 1) / (13 × 7)

Question 10. Which of the following is greater?

(i) 0.5 or 0.05

Answer 10:-

By comparing the whole number, we get 0 = 0

By comparing the tenths place digit, we get 5 > 0

∴ 0.5 > 0.05

(ii) 0.7 or 0.5

By comparing the whole number, 0 = 0

By comparing the tenths place digit we receive, 7 > 5

∴ 0.7 > 0.5

(iii) 7 or 0.7

By comparing these whole numbers, 7 > 0

∴ 7 > 0.7

(iv) 1.37 or 1.49

By comparing these whole numbers, 1 = 1

By comparing the tenths place digit, we get, 3 < 4

∴ 1.37 < 1.49

(v) 2.03 or 2.30

By comparing the whole number, 2 = 2

By comparing the tenths place digit, we get, 0 < 3

∴ 2.03 < 2.30

(vi) 0.8 or 0.88

By comparing these whole numbers, 0 = 0

By comparing the tenths place digit, we get, 8 = 8

Also, by comparing the hundredths place digit, 0 < 8

∴ 0.8 < 0.88

Question 11. Express as rupees as decimals:

(i) 7 paise

Answer 11:-

We know that,

= ₹ 1 = 100 paise

= 1 paise = ₹ (1/100)

∴ 7 paise = ₹ (7/100)

(ii) 7 rupees 7 paise

∴ 7 rupees 7 paise = ₹ 7 + ₹ (7/100)

= ₹ 7 + ₹ 0.07

(iii) 77 rupees 77 paise

∴ 77 rupees 77 paise = ₹ 77 + ₹ (77/100)

= ₹ 77 + ₹ 0.77

(iv) 50 paise

∴ 50 paise = ₹ (50/100)

(v) 235 paise

∴ 235 paise = ₹ (235/100)

Question 12. (i) Express 5 centimeters in meter and kilometre

Answer 12:-

We all know that,

= 1 meter = 100 centimeter

= 1 cm = (1/100) meter

= 5 cm = (5/100)

= 1 km = 1000 meter

= 1 m = (1/1000) kilometer

= 0.05 m = (0.05/1000)

= 0. 00005 kilometer

(i) Express 35 mm in cm, m and km

= 1 cm = 10 mm

= 1 mm = (1/10) cm

= 35 mm = (35/10) cm

= 1 meter = 100 cm

= 1 cm = (1/100) m

= 3.5 cm = (3.5/100) m

= (35/1000) m

= 1 km = 1000 m

= 1 m = (1/1000) km

= 0.035 m = (0.035/1000)

= 0. 000035 km

Question 13. Express in kilogram:

(i) 200 gram

Answer 13:-

= 1 kg = 1000 gram

= 1 g = (1/1000) kg

= 200 g = (200/1000) kilogram

(ii) 3470 gram

= 1 g = (1/1000) kilogram

= 3470 g = (3470/1000) kilogram

= (3470/100)

(ii) 4 kg 8 g

= 4 kg 8 g is equal to 4 kg + (8/1000) kilogram

= 4 kg + 0.008

= 4.008 kilogram

Question 14 . Write the following in decimal numbers in their expanded form:

Answer 14:-

We have that,

20.03 = (2 × 10) + (0 × 1) + (0 × (1/10)) + (3 × (1/100))

2.03 is equal to (2 × 1) + (0 × (1/10)) + (3 × (1/100))

(iii) 200.03

200.03 is (2 × 100) + (0 × 10) + (0 × 1) + (0 × (1/10)) + (3 × (1/100))

2.034 gets equal to (2 × 1) + (0 × (1/10)) + (3 × (1/100)) + (4 × (1/1000)).

Question. Write the place value of 2 in the following decimal numbers:

From the above question, we can observe that,

The place value of 2 in the decimal 2.56 is ones.

The place value of 2 in the decimal 21.37 is tens.

(iii) 10.25

The place value of 2 in the decimal 10.25 is tenths.

The place value of 2 in the decimal 9.42 is the hundredth.

The place value of 2 in the decimal 63.352 is the thousandth.

Question 15. Shyama bought around 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala then bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?

Answer 15:-

Fruits bought by Shyama is = 5 kg 300 g

= 5 kg + (300/1000) kg

= 5 kg + 0.3 kg

Fruits bought by Sarala is = 4 kg 800 g + 4 kg 150 g

= (4 + (800/1000)) + (4 + (150/1000))

= (4 + 0.8) kg + (4 + .150) kg

= 4.8 kg + 4.150kg

So, Sarala bought more fruits.

Question 16. How much less is 28 km as compared to 42.6 km?

Answer 16:-

Now, we have to find the difference between 42.6 km and 28 km.

Hence, 14.6 km less is 28 km than 42.6 km.

Question 17. Find:

(i) 1.3 × 10

Answer 17:-

On multiplying the decimal by 10, the decimal point is shifted to the right by one place.

= 1.3 × 10 = 13

(ii) 36.8 × 10

n multiplying the decimal by 10, the decimal point is shifted to the right by one place.

= 36.8 × 10 = 368

(iii) 153.7 × 10

= 153.7 × 10 = 1537

(iv) 168.07 × 10

= 168.07 × 10 = 1680.7

(v) 31.1 × 100

On multiplying the decimal by 100, the decimal point is shifted to the right by two places.

= 31.1 × 100 = 3110

(vi) 156.1 × 100

= 156.1 × 100 = 15610

(vii) 3.62 × 100

On multiplying a decimal by the number 100, the decimal point is shifted to the right by two places.

