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Dilating Lines and Angles
Angle \(ABC\) is taken by a dilation with center \(P\) and scale factor 3 to angle \(A’B’C’\) . The measure of angle \(ABC\) is \(21^\circ\) . What is the measure of angle \(A’B’C’\) ?
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Select all lines that could be the image of line \(m\) by a dilation.
Dilate line \(f\) with a scale factor of 2. The image is line \(g\) . Which labeled point could be the center of this dilation?
Description: <p>Line f with point C to the right of the center. Line g above line f with point B to the right of the center. Point A is above line g and to the left of point B. Point D is below line f and to the left of point C.</p>
Quadrilateral \(A’B’C’E’\) is the image of quadrilateral \(ABCE\) after a dilation centered at \(F\) . What is the scale factor of this dilation?
Description: <p>Quadrilaterals A B C E and A prime B prime C prime E prime. Side lengths as follows: A B, 3. B C 6, C E, 5. E A, unlabeled. A prime B prime, 1 point 5. B prime C prime, 3. C prime E prime, 2 point 5. E prime A prime, unlabeled.<br> </p>
A polygon has a perimeter of 18 units. It is dilated with a scale factor of \(\frac32\) . What is the perimeter of its image?
Solve the equation.
\(\frac{4}{7}=\frac{10}{x}\)
Here are some measurements for triangle \(ABC \) and triangle \(XYZ\) :
- Angle \(CAB\) and angle \(ZXY\) are both 30 degrees
- \(AC\) and \(XZ\) both measure 3 units
- \(CB\) and \(ZY\) both measure 2 units
Andre thinks thinks these triangles must be congruent. Clare says she knows they might not be congruent. Construct 2 triangles with the given measurements that aren't congruent. Explain why triangles with 3 congruent parts aren't necessarily congruent.
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Answer Key 3.4
For questions 1 to 10, sketch the linear equation using the slope intercept method.
For questions 11 to 20, sketch the linear equation using the [latex]x[/latex] and [latex]y[/latex] intercepts.
For questions 21 to 28, sketch the linear equation using any method.
Intermediate Algebra Copyright © 2020 by Terrance Berg is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License , except where otherwise noted.
Share This Book
( 3 , 2 ) ( 3 , 2 )
( 2 , 3 ) ( 2 , 3 )
( 3 , 4 ) ( 3 , 4 )
( 5 , −4 ) ( 5 , −4 )
no solution
infinitely many solutions
ⓐ no solution, inconsistent, independent ⓑ one solution, consistent, independent
( 6 , 1 ) ( 6 , 1 )
( −3 , 5 ) ( −3 , 5 )
( 2 , 3 2 ) ( 2 , 3 2 )
( − 1 2 , −2 ) ( − 1 2 , −2 )
( 2 , −1 ) ( 2 , −1 )
( −2 , 3 ) ( −2 , 3 )
( 1 , 3 ) ( 1 , 3 )
( 4 , −3 ) ( 4 , −3 )
( 6 , 2 ) ( 6 , 2 )
( 1 , −2 ) ( 1 , −2 )
ⓐ Since both equations are in standard form, using elimination will be most convenient. ⓑ Since one equation is already solved for x , using substitution will be most convenient.
ⓐ Since one equation is already solved for y , using substitution will be most convenient. ⓑ Since both equations are in standard form, using elimination will be most convenient.
160 policies
Mark burned 11 calories for each minute of yoga and 7 calories for each minute of jumping jacks.
Erin burned 11 calories for each minute on the rowing machine and 5 calories for each minute of weight lifting.
The angle measures are 55 and 35.
The angle measures are 5 and 85.
The angle measures are 42 and 138.
The angle measures are 66 and 114.
The length is 60 feet and the width is 35 feet.
The length is 60 feet and the width is 38 feet.
It will take Clark 4 hours to catch Mitchell.
It will take Sally 1 1 2 1 1 2 hours to catch up to Charlie.
The rate of the boat is 11 mph and the rate of the current is 1 mph.
The speed of the canoe is 7 mph and the speed of the current is 1 mph.
The speed of the jet is 235 mph and the speed of the wind is 30 mph.
