assignment for class 6 maths chapter 3

NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers

NCERT Solutions for class 6 maths chapter 3 Playing With Numbers will help students study the topics, such as multiples, divisor, factors, and the identification of factors and multiples. In the previous two chapters, we studied whole numbers and natural numbers. With the help of this chapter, we will take a step ahead and learn the meaning of factors and multiples of a number. NCERT Solutions Class 6 maths chapter 3 consists of activities related to these concepts that make learning super easy.

With the help of the exercise questions, students will be able to find out the factors of a number using different methods. They will also be able to comprehend the application of these concepts in their day-to-day lives. Class 6 Maths NCERT Solutions Chapter 3 Playing with Numbers has a total of 7 exercises. With the help of this article, we will do an in-depth analysis of NCERT Solutions Class 6 Maths Chapter 3, and also you can find some of these in the exercises given below.

• NCERT Solutions Class 6 Maths Chapter 3 Ex 3.1
• NCERT Solutions Class 6 Maths Chapter 3 Ex 3.2
• NCERT Solutions Class 6 Maths Chapter 3 Ex 3.3
• NCERT Solutions Class 6 Maths Chapter 3 Ex 3.4
• NCERT Solutions Class 6 Maths Chapter 3 Ex 3.5
• NCERT Solutions Class 6 Maths Chapter 3 Ex 3.6
• NCERT Solutions Class 6 Maths Chapter 3 Ex 3.7

NCERT Solutions for Class 6 Maths Chapter 3 PDF

One of the key concepts covered in the NCERT solutions class 6 maths is finding the factors of a number in a stepwise manner. The only way students can get a good grasp of the concepts is by solving all the questions given in this coursebook. The NCERT Solutions for Class 6 Maths Chapter 3 are free to download using the links given below:

☛ Download Class 6 Maths NCERT Solutions Chapter 3 Playing with Numbers

NCERT Class 6 Maths Chapter 3   Download PDF

The best way to get strong fundamentals in maths is by practicing many questions on a regular basis. Thus, students need to visit the above links from time to time and revise all the questions. Numbers are everywhere, be it time, date, year, and weather; we use numerals to count things. We utilize numbers for counting money, measurements , phone numbers, phone passwords, locks, reading, page numbers, and TV channels. Engineers utilize numbers in their calculations when creating structures and roadways. They are also used by doctors to check blood counts and administer medications. With such wide applications of numbers , it is important for us to study the numbers in detail. An elaborate analysis of NCERT Solutions Class 6 Maths Chapter 3 is given below :

• Class 6 Maths Chapter 3 Ex 3.1 - 4 Questions
• Class 6 Maths Chapter 3 Ex 3.2 - 9 Questions
• Class 6 Maths Chapter 3 Ex 3.3 - 6 Questions
• Class 6 Maths Chapter 3 Ex 3.4 - 7 Questions
• Class 6 Maths Chapter 3 Ex 3.5 - 12 Questions
• Class 6 Maths Chapter 3 Ex 3.6 - 3 Questions
• Class 6 Maths Chapter 3 Ex 3.7 - 11 Questions

☛ Download Class 6 Maths Chapter 3 NCERT Book

Topics Covered: The topics covered under class 6 maths NCERT solutions chapter 3 are multiples , divisors , factors , identification of multiples, and factors. We will also learn how to determine if a number is prime or composite using the factors. Apart from that, we will explore how to find the HCF and LCM using the factors method.

Total Questions: Class 6 maths chapter 3 Playing with Numbers has 52 questions in total out of which 30 can be classified as easy short answer sums, 15 are long answer type problems while the other 7 are complex problems.

List of Formulas in NCERT Solutions Class 6 Maths Chapter 3

NCERT solutions class 6 maths chapter 3 does not consist of any formulas however there are some important concepts discussed in the chapter related to finding the HCF, LCM, and factors of numbers. We will discuss these essential concepts in this section.