= 3.62 × 100 = 362

(viii) 43.07 × 100

= 43.07 × 100 = 4307

Question 18. A two-wheeler covers a total distance of 55.3 km in one litre of petrol. How much total distance will it cover in 10 litres of petrol?

Answer 18:-

Distance covered by the two-wheeler in 1L of petrol = 55.3 km

Distance covered by the two-wheeler in 10L of petrol is = (10 × 55.3)

Hence the Two-wheeler covers a distance of 10L of petrol 553 km.

Question 19. Find the following:

(a) 2.5 × 0.3

Answer 19:-

= (25/10) × (3/10)

On dividing the decimal by 100, the decimal point is shifted to the left by two places.

(b) 0.1 × 51.7

= (1/10) × (517/10)

= (517/100)

= (2/10) × (3168/10)

= (6336/100)

(d) 1.3 × 3.1

= (13/10) × (31/10)

= (403/100)

Question 20. Find:

(i) 7 ÷ 3.5

= 7 ÷ (35/10)

= 7 × (10/35)

= 1 × (10/5)

(ii) 36 ÷ 0.2

= 36 ÷ (2/10)

= 36 × (10/2)

(iii) 3.25 ÷ 0.5

= (325/100) ÷ (5/10)

= (325/100) × (10/5)

= (325 × 10)/ (100 × 5)

= (65 × 1)/ (10 × 1)

Benefits of Solving Important Questions Class 7 Mathematics Chapter 2

Practice is very important for students. It helps them to clear their doubts and strengthen their concepts. Often, students need more than textbook exercises. They may take help from the chapter-wise question series made by our professionals. They have collected the questions from several sources and given the solutions in the Class 7 Mathematics Chapter 2 Important Questions , and there will be multiple benefits to solving these questions. These are-

Sometimes, students need more than textbook exercises. They would need help to search for questions from different sources. The experts have made the task easier for the students. They collected questions from the CBSE sample papers, NCERT textbook exercises, NCERT exemplars and important reference books. Apart from this, they have included a few questions from CBSE past years’ question papers. Thus, students will find the vital questions in one single pdf.
The experts have not only included the questions, but they have solved the questions too. They have given a step-step process to solve the problems. Thus, the students can follow the solutions if they cannot solve the questions. Experienced professionals have further checked the answers to ensure the best quality of the content. Thus, the Mathematics Class 7 Chapter 2 Important Questions will also help the students to solve the questions. It will boost their confidence and generate their interest in the subject matter.
The habit of practice is very important for students. They must solve questions regularly to strengthen their concepts of the subject matter. The experts have tried to include all the important concepts in this article. Thus, the Important Questions Class 7 Mathematics Chapter 2 will help students in several ways. It will clear their doubts and strengthen their concepts. Thus, it will help them to score better in exams. Some students are scared of this subject. It is because they need help understanding the concepts clearly. This question series will help them greatly because they can follow the solutions and learn how to solve the sums.

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What is the value of the following expression? 0 .1 0 .01 + 0 .01 0 .1

Ans Option1 Explanation

0 .1 0 .01 + 0 .01 0 .1 = 10 + 1 10 = 10 + 0 .1 = 10 .1

Q.2 What is the value of 10.05 × 1.05?

Ans Option2 Explanation

1005 × 105 = 105525

Since 10.05 has 2 digits and 1.05 has 2 digits after the decimal point, therefore, the product must have 4 digits after decimal point.

10.05 × 1.05 = 10.5525

Q.3 Bob has given half of the whole cake to his sister Maria. Maria further divided it into three parts, ate only one part and kept the rest two parts in the fridge for later. What part of the whole cake has she kept in the fridge?

Share= 1 2 The part which Maria ate = 1 2 ÷ 3 Remaining part = 1 2 − 1 6 = 3 − 1 6 = 2 6 = 1 3

4 + 3 5 − 2 7

Marks: 1 Ans

L.C.M of 1, 5, 7 = 35

∴ 4 + 3 5 − 2 7 = 140 + 21 − 10 35 = 151 35

Q.5 What is the expanded form of 205.149?

2 × 1000 + 0 × 100 + 5 × 10 + 1 × 1 10 + 4 × 1 100 + 9 × 1 1000 2 × 100 + 0 × 10 + 5 × 1 + 1 × 1 + 4 × 1 10 + 9 × 1 100 1 × 100 + 4 × 10 + 9 × 1 + 2 × 1 10 + 0 × 1 100 + 5 × 1 1000 2 × 100 + 0 × 10 + 5 × 1 + 1 × 1 10 + 4 × 1 100 + 9 × 1 1000

Ans Option4 Explanation

The expanded form of 205 .149 is: 2 × 100 + 0 × 10 + 5 × 1 + 1 × 1 10 + 4 × 1 100 + 9 × 1 1000

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Faqs (frequently asked questions), 1. what is the content of chapter 2 class 7 mathematics.

Chapter 2 of Class 7 Mathematics deals with the addition, subtraction, multiplication and division of fractions and decimals. Students are familiar with decimals and fractions but have yet to study how to perform different mathematical relations between fractions or decimals. The chapter is relatively easy for students; they can easily understand the subject matter if they follow the textbook exercises seriously. They can also take help from the Important Questions Class 7 Mathematics Chapter 2 by the experts of Extramarks. They can also follow the questions if they cannot solve the questions.