The speed of the jet is 408 mph and the speed of the wind is 24 mph.
206 adults, 347 children
42 adults, 105 children
13 dimes and 29 quarters
19 quarters and 51 nickels
3 pounds peanuts and 2 pounds cashews
10 pounds of beans, 10 pounds of ground beef
120 ml of 25% solution and 30 ml of 50% solution
125 ml of 10% solution and 125 ml of 40% solution
$42,000 in the stock fund and $8000 in the savings account
$1750 at 11% and $5250 at 13%
Bank $4,000; Federal $14,000
$41,200 at 4.5%, $24,000 at 7.2%
ⓐ C ( x ) = 15 x + 25 , 500 C ( x ) = 15 x + 25 , 500
ⓑ R ( x ) = 32 x R ( x ) = 32 x
ⓓ 1,500 1,500 ; when 1,500 benches are sold, the cost and revenue will be both 48,000
ⓐ C ( x ) = 120 x + 150,000 C ( x ) = 120 x + 150,000
ⓑ R ( x ) = 170 x R ( x ) = 170 x
ⓓ 3,000 3,000 ; when 3,000 benches are sold, the revenue and costs are both $510,000
( 2 , −1 , 3 ) ( 2 , −1 , 3 )
( −2 , 3 , 4 ) ( −2 , 3 , 4 )
( −3 , 4 , −2 ) ( −3 , 4 , −2 )
( −2 , 3 , −1 ) ( −2 , 3 , −1 )
infinitely many solutions ( x , 3 , z ) ( x , 3 , z ) where x = z − 3 ; y = 3 ; z x = z − 3 ; y = 3 ; z is any real number
infinitely many solutions ( x , y , z ) ( x , y , z ) where x = 5 z − 2 ; y = 4 z − 3 ; z x = 5 z − 2 ; y = 4 z − 3 ; z is any real number
The fine arts department sold 75 adult tickets, 200 student tickets, and 75 child tickets.
The soccer team sold 200 adult tickets, 300 student tickets, and 100 child tickets.
ⓐ [ 3 8 −3 2 5 −3 ] [ 3 8 −3 2 5 −3 ] ⓑ [ 2 −5 3 8 3 −1 4 7 1 3 2 −3 ] [ 2 −5 3 8 3 −1 4 7 1 3 2 −3 ]
ⓐ [ 11 9 −5 7 5 −1 ] [ 11 9 −5 7 5 −1 ] ⓑ [ 5 −3 2 −5 2 −1 −1 4 3 −2 2 −7 ] [ 5 −3 2 −5 2 −1 −1 4 3 −2 2 −7 ]
{ x − y + 2 z = 3 2 x + y − 2 z = 1 4 x − y + 2 z = 0 { x − y + 2 z = 3 2 x + y − 2 z = 1 4 x − y + 2 z = 0
{ x + y + z = 4 2 x + 3 y − z = 8 x + y − z = 3 { x + y + z = 4 2 x + 3 y − z = 8 x + y − z = 3
ⓐ [ −2 3 0 −2 4 −1 −4 4 5 −2 −2 −2 ] [ −2 3 0 −2 4 −1 −4 4 5 −2 −2 −2 ] ⓑ [ −2 3 0 −2 4 −1 −4 4 15 −6 −6 −6 ] [ −2 3 0 −2 4 −1 −4 4 15 −6 −6 −6 ] ⓒ [ −2 3 0 −2 3 4 −13 −16 −8 15 −6 −6 −6 ] [ −2 3 0 −2 3 4 −13 −16 −8 15 −6 −6 −6 ]
ⓐ [ 4 1 −3 2 2 −3 −2 −4 5 0 4 −1 ] [ 4 1 −3 2 2 −3 −2 −4 5 0 4 −1 ] ⓑ [ 8 2 −6 4 2 −3 −2 −4 5 0 4 −1 ] [ 8 2 −6 4 2 −3 −2 −4 5 0 4 −1 ] ⓒ [ 14 −7 −12 −8 2 −3 −2 −4 5 0 4 −1 ] [ 14 −7 −12 −8 2 −3 −2 −4 5 0 4 −1 ]
[ 1 −1 2 0 −3 −4 ] [ 1 −1 2 0 −3 −4 ]
[ 1 −1 3 0 −5 8 ] [ 1 −1 3 0 −5 8 ]
The solution is ( 4 , −1 ) . ( 4 , −1 ) .