• A prime number is any number other than 1 that has only two factors: 1 and the number itself. Composite numbers are those that have more than two factors. Number one is neither composite nor prime.
• If two numbers are divisible by a number, their sum and difference are likewise divisible by the same number.
• The Highest Common Factor (HCF) of two or more numbers is the highest common factor among them.
• The Least Common Multiple (LCM) of two or more numbers is the smallest of their common multiples.

Important Questions for Class 6 Maths NCERT Solutions Chapter 3

Faqs on ncert solutions for class 6 maths chapter 3, why are ncert solutions class 6 maths chapter 3 important.

NCERT solutions class 6 Maths Chapter 3 are designed by subject experts from IIT and Cambridge university. This chapter will help you understand the prime role that different numbers and their multiples play in solving an equation. These solutions also include various questions based on the laws of divisibility which are explained in detail. The NCERT solutions class 6 maths chapter 3 are the perfect study material for class 6 students as it will help them review their answers and also provide a step-wise approach to solve all questions.

Do I Need to Practice all Questions Provided in Class 6 Maths NCERT Solutions Playing with Numbers?

It is crucial for the students to practice all the questions in NCERT Solutions Class 6 Maths Playing With Numbers. This will help them understand the concepts better and build confidence, thus enabling them to memorize formulas faster. The main highlight of this chapter is HCF and LCM, and it is essential to practice all of the questions related to these topics. All the problems cover a variety of subject matter, thus allowing students to get a better grasp of numbers.

What are the Important Topics Covered in NCERT Solutions Class 6 Maths Chapter 3?

All the topics covered in NCERT Solutions Class 6 Maths Chapter 3 are equally important. However, to streamline the studying process, students need to give ample time in preparing questions based on HCF, LCM, and factors. Additionally, they must also go through the entire theory of the chapter to understand the concepts better.

How Many Questions are there in Class 6 Maths NCERT Solutions Chapter 3 Playing With Numbers?

There are 52 questions in the NCERT Solutions Class 6 Maths Chapter 3 Playing With Numbers. These are divided into seven different exercises. Exercise 3.6 and 3.7 are the most important exercises from an examination perspective, covering important topics like the prime factors, HCF, and LCM of numbers. Since these concepts are new to students, they should engage in activities to understand these concepts in a more practical way.

What are the Important Formulas in NCERT Solutions Class 6 Maths Chapter 3?

Students will come across many important concepts in the NCERT Solutions Class 6 maths chapter 3. We do not have any important formulas in this chapter; however certain facts like every number is a factor and multiple will help them understand the prime role that different numbers and their multiples play in solving an equation. Students must go through all the questions and solve the examples in order to develop a rock-solid foundation.

How CBSE Students can utilize NCERT Solutions Class 6 Maths Chapter 3 effectively?

To effectively utilize the NCERT Solutions Class 6 Maths Chapter 3, kids must first go through the theoretical concepts and activities discussed in the chapter. Topics such as common factors and multiples, divisibility laws, greatest common factors, lowest common factors, etc., are introduced to the kids. Students will be able to understand prime and composite numbers, as well as their differences, provided they have a thorough understanding of the chapter. This will help students identify practical ways of solving a problem.

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.2

NCERT Solutions for Class 6 Maths Chapter 3 Exercise 3.2 in Hindi and English Medium updated and revised for academic session 2024-25. The questions of 6th Maths ex. 3.2 are revised on the basis of new syllabus and latest textbooks for curriculum 2024-25.

6th Maths Exercise 3.2 Solution in Hindi and English Medium

• Class 6 Maths Exercise 3.2 in English
• Class 6 Maths Exercise 3.2 in Hindi
• Class 6 Maths Chapter 3 in PDF
• Class 6 Maths Chapter 3 Solutions
• Class 6 Maths NCERT Solutions
• Class 6 All Subjects NCERT Solutions

Class VI Mathematics NCERT Book Ex. 3.2 of chapter 3 Playing with Numbers free to use online or download in PDF format based on CBSE and State board. All the solution of Grade 6 NCERT is updated for academic session 2024-25 free to use online or download to use offline. All the questions are solved in simplest way so that students can understand easily.