2. How can the Important Questions Class 7 Mathematics Chapter 2 help students?

The experts of Extramarks have made this question series to help students. They have collected important questions from different sources such as the textbook exercises, CBSE sample papers, CBSE past years’ question papers, NCERT exemplar and important reference books. They have solved the questions, and experienced professionals have further checked the answers to ensure the best quality of the content. The students can follow the answers if they need help solving the questions. Thus, the Important Questions Class 7 Mathematics Chapter 2 can help students to score better in exams.

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CBSE Notes For Class 7
CBSE Notes Class 7 Maths
Chapter 2: Fractions And Decimals

Fractions and Decimals Class 7 Notes: Chapter 2

Introduction: fractions.

The word fraction derives from the Latin word “Fractus” meaning broken . It represents a part of a whole , consisting of a number of equal parts out of a whole. E.g : slices of a pizza.

For more information on Introduction to Fractions, watch the below video.

To know more about Fractions, visit here .

Representation of Fractions

A fraction is represented by 2 numbers on top of each other, separated by a line. The number on top is the numerator and the number below is the denominator . Example : 3 4 which basically means 3 parts out of 4 equal divisions.

For more information on Representation of Fractions, watch the below video.

Fractions on the Number Line

In order to represent a fraction on a number line, we divide the line segment between two whole numbers into n equal parts , where n is the denominator. Example : To represent 1/5 or 3/5 , we divide the line between 0 and 1 in 5 equal parts. Then the numerator gives the number of divisions to mark.

Multiplication of Fractions

Multiplication of a fraction by a whole number : Example 1: 7 ×(1/3) = 7/3 Example 2 : 5 ×(7/45) = 35/45 , Dividing numerator and denominator by 5, we get 7/9

Multiplication of a fraction by a fraction is basically product of numerators/product of denominators

Fraction as an Operator ‘Of’

The ‘of’ operator basically implies multiplication .

Example: 1/6 o f 18 = (1/6) × 18 = 18/6 = 3 or, 1/2 o f 11 = (1/2) × 11 = 11/2 To know more about Multiplication of Fractions, visit here .

Division of Fractions

Reciprocal of a fraction.

Reciprocal of any number n is written as 1 n Reciprocal of a fraction is obtained by interchanging the numerator and denominator. Example: Reciprocal of 2/5 is 5/2 Although zero divided by any number means zero itself, we cannot find reciprocals for them, as a number divided by 0 is undefined . Example : Reciprocal of 0/7 ≠ 7/0

Division of a whole number by a fraction : we multiply the whole number with the reciprocal of the fraction. Example : 63 ÷( 7/5) = 63 × (5/7) = 9 × 5 = 45

Division of a fraction by a whole number : we multiply the fraction with the reciprocal of the whole number. Example : (8/11) ÷ 4 = (8/11) ×( 1/4) = 2/11

Division of a fraction by another fraction : We multiply the dividend with the reciprocal of the divisor. Example : (2/7) ÷ (5/21) = (2/7) × (21/5) = 6/5 To know more about Reciprocal and Division of Fractions, visit here .

Types of Fractions

Proper fractions represent a part of a whole. The numerator is smaller than the denominator. Example: 1/4, 7/9, 50/51. Proper fractions are greater than 0 and less than 1

Improper fractions have a numerator that is greater than or equal to the denominator. Example: 45/6, 6/5. Improper fractions are greater than 1 or equal to 1.

Conversion of fractions : An improper fraction can be represented as mixed fraction and a mixed fraction can represented as improper. In the above case, if you multiply the denominator 5 with the whole number 8 add the numerator 3 to it, you get back 43 5

Like fractions : Fractions with the same denominator are called like fractions. Example: 5/7 , 3/7. Here we can compare them as (5/7) > ( 3/7)

Unlike fractions : Fractions with different denominators are called unlike fractions. Example: 5/3, 9/2. To compare them, we find the L.C.M of the denominator. Here the L.C.M is 6 So, (5/3)×(2/2) , (9/2)×(3/3) ⇒ 10/6, 27/6 ⇒ 27/6 > 10/7

For more information on Types of Fractions, watch the below videos.

To know more about “Types of Fractions”, visit here .

Introduction: Decimal

Decimal numbers are used to represent numbers that are smaller than the unit 1 . Decimal number system is also known as base 10 system since each place value is denoted by a power of 10.

A decimal number refers to a number consisting of the following two parts: (i) Integral part (before the decimal point) (ii) Fractional Part (after the decimal point). These both are separated by a decimal separator(.) called the decimal point .

A decimal number is written as follows: Example 564.8 or 23.97. The numbers to the left of the decimal point increase with the order of 10, while the numbers to the right of the point increase with the decrease order of 10. The above example 564.8 can be read as ‘five hundred and sixty four and eight tenths’ ⇒ 5 × 100 + 6 × 10 + 4 × 1 + 8 ×(1/10)

A fraction can be written as a decimal and vice-versa. Example 3/2 = 1.5 or 1.5 = 15/10 = 3/2

For more information on Fractions and Decimals, watch the below video.

To know more about Decimals, visit here .

Multiplication of Decimals

Multiplication of decimal numbers with whole numbers : Multiply them as whole numbers. The product will contain the same number of digits after the decimal point as that of the decimal number. E.g : 11.3 × 4 = 45.2

Multiplication of decimals with powers of 10 : If a decimal is multiplied by a power of 10, then the decimal point shifts to the right by the number of zeros in its power. E.g : 45.678 × 10 = 456.78 (decimal point shifts by 1 place to the right) or, 45.678 × 1000 = 45678 (decimal point shifts by 3 places to the right)

Multiplication of decimals with decimals :

Multiply the decimal numbers without decimal points and then give decimal point in the answer as many places same as the total number of places right to the decimal points in both numbers.