The solution is ( −2 , 0 ) . ( −2 , 0 ) .
( 6 , −1 , −3 ) ( 6 , −1 , −3 )
( 5 , 7 , 4 ) ( 5 , 7 , 4 )
infinitely many solutions ( x , y , z ) , ( x , y , z ) , where x = z − 3 ; y = 3 ; z x = z − 3 ; y = 3 ; z is any real number.
infinitely many solutions ( x , y , z ) , ( x , y , z ) , where x = 5 z − 2 ; y = 4 z − 3 ; z x = 5 z − 2 ; y = 4 z − 3 ; z is any real number.
ⓐ −14 ; −14 ; ⓑ −28 −28
ⓐ 2 ⓑ −15 −15
ⓐ 3 ⓑ 11 ⓒ 2
ⓐ −3 −3 ⓑ 2 ⓒ 3
( − 15 7 , 24 7 ) ( − 15 7 , 24 7 )
( −2 , 0 ) ( −2 , 0 )
( −9 , 3 , −1 ) ( −9 , 3 , −1 )
( −6 , 3 , −2 ) ( −6 , 3 , −2 )
infinite solutions
The solution is the grey region.
No solution.
ⓐ { 30 m + 20 p ≤ 160 2 m + 3 p ≤ 15 { 30 m + 20 p ≤ 160 2 m + 3 p ≤ 15 ⓑ
ⓐ { a ≥ p + 5 a + 2 p ≤ 400 { a ≥ p + 5 a + 2 p ≤ 400 ⓑ
ⓐ { 0.75 d + 2 e ≤ 25 360 d + 110 e ≥ 1000 { 0.75 d + 2 e ≤ 25 360 d + 110 e ≥ 1000 ⓑ
ⓐ { 140 p + 125 j ≥ 1000 1.80 p + 1.25 j ≤ 12 { 140 p + 125 j ≥ 1000 1.80 p + 1.25 j ≤ 12 ⓑ
Section 4.1 Exercises
( 0 , 2 ) ( 0 , 2 )
( 2 , 4 ) ( 2 , 4 )
( −2 , 2 ) ( −2 , 2 )
( 3 , 3 ) ( 3 , 3 )
( 6 , −4 ) ( 6 , −4 )
No solutions, inconsistent, independent
1 point, consistent and independent
infinite solutions, consistent, dependent
( 1 , −4 ) ( 1 , −4 )
( −3 , 2 ) ( −3 , 2 )
( −1 / 2 , 5 / 2 ) ( −1 / 2 , 5 / 2 )
( −5 , 4 ) ( −5 , 4 )
( 0 , 10 ) ( 0 , 10 )
( 4 , −2 ) ( 4 , −2 )
( 4 , 0 ) ( 4 , 0 )
( 4 , 5 ) ( 4 , 5 )
( 7 , 12 ) ( 7 , 12 )
( −3 , −5 ) ( −3 , −5 )
( 2 , −3 ) ( 2 , −3 )
( −11 , 2 ) ( −11 , 2 )
( 6 / −9 , 24 / 7 ) ( 6 / −9 , 24 / 7 )
infinitely many
ⓐ substitution ⓑ elimination
ⓐ elimination ⓑ substituion
Answers will vary.
Section 4.2 Exercises
−7 −7 and −19 −19
22 and −67 −67
Eighty cable packages would need to be sold to make the total pay the same.
Mitchell would need to sell 120 stoves for the companies to be equal.
8 and 40 gallons
1000 calories playing basketball and 400 calories canoeing
Oranges cost $2 per pound and bananas cost $1 per pound
Package of paper $4, stapler $7
Hot dog 150 calories, cup of cottage cheese 220 calories
Owen will need 80 quarts of water and 20 quarts of concentrate to make 100 quarts of lemonade.
53.5 53.5 degrees and 36.5 36.5 degrees
16 degrees and 74 degrees
134 degrees and 46 degrees
37 degrees and 143 degrees
16 ° 16 ° and 74 ° 74 °
45 ° 45 ° and 45 ° 45 °
Width is 41 feet and length is 118 feet.