Property 1: If a number is divisible by another number, it must be divisible by each of the factors of that number. Example: We know that 48 is divisible by 12. All the factors of 12 are 1, 2, 3, 4, 6 and 12. Clearly, 48 is divisible by each one of 1, 2, 3, 4, 6 and 12.

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Property 2: If a number is divisible by each of the two co-prime numbers, it must be divisible by their product. Example: We know that 672 is divisible by each of the numbers 2 and 3. Also, 2 and 3 are co-primes. Therefore, 672 must be divisible by 6.

Property 3: If a number is a factor of each of the two given numbers, then it must be a factor of their sum. Example: We know that 8 is a factor of 48 as well as that of 64. So, 8 must be a factor of (48 + 64) = 112. Clearly, 8 divides 112 exactly.

Property 4: If a number is a factor of each of the two given numbers, then it must be a factor of their difference. Example: We know that 3 is a factor of each one of the numbers 15 and 27. So, 3 must be a factor of (27 – 15) = 12. Clearly, 12 = 4 × 3, i.e., 3 is a factor of 12.

Important Questions for Class 6 Maths Exercise 3.2

Examine whether the following are prime numbers or not (i) 127 (ii) 133.

(i) Test the divisibility of 127 by each one of the prime numbers 2, 3, 5, 7, 11 and 13. We find that 127 is divisible by none of them. So, 127 is a prime number. (ii) Test the divisibility of 133 by each one of the prime numbers 2, 3, 5, 7, 11 and 13. We find that 133 is divisible by 7. So, 133 is not prime number.

Which of the following is a prime number? (i) 331 (ii) 323

(i) Test the divisibility of 331 by each one of the prime numbers 2, 3, 5, 7, 11,13, 17 and 19. We find that 331 is not divisible by any one of these numbers. So, 331 is a prime number. (ii) Test the divisibility of 323 by each one of the prime numbers 2, 3, 5, 7, 11,13, 17 and 19. Clearly, 323 is divisible by 17. So, it is not a prime number.

Test the divisibility of the following numbers by 2: (i) 854, (ii) 2265, (iii) 4735

(i) 854 is even number and divisible by 2. As we apply last two-digit method here last two digits are 54 And 54 is divisible by 2. (ii) 2265 is an odd number which is not divisible completely by 2. As we apply last two-digit method here last two digits are 65. 65 is not divisible by 2. (iii) 4735 is also an odd number which is not divisible completely by 2. Here last two digits are 35 which is not divisible by 2.

Test the divisibility of the following numbers by 4: (i) 486528 (ii) 3020525

(i) Here we apply same last two-digit rule. Here 28 are last two digits which is divisible by 4. Hence 486528 is divisible by 4. (ii) here last two digits are 25 which not divisible by 4.so number 3020525 is not divisible by 4.

Rule: Examine whether the given number is divisible by any prime number less than 15, i.e., 2, 3, 5, 7, 11 and 13. If it is divisible, then it is not prime, otherwise, it is prime.

Class 6 Maths Exercise 3.2 Extra Questions with Answres

How can we find prime numbers between 100 and 200.

To Find Prime Numbers Between 100 And 200 Examine whether the given number is divisible by any prime number less than 15, i.e., 2, 3, 5, 7, 11 and 13. If it is divisible, then it is not prime, otherwise, it is prime. Example: Test the divisibility of 127 by each one of the prime numbers 2, 3, 5, 7, 11 and 13. We find that 127 is divisible by none of them. So, 127 is a prime number.