Division of Decimals

Dividing a decimal number by a whole number : Example: 45.2/55 Step 1 . Convert the Decimal number into Fraction: 45.25 = 4525/100 Step 2 . Divide the fraction by the whole number: ( 4525/100) ÷ 5 = ( 4525/100) × (1/5) = 9.05

Dividing a decimal number by a decimal number : Example 1: 45.25/0.5 Step 1. Convert both the decimal numbers into fractions: 45.25 = 4525/100 and 0.5 = 5/10 Step 2. Divide the fractions: (4525/100) ÷ (5/10) = (4525/100) × (10/5) = 90.5 Example 2:

Dividing a decimal number by powers of 10 : If a decimal is divided by a power of 10, then the decimal point shifts to the left by the number of zeros present in the power of 10. Example: 98.765 ÷ 100 = 0.98765 Infinity

When the denominator in a fraction is very very small (almost tending to 0), then the value of the fraction tends towards infinity . E.g: 999999/0.000001 = 999999000001 ≈ a very large number, which is considered to be ∞

To know more about Multiplication and Division of Decimals, visit here .

Frequently Asked Questions on CBSE Class 7 Maths Notes Chapter 2 Fractions and Decimals

What is a decimal.

A decimal is a fraction written in a special form.

What is a decimal fraction?

In algebra, a decimal fraction is a fraction whose denominator is 10 or a multiple of 10 like 100, 1,000, 10,000, etc.

What does reciprocal mean?

In Mathematics, reciprocal means an expression which when multiplied by another expression, gives one (1) as the result.

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Class 7 (Old)

Course: class 7 (old) > unit 2.

Unit test Fractions and decimals

Arinjay Academy » Maths Class 7 » Fractions and Decimals Class 7 MCQ Questions

Fractions and Decimals Class 7 MCQ Questions

Fractions and Decimals Class 7 MCQ Questions Maths are covered in this Article. Fractions and Decimals Class 7 MCQ Test contains 46 questions. Answers to MCQs on Fractions and Decimals Class 7 are available at the end of the last question. These MCQ have been made for Class 7 students to help check the concept you have learnt from detailed classroom sessions and application of your knowledge.

1.Is (3/4)is a proper fraction

Answer: (a) Yes

Explanation: Proper fraction is a fraction which represents the part of whole number. In proper fraction numerator is always less than its denominator.

In generalize form for any two integer ‘a’ and ‘b’

a/b where (a < b)

i.e., Numerator < Denominator

Numerator = 3

Denominator = 4

Here 3 < 4

Hence, 3/4 is a proper fraction.

2.Is (1/2) is a improper fraction

Answer: (b) No

Explanation: Improper fractions are the combination of whole number and a proper fraction. Improper fraction is opposite of proper fraction, since in improper fraction numerator is greater than its denominator

a/b where (a > b)

i.e., Numerator > Denominator

Numerator = 1

Denominator = 2

Here, 1 < 2

Hence, 1/2 is not an improper fraction.

3. Are the following fractions are Like Fractions or Unlike Fractions?

5,7 , 7/8 and 6/9

(a) Like fractions

(b) Unlike fractions

Answer: (b) Unlike fractions

Explanation: In case of Like Fraction, the denominator of the fractions are the same.

While, In case of Unlike Fraction denominator of the fractions are not same.

In the present case, the given fractions are

5/7,7/8 and 6/9

Since the Denominator in the present cases are 7 , 8 , 9 which are not same. So, the given fractions are Unlike Fractions

4. Convert (36/48) into its simplest form.

Answer: (d) 3/4

Explanation: 36/48

Taking HCF of 36 and 48 is 12

Divide numerator and denominator by their HCF i.e., 12

(36 ÷ 12)/(48 ÷ 12) = 3/4

5.Are (3/4) and (15/20) equivalent fraction ?

Explanation: Cross Multiplying (3/4) and (15/20)

3 x 20 = 60

15 x 4 = 60

3 x 20 = 15 x 4

Hence, Value of (3/4) = (15/20) on cross multiplication, they are equivalent fraction.

6.Compare the fractions:

(7/12) and (7/6)

(a) (7/12) > (7/6)

(b) (7/12) < (7/6)

Answer: (b) (7/12) < (7/6)

Explanation: On Cross multiplying 7/12 and 7/6

We multiply 7 x 6 = 42

Similarly, we multiply 12 x 7 = 84

Since, 42 < 84

(7/12) < (7/6)

7. Convert the fraction as like fraction (7/20) and (17/8)

(a) 7/20 and 17/20

(b) 15/40 and 87/40

(d) 7/40 and 17/40

Answer: (c) 14/40 and 85/40

Explanation: Step1: Find LCM of given Fractions

LCM of 20 and 8 is 40

Step 2: Divide LCM by the denominators of the given fractions

(40÷20)/(40÷8) = 2/5

Step 3: Multiply the quotient by the numerator and keep denominator equal to LCM. i.e.,

(2×7)/40 = 14/40

(5×17)/40 = 85/40

So, 14/40 and 85/40 are like fractions.

8.Convert (12/5) into Mixed Fraction.