Width is 10 feet and length is 40 feet.
1.5 1.5 hour
Boat rate is 16 mph and current rate is 4 mph.
Boat rate is 18 mph and current rate is 2 mph.
Jet rate is 265 mph and wind speed is 22 mph.
Jet rate is 415 mph and wind speed is 25 mph.
Section 4.3 Exercises
110 adult tickets, 190 child tickets
6 good seats, 10 cheap seats
92 adult tickets, 220 children tickets
13 nickels, 3 dimes
42 dimes, 8 quarters
17 $10 bills, 37 $20 bills
80 pounds nuts and 40 pounds raisins
9 pounds of Chicory coffee, 3 pounds of Jamaican Blue Mountain coffee
10 bags of M&M’s, 15 bags of Reese’s Pieces
7.5 7.5 liters of each solution
80 liters of the 25% solution and 40 liters of the 10% solution
240 liters of the 90% solution and 120 liters of the 75% solution
$1600 at 8%, 960 at 6%
$28,000 at 9%, $36,000 at 5.5 % 5.5 %
$8500 CD, $1500 savings account
$55,000 on loan at 6% and $30,000 on loan at 4.5 % 4.5 %
ⓐ C ( x ) = 5 x + 6500 C ( x ) = 5 x + 6500
ⓑ R ( x ) = 10 x R ( x ) = 10 x
ⓓ 1,500; when 1,500 water bottles are sold, the cost and the revenue equal $15,000
Section 4.4 Exercises
( 4 , 5 , 2 ) ( 4 , 5 , 2 )
( 7 , 12 , −2 ) ( 7 , 12 , −2 )
( −3 , −5 , 4 ) ( −3 , −5 , 4 )
( 2 , −3 , −2 ) ( 2 , −3 , −2 )
( 6 , −9 , −3 ) ( 6 , −9 , −3 )
( 3 , −4 , −2 ) ( 3 , −4 , −2 )
( −3 , 2 , 3 ) ( −3 , 2 , 3 )
( −2 , 0 , −3 ) ( −2 , 0 , −3 )
x = 203 16 ; y = –25 16 ; z = –231 16 ; x = 203 16 ; y = –25 16 ; z = –231 16 ;
( x , y , z ) ( x , y , z ) where x = 5 z + 2 ; y = −3 z + 1 ; z x = 5 z + 2 ; y = −3 z + 1 ; z is any real number
( x , y , z ) ( x , y , z ) where x = 5 z − 2 ; y = 4 z − 3 ; z x = 5 z − 2 ; y = 4 z − 3 ; z is any real number
$20, $5, $10
Section 4.5 Exercises
ⓐ [ 2 4 −5 3 −2 2 ] [ 2 4 −5 3 −2 2 ] ⓑ [ 3 −2 −1 −2 −2 1 0 5 5 4 1 −1 ] [ 3 −2 −1 −2 −2 1 0 5 5 4 1 −1 ]
ⓐ [ 2 −5 −3 4 −3 −1 ] [ 2 −5 −3 4 −3 −1 ] ⓑ [ 4 3 −2 −3 −2 1 −3 4 −1 −4 5 −2 ] [ 4 3 −2 −3 −2 1 −3 4 −1 −4 5 −2 ]
{ 2 x − 4 y = −2 3 x − 3 y = −1 { 2 x − 4 y = −2 3 x − 3 y = −1
{ 2 x − 2 y = −1 2 y − z = 2 3 x − z = −2 { 2 x − 2 y = −1 2 y − z = 2 3 x − z = −2
ⓐ [ 3 2 1 4 −6 −3 ] [ 3 2 1 4 −6 −3 ] ⓑ [ 12 8 4 4 −6 −3 ] [ 12 8 4 4 −6 −3 ] ⓒ [ 12 8 4 24 −10 −5 ] [ 12 8 4 24 −10 −5 ]