In each of the following numbers, replace (*) by the smallest number to make it divisible by 3 (i) 6*1045, (ii) 53*46

(i) 6*1045, here 6 + * + 1 + 0 + 4 + 5 = 16 + *, after 16 the number divisible by 3 is 18. Hence * should be replaced by 2. Number is 621045. (ii) 53*46, here 5 + 3 + * + 4 + 6 = 18 + *, we know 18 is divisible by 3 so we replace * by 0 and number will be 53046.

In 9*8071, replace (*) by the smallest number to make it divisible by 11.

We write Number 9*8071 as 9 + * + 8 + 0 + 7 + 1 = 25 + *, we know that after 25 it is 33 which is divisible by 11. Hence 25 + 8 = 33. In number 9*8071, * should be replaced by 8.

Which of the following are prime numbers? 277, 143, 167, 263, 179, 357, 217, 291, 397, 203.

By applying divisible method, we divide numbers by 2, 3, 5, 7, 11 either we get whole number or not. 277, 167, 263, 179, 397 these are prime numbers.

Rule: Examine whether the given number is divisible by any prime number less than 20, i.e., 2, 3, 5, 7, 11,13, 17 and 19. If it is divisible, then it is not prime, otherwise, it is prime.

Can short answer-type questions come from exercise 3.2 of 6th Maths?

Yes, short answer type questions like fill in the blanks, MCQ, true or false, yes or no, answer in one word, etc can come from exercise 3.2 of class 6th Maths.

How much time is required to complete exercise 3.2 of class 6th Maths?

Students require at most 3 days to complete exercise 3.2 of class 6th Maths if they give 1 hour per day to this exercise. This time depends on teachers and students also because no teacher and students can have the same working speed.

Which questions of exercise 3.2 of class 6th Maths are the expected for the exams?

Exercise 3.2 of grade 6th Maths is important from the exam point of view. Every year questions come from this exercise in the exams. There are 12 questions and one example (example 4) in exercise 3.2. All the questions of this exercise are good, logical, and can come in the exams. The most important questions of this exercise that teachers can give in the exams are questions 2, 8, 10, and 12.

Is exercise 3.2 (chapter 3) of class 6th Maths easy or tough to solve?

Exercise 3.2 (chapter 3) of class 6th Maths is not easy and not tough. It lies in the mid of easy and tough because some questions of this exercise are easy, and some are complicated. However, the difficulty level of any question varies from child to child. So, exercise 3.2 (chapter 3) of class 6th Maths is easy, or tough depends on children also. Some children find it complex, some find it simple, and some find it in the middle of easy and hard.

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Class 6 Mathematics Assignments

We have provided below free printable Class 6 Mathematics Assignments for Download in PDF. The Assignments have been designed based on the latest NCERT Book for Class 6 Mathematics . These Assignments for Grade 6 Mathematics cover all important topics which can come in your standard 6 tests and examinations. Free printable Assignments for CBSE Class 6 Mathematics , school and class assignments, and practice test papers have been designed by our highly experienced class 6 faculty. You can free download CBSE NCERT printable Assignments for Mathematics Class 6 with solutions and answers. All Assignments and test sheets have been prepared by expert teachers as per the latest Syllabus in Mathematics Class 6. Students can click on the links below and download all Pdf Assignments for Mathematics class 6 for free. All latest Kendriya Vidyalaya Class 6 Mathematics Assignments with Answers and test papers are given below.

Mathematics Class 6 Assignments Pdf Download

We have provided below the biggest collection of free CBSE NCERT KVS Assignments for Class 6 Mathematics . Students and teachers can download and save all free Mathematics assignments in Pdf for grade 6th. Our expert faculty have covered Class 6 important questions and answers for Mathematics as per the latest syllabus for the current academic year. All test papers and question banks for Class 6 Mathematics and CBSE Assignments for Mathematics Class 6 will be really helpful for standard 6th students to prepare for the class tests and school examinations. Class 6th students can easily free download in Pdf all printable practice worksheets given below.