Answer: (a) 2(2/5)

Explanation: Given Fraction:

Divide the Numerator by the Denominator

On dividing 12 by 5

We get Quotient = 2

Remainder = 2

For a Mixed Fraction we have to write

Quotient + (Remainder/Divisor)

So, the Mixed Fraction is 2 + (2/5) = 2(2/5).

9. Convert the Fraction 4(3/4) into an Improper Fraction.

Answer: (a) 19/4

Explanation: A combination of Whole Number and a Proper Fraction is called a Mixed Fraction.

Mixed Fraction = 4(3/4)

Whole Number Part = 4

Step 1 : Multiply the Whole Number Part and Denominator of the Mixed Fraction

Step 2 : Add the Numerator to the product obtained in Step 1

3 + 16 = 19

Write the sum as the numerator and denominator would remain the same , as in the Mixed Fraction.

Hence, 4(3/4) = 19/4.

10.Find the sum of (14/15) and (7/15) and reduce to its lowest term.

Answer: (b) 7/5

Explanation: Sum of Like Fraction = Sum of their Numerators / Common Denominator

= (14+7)/15

Hence, the sum of 14/15 and 7/15 is 21/15

Simplifying further,

HCF of 21 and 15 is 3

Dividing both Numerator and Denominator by their HCF i.e.,

(21÷3)/(15÷3) = 7/5

Hence, the sum of (14/15) and (7/15) = 7/5.

11.Find the sum of (8/24) and (5/60) and reduce to its lowest term.

Answer: (c) 5/12

Explanation: In order to add Unlike Fraction

Firstly, we have to change the Unlike Fraction, into equivalent Like Fractions, and then add the two equivalent Like Fractions

Take LCM of 24 and 60 is 120

Converting the Unlike Fraction into Equivalent Like Fraction

We have to multiply , both the numerator and denominator of (8/24) by 5

(8×5)/(24×5) = 40/120

We have to multiply , both the numerator and denominator of 560by 2

(5×2)/(60×2) = 10/120

Now (40/120) + (10/120) = 50/120

HCF of 50 and 120 is 10

(50÷10)/(120÷10) = 5/12

Hence, the sum of 8/24 and 5/60 = 5/12.

12. Find the difference of (45/18) and (25/18) and reduce to its lowest term.

Answer: (b) 10/9

Explanation: Difference of Like Fraction = Difference of their Numerators/Common Denominator

= (45−25)/18

HCF of 20 and 18 is 2

(20÷2)/(18÷2) = 10/9

Hence, the difference of 45/18 and 25/18 = 10/9.

13. Find the difference of (11/24) and (2/16) and reduce to its lowest term.

Answer: (c) 1/3

Explanation: To find the difference of Unlike Fraction

Firstly, we have to change the Unlike Fraction into equivalent Like Fraction, and then subtract the two equivalent Like Fraction

Take LCM of 24 and 16 is 48

We have to multiply Numerator and Denominator of 11/24 by 2

(11×2)/(24×2) = 22/48

We have to multiply Numerator and Denominator of 2/16 by 3

(2×3)/(16×3) = 6/48

Now (22/48) – (6/48) = 16/48

HCF of 16 and 48 is 16

(16÷16)/(48÷16) = 1/3

Hence, the difference of 11/24 and 2/16= 1/3.

14.Find the sum of (10/5)+ (13/5)+ (24/5)

Answer: (c) 47/5

Explanation: Sum of Like Fraction = Sum of their Numerators/Common Denominator

= (10+13+24)/5

Hence, the sum of 10/5, 13/5 and 24/5 is 47/5.

15.Find the sum of 7(1/3)+ 2(1/3)

(b) 11(3/5)

Answer: (a) 9(2/3)

Explanation: 7(1/3)+ 2(1/3)

Converting the Mixed Fractions into Improper Fractions

= (22/3) + (7/3)

Sum of Like Fraction = Sum of their Numerators / Common Denominator

Hence, the sum is 9(2/3).

16. Find: (42/56) of 7

Answer: (a) 21/4

Explanation: In this question ‘of’ means to multiply

When any fractions either proper or improper are multiplied with a whole number, the numerators are multiplied with whole number and the denominator will remains the same.

So, 42/56 of 7

= (7/1) x (42/56)

HCF of 294 and 56 is 14

Since, both numerator and denominator are divide by their HCF i.e.,

(294÷14)/(56÷14) = 21/4

So, the answer is 21/4.

17.Find the sum of 4(3/12)+ (3(1/6)

(a) 9(3/12)

(b) 7(5/12)

Answer: (b) 7(5/12)

Explanation: 4(3/12) + 3(1/6)

(51/12) + (19/6)

Take the LCM of the two denominators 12 and 6 which is 12

= (51×1+19×2)/12

= (51+38)/12

Converting the result into Mixed Fraction

= 7(5/12) ( Quotient (Remainder/Divisor))

18. Find the product of (4/5) x (3/7)

Answer: (a) 12/35

Explanation: Product of Fraction = Product of their Numerators /Product of their Denominators

(4/5) x (3/7) = (4×3)/(5×7) = 12/35

Hence, product of (4/5) x (3/7) = 12/35.

19. (3/10) x (12/5) x (10/8)

Answer: (a) 9/10

Explanation: When any two or More Fractions (Whether Proper or Improper) are to be multiplied, the Numerators are multiplied with Numerator , and Denominators are multiplied with denominator.

Product of Fractions = Product of their Numerators /Product of their Denominators

Here, Numerators are 3 , 12 , 10

Denominators are 10 , 5 , 8

Hence, Product of Fractions would be

(3/10) x (12/5) x (10/8) = (3×12×10)/(10×5×8) = 360/400 = 9/10.