ⓐ [ 2 1 −4 5 6 −5 2 3 3 −3 1 −1 ] [ 2 1 −4 5 6 −5 2 3 3 −3 1 −1 ] ⓑ [ 2 1 −4 5 6 −5 2 3 3 −3 1 −1 ] [ 2 1 −4 5 6 −5 2 3 3 −3 1 −1 ] ⓒ [ 2 1 −4 5 6 −5 2 3 −4 7 −6 7 ] [ 2 1 −4 5 6 −5 2 3 −4 7 −6 7 ]
[ 1 −2 3 −4 0 5 −11 17 0 1 −10 7 ] [ 1 −2 3 −4 0 5 −11 17 0 1 −10 7 ]
( 1 , −1 ) ( 1 , −1 )
( −2 , 5 , 2 ) ( −2 , 5 , 2 )
infinitely many solutions ( x , y , z ) ( x , y , z ) where x = 1 2 z + 4 ; y = 1 2 z − 6 ; z x = 1 2 z + 4 ; y = 1 2 z − 6 ; z is any real number
infinitely many solutions ( x , y , z ) ( x , y , z ) where x = 5 z + 2 ; y = −3 z + 1 ; z x = 5 z + 2 ; y = −3 z + 1 ; z is any real number
Section 4.6 Exercises
ⓐ 6 ⓑ −14 −14 ⓒ −6 −6
ⓐ 9 ⓑ −3 −3 ⓒ 8
( 7 , 6 ) ( 7 , 6 )
( −9 , 3 ) ( −9 , 3 )
inconsistent
Section 4.7 Exercises
ⓐ false ⓑ true
ⓐ { f ≥ 0 p ≥ 0 f + p ≤ 20 2 f + 5 p ≤ 50 { f ≥ 0 p ≥ 0 f + p ≤ 20 2 f + 5 p ≤ 50 ⓑ
ⓐ { c ≥ 0 a ≥ 0 c + a ≤ 24 a ≥ 3 c { c ≥ 0 a ≥ 0 c + a ≤ 24 a ≥ 3 c ⓑ
ⓐ { w ≥ 0 b ≥ 0 27 w + 16 b > 80 3.20 w + 1.75 b ≤ 10 { w ≥ 0 b ≥ 0 27 w + 16 b > 80 3.20 w + 1.75 b ≤ 10 ⓑ
ⓐ { w ≥ 0 r ≥ 0 w + r ≥ 4 270 w + 650 r ≥ 1500 { w ≥ 0 r ≥ 0 w + r ≥ 4 270 w + 650 r ≥ 1500 ⓑ
Review Exercises
( 3 , −1 ) ( 3 , −1 )
one solution, consistent system, independent equations
( 3 , 1 ) ( 3 , 1 )
( 4 , −1 ) ( 4 , −1 )
elimination
50 irises and 150 tulips
10 calories jogging and 10 calories cycling
35 ° 35 ° and 55 ° 55 °
the length is 450 feet, the width is 264 feet
1 2 1 2 an hour
the rate of the jet is 395 mph, the rate of the wind is 7 mph
41 dimes and 11 pennies
46 2 3 46 2 3 liters of 30% solution, 23 1 3 23 1 3 liters of 60% solution
$29,000 for the federal loan, $14,000 for the private loan
( −3 , 2 , −4 ) ( −3 , 2 , −4 )
[ 4 3 0 −2 1 −2 −3 7 2 −1 2 −6 ] [ 4 3 0 −2 1 −2 −3 7 2 −1 2 −6 ]
{ x − 3 z = −1 x − 2 y = −27 − y + 2 z = 3 { x − 3 z = −1 x − 2 y = −27 − y + 2 z = 3
ⓐ [ 1 −3 −2 4 4 −2 −3 −1 2 2 −1 −3 ] [ 1 −3 −2 4 4 −2 −3 −1 2 2 −1 −3 ] ⓑ [ 2 −6 −4 8 4 −2 −3 −1 2 2 −1 −3 ] [ 2 −6 −4 8 4 −2 −3 −1 2 2 −1 −3 ] ⓒ [ 2 −6 −4 8 4 −2 −3 −1 0 −6 −1 5 ] [ 2 −6 −4 8 4 −2 −3 −1 0 −6 −1 5 ]
( −2 , 5 , −2 ) ( −2 , 5 , −2 )
ⓐ { b ≥ 0 n ≥ 0 b + n ≤ 40 12 b + 18 n ≥ 500 { b ≥ 0 n ≥ 0 b + n ≤ 40 12 b + 18 n ≥ 500 ⓑ
Practice Test
( 2 , 1 ) ( 2 , 1 )
( 2 , −2 , 1 ) ( 2 , −2 , 1 )
15 liters of 1% solution, 5 liters of 5% solution
The candy cost $20; the cookies cost $5; and the popcorn cost $10.