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• RS Aggarwal Class 6 Solutions Chapter-3 Whole Numbers
• RS Aggarwal Solutions

Class 6 RS Aggarwal Chapter-3 Whole Numbers Solutions - Free PDF Download

Types of numbers, factors and their properties, multiples, prime and composite numbers, divisibility test of numbers, common multiples, common factors, prime factorization, highest common factor, lowest common multiple, and some practice problems based on LCM and HCF are among the seven exercises in this chapter.

For practice, there are revision questions for all of the areas stated above. To make it easier for students to identify the subjects, these problems have been grouped into seven tasks ranging from 3.1 to 3.7.

Students benefit greatly from studying from RS Aggarwal books for Maths exams because the books cover all of the important topics in each chapter. For the convenience of students, Vedantu has compiled the RS Aggarwal Class 6 Chapter 3 Solutions in PDF format. Vedantu's official website provides you with the RS Aggarwal Chapter 3 PDF for Class 6 Maths that you can download to your devices anytime, anywhere. You can print it out to do a group study with your classmates or to revise the complete syllabus in another way.

Class 6 Chapter-3 RS Aggarwal Solution - Whole Numbers

Predecessor and successor.

Any natural number becomes its successor when you add 1. For example, the number 18 is the successor of 17 since 17 + 1 Equals 18. Similarly, 18 is succeeded by 19, and so on. In these cases, 17 would be the forerunner of 18, while 18 would be the precursor of 19. Predecessors are the numbers obtained by deducting one from the supplied number. As a result, 18 -1 equals 17, 19 -1 equals 18, and so on.

Natural numbers are used in many situations in real life, such as counting the number of people in a country, the number of children in your school, and so on. You now know from the preceding instances that there is no such thing as the greatest number.

Whole Numbers

Since natural numbers begin with 1, the number 1 has no precursor that falls inside the natural numbers range. To find the antecedent of number 1, we must add 0 to the collection of natural numbers.

Natural numbers are subsets of whole numbers, hence all natural numbers are whole numbers, but not all whole numbers are natural numbers.

The Number Line

To make a number line, start by drawing a straight horizontal line and marking a point with the number 0 on it (zero). Make a new point that is directly related to the original one and label it 1. The unit distance is the distance between points 0 and 1. Make a second mark at point 2, which is a unit distance and to the right of point 1. You can continue marking 3, 4, 5, 6, 7,.... on this line in this manner. As long as you stay on this line, you can go to any whole number. The number line for entire numbers is represented by this line.

Addition on a Number Line

On a number line, we make as many hops to the right as the number we want to add. Let's have a look at an example. To add 3 and 4, we start with 3 and make 4 hops to the right, resulting in number 7. As a result, the total of 3 and 4 equals 7.

Subtraction on a Number Line

To subtract numbers from a number line, we make the same number of hops to the left as the number to be subtracted. To subtract 5 from 7, we start with 7 and then move 5 units to the left, resulting in number 2. As a result, we obtain 7 - 5 = 2.

FAQs on RS Aggarwal Class 6 Solutions Chapter-3 Whole Numbers

1. What are some of the properties of Whole Numbers?

Listed below are the important properties of Whole Numbers:

Closure property - This property says that the result is always a whole number when you add or multiply two whole numbers. In other words, the system of whole numbers is closed under addition and multiplication

Addition and Multiplication of Whole Numbers are Commutative - If a and b are two whole numbers then: 

a + b = b + a

a * b = b * a

Addition and Multiplication of Whole Numbers are Associative - If a, b and c are three whole numbers then: 

(a + b) + c = a + (b + c)

(a * b) * c = a * (b * c)

Distributivity of multiplication over addition - If a, b and c are three whole numbers then: 

a * (b + c) = (a * b) + (a * c)

2. How are whole numbers different from natural numbers?

The number 0 differentiates a collection of whole numbers from a collection of natural numbers. So 

Whole numbers - 0, 1, 2, 3, 4, ….