20. Find 7(4/6)x (1/3)

Answer: (b) 23/9

Explanation: In order to multiply a Mixed Fraction with a Improper/ Proper Fraction, we first convert mixed Fraction into improper Fraction , and then multiply it with the Improper/Proper Fraction

7(4/6) means Quotient(Remainder/Divisor)

Converting Mixed Fraction into an Improper Fraction = ((Quotient× Divisor)+Remainder)/Divisor

= ((7×6)+4)/6

Multiplying the Improper Fraction obtained by conversion of Mixed Fraction, with given Fraction

46/6 x (1/3) = (46×1)/(6×3) = 46/18

Converting the result into Simplest form

HCF of 46 and 18 is 2

(46÷2)/(18÷2) = 23/9

21.Find (7/12) of a Year ?

(a) 12 months

(b) 7 months

Answer: (b) 7 months

Explanation: We know that, 1 Year = 12 months

7/12 of a Year

= (7/12) of 12 months

((7/12) x 12) months ( here ” of ” means to multiply ” x ” )

= (84/12) months = 7 months

22.Find (12/25) of a km ?

Answer: (a) 480 m

Explanation: We know that, 1 km = 1000 m

(12/25) of a km

= (12/25) of 1000 m

= ( 12/25 x 1000 ) m ( here ” of ” means to multiply ” x ” )

= ( 12000/25 ) m = 480 m

23.Find (4/5) of a metre (m) ?

Answer: (c) 80 cm

Explanation: We know that, 1 m = 100 cm

4/5 of a metre (m)

= (4/5) of 100 cm

((4/5) x 100 ) cm ( here ” of ” means to multiply ” x ” )

= ( 400/5 ) cm = 80 cm

24. Find (4/25) of a Rupee ?

(a) 23 paise

(b) 14 paise

Answer: (c) 16 paise

Explanation: We know that, 1 Rupee = 100 paise

(4/25) of a Rupee

= (4/25) of 100 paise

((4/25) x 100 ) paise ( here ” of ” means to multiply ” x ” )

= ( 400/25 ) paise = 16 paise

25. Find (8/5) of an Hour ?

(a) 103 min

Answer: (c) 96 min

Explanation: We know that, (1 Hour = 60 min )

(8/5) of an Hour

= (8/5) of 60 min

= ((8/5)x 60 ) min ( here ” of ” means to multiply ” x ” )

= ( 480/5 ) min = 96 min

26. Divide (5/16) ÷ (15/32)

Answer: (a) 2/3

Explanation: We have, (5/16) ÷ (15/32)

In order to divide a Fraction by another Fraction

We have to multiply First Fraction with Reciprocal of the second Fraction

We have (5/16) ÷ (15/32)

= (5/16) x (32/15) (Since, Reciprocal of 1532is 3215)

(5×32)/(16×15) = 160/240

Simplifying the given Fraction,

HCF of 160 and 240 is 80

= (160÷80)/(240÷80) = 2/3

27. Divide (3(1/3)) ÷ (6/7)

Answer: (c) 35/9

Explanation: We have, (3(1/3)) ÷ (6/7)

Simplifying, the above equation, we get (10/3) ÷ (6/7)

(10/3) x (6/7) (Since, Reciprocal of 6/7 is 7/6 )

(10×7)/(3×6) = 70/18

HCF of 70 and 18 is 2

= (70÷2)/(18÷2) = 35/9

28. A town has a population of 10000 people. Two – fifths of the people own flat ,the rest do not. How many people in the town do not own flat ?

Answer: (b) 6000

Explanation: Total population of town = 10000

It is given that,

Two fifths of the people own flat

Therefore, Number of people who have their own flat = 25 of Total population of town

= (2/5) x 10000

On simplifying it

= (2/1) x 2000

So, Number of people who have their own flat = 4000

Now, the number of people do not have own flat = Total population of town – Number of people who have their own flat

= 10000 – 4000

Therefore, the number of people do not have own flat = 6000

29. Divide (4/7) by 12

Answer: (b) 1/21

Explanation: We have, (4/7) ÷ 12

(4/7) x (1/12) (Since, Reciprocal of 12/1 is 1/12 )

(4×1)/(7×12) = 4/84

HCF of 4 and 84 is 4

= (4÷4)/(84÷4) = 1/21

30.Divide 5 by (15/2)

Answer: (d) 2/3

Explanation: We have, 5 ÷ (15/2)

In order to divide a whole number by a Fraction, we need to multiply the whole number with the reciprocal of that Fraction.

We have to multiply Whole number by Reciprocal of that Fraction

5 x (2/15) (Since, Reciprocal of 15/2 is 2/15 )

5×(2/15) = 10/15

HCF of 10 and 15 is 5

= (10÷5)/(15÷5) = 2/3

31. Find the Like Decimals in the given sets of Decimals ?

(d) (a) and (c)

(e) (a) and (b)

Answer: (d) (a) and (c)

Explanation: Decimal Numbers, having the same number of Decimal places are called Like Decimals.

The number of Decimal places in 14.08 is 2

The number of Decimal places in 14.2 is 1

The number of Decimal places in 26.71 is 2

Hence, 14.08 and 26.71 are Like Decimals since these two numbers have 2 Decimal places, while 14.2 has only 1 Decimal place.