ⓐ { C ≥ 0 L ≥ 0 C + 0.5 L ≤ 50 L ≥ 3 C { C ≥ 0 L ≥ 0 C + 0.5 L ≤ 50 L ≥ 3 C ⓑ
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Lesson 3.1.1, lesson 3.1.2, lesson 3.1.3, lesson 3.1.4, lesson 3.2.1, lesson 3.2.2, lesson 3.2.3, lesson 3.2.4, lesson 3.2.5, lesson 3.2.6.
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Eureka Math Grade 3 Module 4 Lesson 10 Answer Key
Engage ny eureka math 3rd grade module 4 lesson 10 answer key, eureka math grade 3 module 4 lesson 10 problem set answer key.
Answer: The area of the larger rectangle = 56 sq unit. the area of the small rectangle A = 35 sq unit. the area of the small rectangle B = 21 sq unit.
Explanation: In the above-given question, given that, the area of the larger rectangle = 56 sq unit. area = length x breadth. area = l x b. area = 8 x 7. area = 56. the area of the rectangle A = 35 sq unit. area = length x breadth. area = l x b. area = 5 x 7. area = 35. the area of the rectangle B = 21 sq unit. area = length x breadth. area = l x b. area = 3 x 7. area = 21.
Answer: The area of the larger rectangle = 48 sq unit. the area of the small rectangle A = 40 sq unit. the area of the small rectangle B = 8 sq unit.
Explanation: In the above-given question, given that, the area of the larger rectangle = 48 sq unit. area = length x breadth. area = l x b. area = 12 x 4. area = 48. the area of the rectangle A = 40 sq unit. area = length x breadth. area = l x b. area = 10 x 4. area = 40. the area of the rectangle B = 8 sq unit. area = length x breadth. area = l x b. area = 2 x 4. area = 8.
Answer: The area of the larger rectangle = 78 sq unit. the area of the small rectangle A = 60 sq unit. the area of the small rectangle B = 18 sq unit.
Explanation: In the above-given question, given that, the area of the larger rectangle = 78 sq unit. area = length x breadth. area = l x b. area = 6 x 13. area = 78. the area of the rectangle A = 60 sq unit. area = length x breadth. area = l x b. area = 10 x 6. area = 60. the area of the rectangle B = 8 sq unit. area = length x breadth. area = l x b. area = 6 x 3. area = 18.
Answer: The area of the larger rectangle = 96 sq unit. the area of the small rectangle A = 80 sq unit. the area of the small rectangle B = 16 sq unit.
Explanation: In the above-given question, given that, the area of the larger rectangle = 96 sq unit. area = length x breadth. area = l x b. area = 8 x 12. area = 96. the area of the rectangle A = 80 sq unit. area = length x breadth. area = l x b. area = 10 x 8. area = 80. the area of the rectangle B = 16 sq unit. area = length x breadth. area = l x b. area = 8 x 2.
Answer: The area of the rectangle = 72 sq cm.
Explanation: In the above-given question, given that, the area of the rectangle = l x b. where l = length and b = breadth. area = 9 x 8. area = 72 sq cm. so the area of the rectangle = 72 sq cm.
Answer: The area of the rectangle = 40 sq cm.
Explanation: In the above-given question, given that, the area of the rectangle = l x b. where l = length and b = breadth. area = 5 x 8. area = 40 sq cm. so the area of the rectangle = 40 sq cm.
Answer: The area of the rectangle = 35 sq cm.
Eureka Math Grade 3 Module 4 Lesson 10 Exit Ticket Answer Key
Label the side lengths of the shaded and unshaded rectangles. Then, find the total area of the large rectangle by adding the areas of the 2 smaller rectangles.