Natural numbers - 1, 2, 3, 4, ….

3. What is called the additive identity for whole numbers?

The number 0 (zero) is called the additive identity or identity for addition of whole numbers. This is because by adding 0 to any whole number we get the same number i.e. 3 + 0 = 3, 5 + 0 = 5, etc.

4. What are the RS Aggarwal Class 6 Maths Chapter 3 Preparation Tips?

To get the basics down, go over the RS Aggarwal Solutions Class 6 Maths Chapter and solve predecessor and successor sums. Because the number line is such an essential concept in whole numbers, try to practice more sums that are dependent on number line operations, especially multiplication and division, which can be challenging. Keep a sheet of paper with significant features of whole numbers nearby so you may readily review and memorize them. These characteristics are critical for solving a variety of challenges.

5. What is the meaning of the number 0? 

Everything begins at zero and ends at zero. You may not know the end, but you do know the beginning, which is zero. Zero is a non-negative integer that can be categorized as a whole number, a real number, or a fraction. It is neither an undercounting number, nor an odd, positive natural, or negative whole number, nor a complex number. It's difficult to divide zero into multiple groups. It may, however, be used in a variety of complex-number equations. To do well in these topics and other areas in this chapter, practice all of the problems relevant to them.

6. Is it possible to classify zero as a natural number?

In RS Aggarwal Class 6 Solutions Chapter-3 Whole Numbers Zero is a non-negative integer that is both a whole number and a real number. It is neither a complex number, nor is it a counting, odd, positive natural, or negative whole number. In many respects, categorizing zero is challenging. It may, however, be employed in a variety of complex-valued equations. You may acquire several modules and example papers relevant to these subjects from the Vedantu website as well as the Vedantu mobile app.

7. What do you mean by whole numbers?

A collection of numbers that includes all positive integers and 0 is known as a whole number. Whole numbers are fractions, decimals, and negative values that are not included in real numbers. Whole numbers include counting numerals as well. You will learn whole numbers and associated topics in this session. The number system in mathematics is made up of numerous sorts of numbers, such as natural numbers and whole numbers, prime numbers and composite numbers, integers, real numbers, and imaginary numbers, and so on, all of which are used to accomplish various computations.

8. Why is solving RS Aggarwal important?

NCERT (CBSE) Maths Exercise Book Solutions by RS Aggarwal Maths necessitates complete attention and concentration. To achieve success in a variety of professions Math is an essential topic, and students need strong information to do well in it. RS Aggarwal's math answer in pdf is a useful tool for students. Math takes a great deal of practice in order to understand the ideas. RS Aggarwal's math textbooks are excellent for this type of practice. It is critical to finish your curriculum while studying for the majority of tests. Another crucial aspect is making the most use of your time. Exam preparation should begin early in order to ensure that you have many opportunities to review your material.

NCERT Solutions

• NCERT Class 6
• NCERT 6 Maths
• Chapter 3: Playing With Numbers
• Exercise 3.2

NCERT Solutions for Class 6 Maths Chapter 3 Playing With Numbers Exercise 3.2

The NCERT Solutions For Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.2 is the continuation of the 1st exercise of the chapter.  In the previous exercise, we have learnt about the factors and multiples. Now, in this exercise of  NCERT Class 6 Maths Chapter 3, we get a brief idea about the prime and composite numbers. We, at BYJU’S, have provided NCERT Solutions for the students to aid them in understanding the steps involved in solving the problems. The numbers which have factors as 1 and the number itself are prime numbers and those having many factors are composite numbers. Learn more about prime and composite numbers by practising the  NCERT Solutions of Class 6 Maths  that is being provided here for the second exercise of Chapter 3 Playing with Numbers.