32. Find the unlike Decimal in the given sets of Decimals?

Answer: (b) 32.7

Explanation: Where the number of Decimal places in two Decimals are different, they are called Unlike Decimals.

The number of Decimal places in 14.59 is 2

The number of Decimal places in 32.7 is 1

The number of Decimal places in 17.34 is 2

The number of Decimal places in 23.48 is 2

Hence, 32.7 is the unlike Decimal amongst the given Decimals since it has only 1 Decimal place while all other numbers have 2 Decimal places.

33. Find the place value of 9 in 4926.371

Answer: (c) 900

Explanation: If we plot the given number on the place value Table, we would get:

In the given Table, place value of 9 = 9 Hundreds = 900

So, the place value of 9 in 4926.371 is 900

34. Express 22(1/5) into Decimal.

Answer: (c) 22.2

Explanation: Whenever, we have a mixed fraction, it would consist of two parts.

Whole Number Part = 22

Fraction Part = 1/5

The Whole Number Part would remain the same.

The Fraction Part should be converted into decimal.

When we convert 1/5 into decimal we would get 0.2

The Decimal value of the given fraction = Whole Number Part . Decimal value of Fraction Part

The Decimal value of the given fraction = 22.2

35. Convert 0.26 into a fractions in its Simplest form ?

Answer: (a) 13/50

Explanation: Step 1: Write the given Decimal without the Decimal point as the numerator of the fraction 26

Step 2: Write 1 followed by as many zeroes, as there are Decimal places in the given Decimal 100 (Since there was 2 decimal place in the given number, we have added 2 zero at the end of 1 )

Step 3: Convert the fraction 26/100 into simplest form

HCF of 26 and 100 is 2.

To simplify this we have to divide both the numerator and denominator of the fraction by their HCF i.e.,

26 and 100 by 2

In other words (26/100) = (26÷2)/(100÷2) = 13/50

Hence, 0.26 = 13/50

36.Express 24 km 347 m in km?

(a) 27.47 km

(b) 24.0347 km

(d) 58.7 km

Answer: (c) 24.347 km

Explanation: First, we have to convert 347 m into km

As we know that, 1000 m = 1 km

1 m = 1/1000 km

347 m = (1/1000)x 347 km

347 m = (347/1000) km

347 m = 0.347 km

Now we have to convert, 24 km 347 m into km

24 km + 347 m

= 24 km + 0.347 km (From above 347 m = 0.347 km )

= 24.347 km

37. Express 16 kg 178 g in kg?

(a) 1617.8 kg

(b) 16.178 kg

(d) 16.0178 kg

Answer:(b) 16.178 kg

Explanation: First, we have to convert 178 g into kg

As we know that, 1000 g = 1 kg

1 g = (1/1000) kg

178 g = (1/1000) x 178 kg

178 g = (178/1000) kg

178 g = 0.178 kg

Now we have to convert, 16 kg 178 g into kg

16 kg + 178 g

= 16 kg + 0.178 kg (From above 178 g = 0.178 kg )

= 16.178 kg

38. Express ₹ 51 and 45 paise into rupees?

(a) ₹ 51.045

(b) ₹ 51.0045

(d) ₹ 51.45

Answer: (d) ₹ 51.45

Explanation: First, we have to convert 45 paise into rupees

As we know that, 100 paise = 1 rupees

1 paise = (1/100) rupees

45 paise = (1/100) x 45 rupees

45 paise = ₹ (45/100)

45 paise = ₹ 0.45

Now we have to convert, ₹ 51 and 45 paise into rupees

₹ 51 + 45 paise

= ₹ 51 + ₹ 0.45 (From above 45 paise = ₹ 0.45 )

39. What should be added to 49.76 to get 79.48 ?

Answer:(c) 29.72

Explanation: Let us say the number to be added to 49.76 to get 79.48 is x

This implies that 49.76 + x = 79.48

or x = 79.48 -49.76

– 49.76

Hence, if we add 29.72 to 49.76 we would get 79.48.

40. What should be subtracted from 69.13 to get 52.43?

Answer: (c) 16.70

Explanation: Lets us say that the number to be subtracted from 69.13 to get 52.43 is x

This implies that 69.13 – x = 52.43

or x = 69.13 – 52.43

– 52.43

Hence, if we subtract 16.70 from 69.13 we would get 52.43.

41. Find 62.3837 x 1000

(a) 62383.7

(b) 6238.37

Answer: (a) 62383.7

Explanation: When a Decimal is multiplied by 1000, the Decimal point is shifted to the right by three places.

When we need to multiply 62.3837 x 1000

We would need to move the Decimal of 62.3837 by 3 digit to the right side

we would get, 62383.7

Hence, 62.3837 x 1000 = 62383.7

42. Find 1.866 x 15?

Answer: (c) 27.99

Explanation: Step I : Remove the Decimal Point from the Decimal number, and multiply it with the whole number.

i.e., 1866 x 15 = 27990

Step II : Count the Decimal Places in the given numbers, and add the same number of decimal places in the answer.

Number of Decimal places in the given Decimal is 3

If we add 3 decimal places to 27990 it would become 27.99

Hence, 1.866 x 15 = 27.99

43. Find 0.105 x 0.21 ?

(a) 0.02205

(b) 0.002205

Answer:(a) 0.02205

Explanation: Step I : Remove the Decimal Point from both the Decimal numbers, and multiply them

105 x 21 = 2205

Step II : Count the Decimal Places in both the decimal numbers, and add the same number of decimal places in the answer.