Answer: The area of the larger rectangle = 56 sq unit. the area of the small rectangle A = 40 sq unit. the area of the small rectangle B = 16 sq unit.
Explanation: In the above-given question, given that, the area of the larger rectangle = 56 sq unit. area = length x breadth. area = l x b. area = 8 x 7. area = 56. the area of the rectangle A = 40 sq unit. area = length x breadth. area = l x b. area = 8 x 5. area = 40. the area of the rectangle B = 16 sq unit. area = length x breadth. area = l x b. area = 8 x 2. area = 16.
Answer: The area of the larger rectangle = 117 sq unit. the area of the small rectangle A = 90 sq unit. the area of the small rectangle B = 27 sq unit.
Explanation: In the above-given question, given that, the area of the larger rectangle = 117 sq unit. area = length x breadth. area = l x b. area = 9 x 13. area = 117. the area of the rectangle A = 90 sq unit. area = length x breadth. area = l x b. area = 9 x 10. area = 90. the area of the rectangle B = 27 sq unit. area = length x breadth. area = l x b. area = 9 x 3. area = 27.
Eureka Math Grade 3 Module 4 Lesson 10 Homework Answer Key
Answer: The area of the larger rectangle = 72 sq unit. the area of the small rectangle A = 40 sq unit. the area of the small rectangle B = 32 sq unit.
Explanation: In the above-given question, given that, the area of the larger rectangle = 78 sq unit. area = length x breadth. area = l x b. area = 9 x 8. area = 72. the area of the rectangle A = 40 sq unit. area = length x breadth. area = l x b. area = 5 x 8. area = 40. the area of the rectangle B = 32 sq unit. area = length x breadth. area = l x b. area = 4 x 8. area = 32.
Answer: The area of the larger rectangle = 60 sq unit. the area of the small rectangle A = 50 sq unit. the area of the small rectangle B = 10 sq unit.
Explanation: In the above-given question, given that, the area of the larger rectangle = 60 sq unit. area = length x breadth. area = l x b. area = 12 x 5. area = 60. the area of the rectangle A = 50 sq unit. area = length x breadth. area = l x b. area = 10 x 5. area = 50. the area of the rectangle B = 10 sq unit. area = length x breadth. area = l x b. area = 2 x 5. area = 10.
Answer: The area of the larger rectangle = 91 sq unit. the area of the small rectangle A = 70 sq unit. the area of the small rectangle B = 21 sq unit.
Explanation: In the above-given question, given that, the area of the larger rectangle = 91 sq unit. area = length x breadth. area = l x b. area = 7 x 13. area = 91. the area of the rectangle A = 70 sq unit. area = length x breadth. area = l x b. area = 7 x 10. area = 70. the area of the rectangle B = 21 sq unit. area = length x breadth. area = l x b. area = 7 x 3. area = 21.
Answer: The area of the larger rectangle = 108 sq unit. the area of the small rectangle A = 90 sq unit. the area of the small rectangle B = 18 sq unit.
Explanation: In the above-given question, given that, the area of the larger rectangle = 108 sq unit. area = length x breadth. area = l x b. area = 9 x 12. area = 108. the area of the rectangle A = 90 sq unit. area = length x breadth. area = l x b. area = 9 x 10. area = 90. the area of the rectangle B = 18 sq unit. area = length x breadth. area = l x b. area = 9 x 2. area = 18.
Answer: The area of the rectangle = 81 sq cm.
Explanation: In the above-given question, given that, the area of the rectangle = l x b. where l = length and b = breadth. area = 9 x 9. area = 81 sq cm. so the area of the rectangle = 81 sq cm.
Explanation: In the above-given question, given that, the area of the rectangle = l x b. where l = length and b = breadth. area = 10 x 4. area = 40 sq cm. so the area of the rectangle = 40 sq cm.
Answer: The area of the rectangle = 24 sq cm.
Eureka Math Grade 3 Module 4 Lesson 10 Template Answer Key
Explanation: In the above-given question, given that, the area of the rectangle = l x b. where l = length and b = breadth. area = 4 x 4. area = 16 sq cm. so the area of the rectangle = 16 sq cm.
Answer: The area of the rectangle = 8 sq cm.
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