• Chapter 1 Knowing our Numbers
• Chapter 2 Whole Numbers
• Chapter 3 Playing With Numbers
• Chapter 4 Basic Geometrical Ideas
• Chapter 5 Understanding Elementary Shapes
• Chapter 6 Integers
• Chapter 7 Fractions
• Chapter 8 Decimals
• Chapter 9 Data Handling
• Chapter 10 Mensuration
• Chapter 11 Algebra
• Chapter 12 Ratio And Proportion
• Chapter 13 Introduction To Symmetry
• Chapter 14 Practical Geometry
• Exercise 3.1 Chapter 3 Playing With Numbers
• Exercise 3.2 Chapter 3 Playing With Numbers
• Exercise 3.3 Chapter 3 Playing With Numbers
• Exercise 3.4 Chapter 3 Playing With Numbers
• Exercise 3.5 Chapter 3 Playing With Numbers
• Exercise 3.6 Chapter 3 Playing With Numbers
• Exercise 3.7 Chapter 3 Playing With Numbers

NCERT Solutions for Class 6 Maths Chapter 3 Playing with Numbers Exercise 3.2

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Access NCERT Solutions for Class 6 Chapter 3: Playing with Numbers Exercise 3.2

1. What is the sum of any two (a) Odd numbers? (b) Even numbers?

(a) The sum of any two odd numbers is an even number.

Examples: 5 + 3 = 8

15 + 13 = 28

(b) The sum of any two even numbers is an even number.

Examples: 2 + 8 = 10

12 + 28 = 40

2. State whether the following statements are True or False:

(a) The sum of three odd numbers is even.

(b) The sum of two odd numbers and one even number is even.

(c) The product of three odd numbers is odd.

(d) If an even number is divided by 2, the quotient is always odd.

(e) All prime numbers are odd.

(f) Prime numbers do not have any factors.

(g) Sum of two prime numbers is always even.

(h) 2 is the only even prime number.

(i) All even numbers are composite numbers.

(j) The product of two even numbers is always even.

(a) False. The sum of three odd numbers is odd.

Example: 7 + 9 + 5 = 21 i.e., odd number

(b) True. The sum of two odd numbers and one even number is even.

Example: 3 + 5 + 8 = 16 i.e is even number.

(c) True. The product of three odd numbers is odd.

Example: 3 × 7 × 9 = 189 i.e., is an odd number.

(d) False. If an even number is divided by 2, the quotient is even.

Example: 8 ÷ 2 = 4

(e) False, All prime numbers are not odd.

Example: 2 is a prime number but it is also an even number.

(f) False. Since, 1 and the number itself are factors of the number

(g) False. Sum of two prime numbers may also be an odd number

Example: 2 + 5 = 7 i.e., odd number.

(h) True. 2 is the only even prime number.

(i) False. Since, 2 is a prime number.

(j) True. The product of two even numbers is always even.

Example: 2 × 4 = 8 i.e., even number.

3. The numbers 13 and 31 are prime numbers. Both these numbers have same digits 1 and 3. Find such pairs of prime numbers upto 100.

The prime numbers with same digits upto 100 are as follows:

4. Write down separately the prime and composite numbers less than 20.

2, 3, 5, 7, 11, 13, 17 and 19 are the prime numbers less than 20

4, 6, 8, 9, 10, 12, 14, 15, 16 and 18 are the composite numbers less than 20

5. What is the greatest prime number between 1 and 10?

2, 3, 5 and 7 are the prime numbers between 1 and 10. 7 is the greatest prime number among them.

6. Express the following as the sum of two odd primes.

(a) 3 + 41 = 44

(b) 5 + 31 = 36

(c) 5 + 19 = 24

(d) 5 + 13 = 18

7. Give three pairs of prime numbers whose difference is 2. [Remark: Two prime numbers whose difference is 2 are called twin primes].

The three pairs of prime numbers whose difference is 2 are

8. Which of the following numbers are prime?

1 × 23 = 23

23 × 1 = 23

Therefore, 23 has only two factors 1 and 23. Hence, it is a prime number.