Number of Decimal place in the given Decimals = 3 + 2 = 5

So, the product will contain 5 Decimal point

If we add 5 decimal places to 2205 it would become 0.02205

Hence, 0.105 x 0.21 = 0.02205

44. Find 2.9 x 1.3 x 4.9 ?

Answer: (c) 18.473

Explanation: Step I : Remove the Decimal Point from all the Decimal number, and multiply them.

29 x 13 x 49 = 18473

Step II : Count the Decimal Places in all the decimal numbers, and add the same number of decimal places in the answer.

Number of Decimal place in the given Decimals = 1 + 1 + 1 = 3

So, the product will contain 3 Decimal point

If we add 3 decimal places to 18473 it would become 18.473

Hence, 2.9 x 1.3 x 4.9 = 18.473

45. If the cost of a pen is ₹ 24.25, find the cost of 16 such pens ?

(a) ₹ 436.5

Answer: (c) ₹ 388

Explanation: Cost of 1 pen = ₹ 24.25

Cost of 16 pens = ₹ ( 24.25 x 16 )

Hence, the cost of 16 such pens = ₹ 388

46. Divide 765.26 by 1000?

(a) 0.76526

Answer: (a) 0.76526

Explanation: When a Decimal is divided by 1000, the Decimal point is shifted to the left by three places.

When we need to divide 765.26 by 1000

We would need to move the Decimal of 765.26 by three digit to the left side.

we would get, 0.76526

Hence, 765.26 ÷ 1000 = 0.76526

MCQ Questions for Class 7 Maths with Answers

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Comparing Quantities Class 7 MCQ with Answers
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Frequently Asked Questions on Fractions and Decimals Class 7 MCQ Questions

1. Are these MCQ on Fractions and Decimals Class 7 are based on 2021-22 CBSE Syllabus?

Yes. There are 46 MCQ’s on this Chapter in this blog.

2. Are you giving all the chapters of Maths Class 7 MCQs with Answers which are given in CBSE syllabus for 2021-22 ?

Yes, we are providing all the chapters of Maths Class 7 MCQs with Answers.

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CBSE Class 7 Fractions to Decimal Worksheet

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Fractions to decimal worksheets are great for practicing turning fractions into decimals and vice versa. You’ll learn how to change fractions into decimals using long division.

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Target Exam ---

In a fraction, there are two parts: the top number (numerator) and the bottom number (denominator). They show how many parts we have out of the whole. You can think of the line between them as a division sign.

Worksheet for Class 7 Maths

CBSE Class 7 Fractions to Decimal Worksheet – Download PDF

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Class 7 Mathematics Worksheet 1 : Chapter 1 – Fractions to Decimal

Question 1: Convert the following fractions into decimals:

a) $ \frac{3}{4} $
b) $ \frac{5}{8} $
c) $ \frac{2}{5} $
a) $ \frac{3}{4} = 0.75 $
b) $ \frac{5}{8} = 0.625 $
c) $ \frac{2}{5} = 0.4 $

Question 2: Convert the following fractions into decimals:

a) $ \frac{7}{10} $
b) $ \frac{1}{2} $
c) $ \frac{4}{25} $
a) $ \frac{7}{10} = 0.7 $
b) $ \frac{1}{2} = 0.5 $
c) $ \frac{4}{25} = 0.16 $ (rounded to two decimal places)

Question 3: Convert the following fractions into decimals:

a) $ \frac{9}{20} $
b) $ \frac{3}{7} $
c) $ \frac{6}{15} $
a) $ \frac{9}{20} = 0.45 $
b) $ \frac{3}{7} $ is approximately $ 0.4286 $ (rounded to four decimal places)
c) $ \frac{6}{15} = 0.4 $

Question 4: Convert the following fractions into decimals:

a) $ \frac{2}{9} $
b) $ \frac{5}{6} $
c) $ \frac{7}{12} $
a) $ \frac{2}{9} $ is approximately $ 0.2222 $ (rounded to four decimal places)
b) $ \frac{5}{6} = 0.8333 $ (rounded to four decimal places)
c) $ \frac{7}{12} $ is approximately $ 0.5833 $ (rounded to four decimal places)\

Algebraic Expressions

Benefits of Fractions to Decimal Worksheets

To change a fraction into a decimal, you divide the top number (numerator) by the bottom number (denominator). Decimals are really useful for everyday tasks. Think about things like measuring how tall someone is or figuring out how much to pay for something. If you don’t do the conversion correctly, you might lose accuracy. That’s why knowing how to switch between fractions and decimals is super handy in daily life.

Class 7 Fractions to Decimal Worksheet FAQ’s

What i learnt in fractions and decimals.

I learned about parts of a whole and how to express them as fractions or decimals.

Why do we use decimals instead of fractions?

Decimals are easier to work with for precise measurements, like money or scientific data.

What I found challenging in fraction and decimal Class 7?

Understanding how to convert between fractions and decimals was tricky for me.

Why do we use fractions over decimals?

Fractions are useful for representing parts of a whole, like slices of pizza or portions of a cake.

What is the relationship between fraction and decimal?

Fractions and decimals both represent parts of a whole; they are different ways of expressing the same thing.

case study questions on decimals class 7

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Revision Notes on Fractions and Decimals

The General form of a Fraction

Types of Fraction

Converting an Improper Fraction into a Mixed Fraction

Reciprocal of a Fraction

Multiplication of Fractions

Division of Fractions

Decimal Numbers

Multiplication of Decimal Numbers

Division of Decimal Numbers

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