1 × 51 = 51

3 × 17 = 51

Therefore, 51 has four factors 1, 3, 17 and 51. Hence, it is not a prime number, it is a composite number.

1 × 37 = 37

37 × 1 = 37

Therefore, 37 has two factors 1 and 37. Hence, it is a prime number.

1 × 26 = 26

2 × 13 = 26

Therefore, 26 has four factors 1, 2, 13 and 26. Hence, it is not a prime number, it is a composite number.

9. Write seven consecutive composite numbers less than 100 so that there is no prime number between them.

Seven composite numbers between 89 and 97 both which are prime numbers are 90, 91, 92, 93, 94, 95 and 96

Numbers                                                                                                  Factors

90                                                                                       1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

91                                                                                        1, 7, 13, 91

92                                                                                       1, 2, 4, 23, 46, 92

93                                                                                       1, 3, 31, 93

94                                                                                       1, 2, 47, 94

95                                                                                       1, 5, 19, 95

96                                                                                       1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 96

10. Express each of the following numbers as the sum of three odd primes:

(a) 3 + 5 + 13 = 21

(b) 3 + 5 + 23 = 31

(c) 13 + 17 + 23= 53

(d) 7 + 13 + 41 = 61

11. Write five pairs of prime numbers less than 20 whose sum is divisible by 5. (Hint: 3 + 7 = 10)

The five pairs of prime numbers less than 20 whose sum is divisible by 5 are

2 + 13 = 15

3 + 17 = 20

7 + 13 = 20

19 + 11 = 30

12. Fill in the blanks:

(a) A number which has only two factors is called a ______.

(b) A number which has more than two factors is called a ______.

(c) 1 is neither ______ nor ______.

(d) The smallest prime number is ______.

(e) The smallest composite number is _____.

(f) The smallest even number is ______.

(a) A number which has only two factors is called a prime number.

(b) A number which has more than two factors is called a composite number.

(c) 1 is neither a prime number nor a composite number.

(d) The smallest prime number is 2

(e) The smallest composite number is 4

(f) The smallest even number is 2.

Also, explore – 

NCERT Solutions for Class 6 Maths Chapter 3

NCERT Solutions for Class 6

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DAV Class 6 Maths Book Solutions Pdf – DAV Class 6 Maths Solutions

DAV Class 6 Maths Book Solutions Pdf: Students who are studying class 6 in Dayanand Angola Vedic DAV public school can explore trusted and reliable DAV Class 6 Maths Solutions in PDF format.

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DAV Public School Class 6 Maths Book Solutions – DAV Maths Book Class 6 Solutions

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Secondary Mathematics Class 6th DAV Solutions Pdf

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DAV Class 6 Maths Book Pdf Chapter 1 Natural Numbers and Whole Numbers

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DAV Class 6 Maths Book Solutions Pdf Chapter 2 Factors and Multiples

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Secondary Mathematics Class 6th DAV Solutions Pdf Chapter 3 Integers

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DAV Class 6 Maths Solution Chapter 4 Ratio, Proportion and Unitary Method

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DAV Class 6 Maths Solutions Chapter 5 Percentage and its Applications

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DAV Maths Book Class 6 Pdf Chapter 6 Introduction to Algebra

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DAV Maths Book Class 6 Solutions Chapter 7 Linear Equations

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DAV Class 6 Maths Full Book Pdf Chapter 9 Line Segments

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DAV Class 6 Maths Book Solutions Chapter 10 Angles

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Class 6 DAV Maths Book Chapter 11 Transversal and Pairs of Lines

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Class 6 DAV Maths Book Solution Chapter 12 Triangles

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DAV Books Solutions Class 6 Maths Chapter 13 Circles

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DAV Maths Solution Class 6 Chapter 14 Constructions

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DAV School Class 6 Maths Solutions Chapter 15 Perimeter and Area

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DAV Public School Class 6 Maths Book Pdf Chapter 16 Statistics

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